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Basic Geometry : Squares

Study concepts, example questions & explanations for Basic Geometry

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Example Questions

Example Question #1 : How To Find The Length Of The Side Of A Square

A square has one side of length , what is the length of the opposite side?

Possible Answers:

Correct answer:

Explanation:

One of the necessary conditions of a square is that all sides be of equal length. Therefore, because we are given the length of one side we know the length of all sides and that includes the length of the opposite side. Since the length of one of the sides is 4 we can conclude that all of the sides are 4, meaning the opposite side has a length of 4.

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Example Question #1 : How To Find The Length Of The Side Of A Square

The perimeter of a square is half its area. What is the length of one side of the square?

Possible Answers:

$4\sqrt{2}$

Correct answer:

Explanation:

We begin by recalling the formulas for the perimeter and area of a square respectively.

P=4s

A=s^2

Using these formulas and the fact that the perimeter is half the area, we can create an equation.

$4s=\frac{1}{2}(s^2)$

We can multiply both sides by 2 to eliminate the fraction.

8s=s^2

To get one side of the equation equal to zero, we will move everything to the right side.

0=s^2-8s

Next we can factor.

0=s(s-8)

Setting each factor equal to zero provides two potential solutions.

s=0 or s-8=0

s=8

However, since a square cannot have a side of length 0, 8 is our only answer.

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Example Question #1 : How To Find The Length Of The Side Of A Square

If the area of the square is 100 square units, what is, in units, the length of one side of the square?

Possible Answers:

Correct answer:

Explanation:

$Area = Length \times Length$

100 = (Length)^2

$Length = \sqrt{100}=10$

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Example Question #1 : How To Find The Length Of The Side Of A Square

In Square SQUA , $SU = \sqrt{2x}$ . Evaluate in terms of .

Possible Answers:

$\sqrt{x}$

$x\sqrt{2}$

$2\sqrt{x}$

Correct answer:

$\sqrt{x}$

Explanation:

If diagonal $\overline{SU}$ of Square SQUA is constructed, then $\bigtriangleup SQU$ is a 45-45-90 triangle with hypotenuse $SU = \sqrt{2x}$ . By the 45-45-90 Theorem, the sidelength can be calculated as follows:

$SQ = \frac{SU}{\sqrt{2}} = \frac{\sqrt{2x}}{\sqrt{2}} = \sqrt{\frac{2x}{2}} = \sqrt{x}$ .

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Example Question #1 : How To Find The Length Of The Side Of A Square

The circle that circumscribes Square SQUA has circumference 20. To the nearest tenth, evaluate .

Possible Answers:

9.0

3.2

4.5

2.3

6.4

Correct answer:

4.5

Explanation:

The diameter of a circle with circumference 20 is

$\frac{20}{\pi } \approx \frac{20 }{3.1416} \approx 6.3662$

The diameter of a circle that circumscribes a square is equal to the length of the diagonals of the square.

If diagonal $\overline{SU}$ of Square SQUA is constructed, then $\bigtriangleup SQU$ is a 45-45-90 triangle with hypotenuse approximately 6.3662. By the 45-45-90 Theorem, divide this by $\sqrt{2} \approx 1.4142$ to get the sidelength of the square:

$6.3662 \div 1.4142 \approx 4.5$

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Example Question #1 : How To Find The Length Of The Side Of A Square

Rectangle RECT has area 90% of that of Square SQUA , and is 80% of . What percent of is ?

Possible Answers:

$79\frac{1}{81} \%$

$126 \frac{9}{16} \%$

$88 \frac{8} {9} \%$

$70 \%$

$112\frac{1}{2} \%$

Correct answer:

$88 \frac{8} {9} \%$

Explanation:

The area of Square SQUA is the square of sidelength , or $(SQ)^{2}$ .

The area of Rectangle RECT is $RE \cdot EC$ . Rectangle RECT has area 90% of that of Square SQUA , which is $\frac{9}{10} (SQ)^{2}$ ; is 80% of , so $RE = \frac{4}{5}SQ$ . We can set up the following equation:

$\frac{9}{10} (SQ)^{2} = RE \cdot EC$

$\frac{9}{10} (SQ)^{2} = \frac{4}{5} SQ \cdot EC$

$\frac{9}{10} \cdot SQ = \frac{4}{5} \cdot EC$

$\frac{10} {9} \cdot \frac{9}{10} \cdot SQ = \frac{10} {9} \cdot \frac{4}{5} \cdot EC$

$SQ = \frac{8} {9} \cdot EC$

As a percent, $\frac{8} {9}$ of is $\frac{8} {9} \times 100 \%= 88 \frac{8} {9} \%$

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Example Question #411 : Geometry

Reducing the area of a square by 12% has the effect of reducing its sidelength by what percent (hearest whole percent)?

Possible Answers:

$15 \%$

$3 \%$

$6 \%$

$9 \%$

$12 \%$

Correct answer:

$6 \%$

Explanation:

The area of the square was originally

$A = s^{2}$ ,

being the sidelength.

Reducing the area by 12% means that the new area is 88% of the original area, or 0.88A ; the square root of this is the new sidelength, so

$0.88A = 0.88s^{2}$

$\sqrt{0.88A} = \sqrt{0.88s^{2}} = \sqrt{0.88} \cdot \sqrt{s^{2}} \approx 0.94 s$

Each side of the new square will measure 94% of the length of the old measure - a reduction by 6%.

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Example Question #1 : How To Find The Length Of The Side Of A Square

The circle inscribed inside Square SQUA has circumference 16. To the nearest tenth, evaluate .

Possible Answers:

7.2

5.1

3.6

10.2

2.5

Correct answer:

5.1

Explanation:

The diameter of a circle that is inscribed inside a square is equal to its sidelength , so all we need to do is find the diameter of the circle - which is circumference 16 divided by $\pi$ :

$\frac{16}{\pi } \approx \frac{16}{3.1416 } \approx 5.1$ .

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Example Question #412 : Geometry

Thingy

Refer to the above figure, which shows equilateral triangle $\bigtriangleup CDE$ inside Square ABCD . Also, $\overline{EF} \perp \overline{AB}$ .

Quadrilateral BCEF has area 100. Which of these choices comes closest to ?

Possible Answers:

Correct answer:

Explanation:

Let s = CD , the sidelength shared by the square and the equilateral triangle.

The area of $\bigtriangleup CDE$ is

$\frac{s^{2}\sqrt{3}}{4} = \frac{\sqrt{3}}{4} \cdot s^{2} \approx \frac{1.7321}{4} \cdot s^{2} \approx 0.4330 s^{2}$

The area of Square ABCD is $s^{2}$ .

By symmetry, $\overline{EF}$ bisects the portion of the square not in the triangle, so the area of Quadrilateral BCEF is half the difference of those of the square and the triangle. Since the area of Quadrilateral BCEF is 100, we can set up an equation:

$\frac{1}{2}\left (s ^{2} - 0.4330 s ^{2} \right ) = 100$

$\frac{1}{2}\left ( 0.5670 s ^{2} \right ) = 100$

$0.2835 s ^{2} = 100$

$s ^{2} \approx 100 \div 0.2835$

$s ^{2} \approx 352.73$

$s \approx\sqrt{ 352.73} \approx 18.7$

Of the five choices, 20 comes closest.

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Example Question #931 : Basic Geometry

The perimeter of a square is 444 . What is the length of one side of the square?

Possible Answers:

101

111

116

112

Correct answer:

111

Explanation:

Recall how to find the perimeter of a square:

$\text{Perimeter}=4(\text{side length})$

By dividing both sides by , we can write the following:

$\text{Side length}=\frac{\text{Perimeter}}{4}$

For the square in question,

$\text{Side length}=\frac{444}{4}$

$\text{Side length}=111$

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Basic Geometry : Squares

Study concepts, example questions & explanations for Basic Geometry

All Basic Geometry Resources

Example Questions

Example Question #1 : How To Find The Length Of The Side Of A Square

Example Question #1 : How To Find The Length Of The Side Of A Square

Example Question #1 : How To Find The Length Of The Side Of A Square

Example Question #1 : How To Find The Length Of The Side Of A Square

Example Question #1 : How To Find The Length Of The Side Of A Square

Example Question #1 : How To Find The Length Of The Side Of A Square

Example Question #411 : Geometry

Example Question #1 : How To Find The Length Of The Side Of A Square

Example Question #412 : Geometry

Example Question #931 : Basic Geometry

All Basic Geometry Resources

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