We are open Saturday and Sunday!

Call Now to Set Up Tutoring:

(888) 888-0446

Basic Geometry : Rectangles

Study concepts, example questions & explanations for Basic Geometry

Create An Account

All Basic Geometry Resources

9 Diagnostic Tests 164 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #3 : How To Find The Length Of The Diagonal Of A Rectangle

A standard high school basketball court is 84 feet long and 50 feet wide. During practice, Coach K has Kyrie run from one the right corner on one end of the court to the left corner at the other end of the court. To the nearest foot, how far did Kyrie run?

Possible Answers:

87ft

134ft

104ft

93ft

98ft

Correct answer:

98ft

Explanation:

A picture helps greatly with this problem, so we begin with a rectangular basketball court.

We note that the distance run by Kyrie (drawn in red) is the diagonal of our rectangle, which we will call . We should also not that this diagonal divides our rectangle into two congruent right triangles. We can therefore find the length of our diagonal by focusing on one of these triangles and determining the hypotenuse. This can be done with the Pythagorean Theorem, which gives us:

50^2+84^2=k^2

2500+7056=k^2

9556=k^2

Taking the square root gives us

k=97.754795...

Rounding to the nearest foot gives an answer of 98.

Report an Error

Example Question #1 : How To Find The Length Of The Diagonal Of A Rectangle

A rectangle has a height of and a base of . What is the length of its diagonal rounded to the nearest tenth?

Possible Answers:

30.5

19.5

28.4

12.2

24.4

Correct answer:

24.4

Explanation:

1. Use Pythagorean Theorem with a=14 and b=20 .

$a^{2}+b^{2}=c^{2}$

$14^{2}+20^{2}=c^{2}$

2. Solve for , the length of the diagonal:

$14^{2}+20^{2}=c^{2}$

$196+400=c^{2}$

$596=c^{2}$

c=24.41

This rounds down to 24.4 because the hundredth's place () is less than .

Report an Error

Example Question #4 : How To Find The Length Of The Diagonal Of A Rectangle

The sides of rectangle ABCD are 4 in and 13 in.

How long is the diagonal of rectangle ABCD?

Possible Answers:

$\sqrt{125}$

$\sqrt{185}$

185

Correct answer:

$\sqrt{185}$

Explanation:

A diagonal of a rectangle cuts the rectangle into 2 right triangles with sides equal to the sides of the rectangle and with a hypotenuse that is the diagonal. All you need to do is use the pythagorean theorem:

a^2+b^2=c^2 where a and b are the sides of the rectangle and c is the length of the diagonal.

$\sqrt{4^2+16^2}=\sqrt{185}=c$

Report an Error

Example Question #1 : How To Find The Length Of The Diagonal Of A Rectangle

Find the length of the diagonal of a rectangle that has a length of and a width of .

Possible Answers:

Correct answer:

Explanation:

The diagonal of a rectangle is also the hypotenuse of a right triangle that has the length and the width of the rectangle as its legs.

We can then use the Pythgorean Theorem to find the diagonal.

$\text{Diagonal}=\sqrt{\text{length}^2+\text{width}^2}$

For the given rectangle,

$\text{Diagonal}=\sqrt{9^2+12^2}=\sqrt{225}=15$

Report an Error

Example Question #5 : How To Find The Length Of The Diagonal Of A Rectangle

Find the length of the diagonal of a rectangle that has a length of and a width of .

Possible Answers:

Correct answer:

Explanation:

The diagonal of a rectangle is also the hypotenuse of a right triangle that has the length and the width of the rectangle as its legs.

We can then use the Pythgorean Theorem to find the diagonal.

$\text{Diagonal}=\sqrt{\text{length}^2+\text{width}^2}$

For the given rectangle,

$\text{Diagonal}=\sqrt{10^2+24^2}=\sqrt{676}=26$

Report an Error

Example Question #3 : How To Find The Length Of The Diagonal Of A Rectangle

Find the length of the diagonal of a rectangle that has a length of and a width of .

Possible Answers:

Correct answer:

Explanation:

The diagonal of a rectangle is also the hypotenuse of a right triangle that has the length and the width of the rectangle as its legs.

We can then use the Pythgorean Theorem to find the diagonal.

$\text{Diagonal}=\sqrt{\text{length}^2+\text{width}^2}$

For the given rectangle,

$\text{Diagonal}=\sqrt{6^2+8^2}=\sqrt{100}=10$

Report an Error

Example Question #1 : How To Find The Length Of The Diagonal Of A Rectangle

Find the length of the diagonal of a rectangle that has a length of and a width of .

Possible Answers:

$12\sqrt{35}$

$3\sqrt{34}$

$6\sqrt{2}$

$4\sqrt3$

Correct answer:

$3\sqrt{34}$

Explanation:

The diagonal of a rectangle is also the hypotenuse of a right triangle that has the length and the width of the rectangle as its legs.

We can then use the Pythgorean Theorem to find the diagonal.

$\text{Diagonal}=\sqrt{\text{length}^2+\text{width}^2}$

For the given rectangle,

$\text{Diagonal}=\sqrt{9^2+15^2}=\sqrt{306}=3\sqrt{34}$

Report an Error

Example Question #111 : Rectangles

Find the length of the diagonal of a rectangle that has a length of and a width of .

Possible Answers:

$16\sqrt{3}$

$15\sqrt{29}$

Correct answer:

Explanation:

The diagonal of a rectangle is also the hypotenuse of a right triangle that has the length and the width of the rectangle as its legs.

We can then use the Pythgorean Theorem to find the diagonal.

$\text{Diagonal}=\sqrt{\text{length}^2+\text{width}^2}$

For the given rectangle,

$\text{Diagonal}=\sqrt{13^2+84^2}=\sqrt{7225}=85$

Report an Error

Example Question #111 : Rectangles

Find the length of the diagonal of a rectangle that has a length of and a width of .

Possible Answers:

$2\sqrt{5}$

$\sqrt{7}$

$6\sqrt3$

$\sqrt{13}$

Correct answer:

$\sqrt{13}$

Explanation:

The diagonal of a rectangle is also the hypotenuse of a right triangle that has the length and the width of the rectangle as its legs.

We can then use the Pythgorean Theorem to find the diagonal.

$\text{Diagonal}=\sqrt{\text{length}^2+\text{width}^2}$

For the given rectangle,

$\text{Diagonal}=\sqrt{2^2+3^2}=\sqrt{13}$

Report an Error

Example Question #112 : Quadrilaterals

Find the length of the diagonal of a rectangle that has a length of and a width of .

Possible Answers:

$2\sqrt{15}$

$2\sqrt{13}$

$2\sqrt{19}$

$2\sqrt{17}$

Correct answer:

$2\sqrt{17}$

Explanation:

The diagonal of a rectangle is also the hypotenuse of a right triangle that has the length and the width of the rectangle as its legs.

We can then use the Pythgorean Theorem to find the diagonal.

$\text{Diagonal}=\sqrt{\text{length}^2+\text{width}^2}$

For the given rectangle,

$\text{Diagonal}=\sqrt{8^2+2^2}=\sqrt{68}=2\sqrt{17}$

Report an Error

View Tutors

Nina
Certified Tutor

The University of Texas at Austin, Bachelor in Arts, Finance.

View Tutors

Mariam
Certified Tutor

Yarmouk University, Bachelor of Science, Mathematics. Touro College, Master of Science, Teacher Education, Multiple Levels.

View Tutors

Ebony
Certified Tutor

Ashford University, Bachelor of Education, Education. University of Phoenix-Houston Campus, Masters in Education, Educational...

All Basic Geometry Resources

9 Diagnostic Tests 164 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

MCAT Tutors in Chicago, Math Tutors in Houston, Algebra Tutors in Boston, SAT Tutors in Phoenix, Reading Tutors in Atlanta, Biology Tutors in Philadelphia, Statistics Tutors in Phoenix, Chemistry Tutors in San Diego, French Tutors in Seattle, SSAT Tutors in San Diego

Popular Courses & Classes

SAT Courses & Classes in New York City, Spanish Courses & Classes in Phoenix, GRE Courses & Classes in San Diego, LSAT Courses & Classes in Philadelphia, GRE Courses & Classes in Miami, Spanish Courses & Classes in Atlanta, ISEE Courses & Classes in San Francisco-Bay Area, ACT Courses & Classes in Seattle, MCAT Courses & Classes in Denver, GRE Courses & Classes in New York City

Popular Test Prep

SAT Test Prep in New York City, MCAT Test Prep in Chicago, SAT Test Prep in San Francisco-Bay Area, LSAT Test Prep in Washington DC, MCAT Test Prep in Dallas Fort Worth, SAT Test Prep in Denver, ACT Test Prep in Chicago, ISEE Test Prep in Houston, GMAT Test Prep in Dallas Fort Worth, MCAT Test Prep in Denver

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Basic Geometry : Rectangles

Study concepts, example questions & explanations for Basic Geometry

All Basic Geometry Resources

Example Questions

Example Question #3 : How To Find The Length Of The Diagonal Of A Rectangle

Example Question #1 : How To Find The Length Of The Diagonal Of A Rectangle

Example Question #4 : How To Find The Length Of The Diagonal Of A Rectangle

Example Question #1 : How To Find The Length Of The Diagonal Of A Rectangle

Example Question #5 : How To Find The Length Of The Diagonal Of A Rectangle

Example Question #3 : How To Find The Length Of The Diagonal Of A Rectangle

Example Question #1 : How To Find The Length Of The Diagonal Of A Rectangle

Example Question #111 : Rectangles

Example Question #111 : Rectangles

Example Question #112 : Quadrilaterals

All Basic Geometry Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: