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Basic Geometry : Quadrilaterals

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Example Questions

Example Question #51 : Quadrilaterals

If the area of the rectangle is , what is the perimeter?

Possible Answers:

Correct answer:

Explanation:

In order to find the perimeter of a rectangle, you will need to know both length and width. The question, however, only provides us with the width.

Recall how to find the area of the rectangle:

$\text{Area}=\text{length}\times\text{width}$

Now, using the area and the given width, we can then find the length.

$\text{length}=\frac{\text{Area}}{\text{width}}$

Plug in the given values.

$\text{length}=\frac{72}{12}=6$

Now that we have both length and width, find the perimeter of the rectangle.

$\text{Perimeter}=2(\text{length}+\text{width})$

$\text{Perimeter}=2(12+6)=2(18)=36$

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Example Question #460 : Plane Geometry

If the area of the rectangle is , what is the perimeter?

Possible Answers:

Correct answer:

Explanation:

In order to find the perimeter of a rectangle, you will need to know both length and width. The question, however, only provides us with the width.

Recall how to find the area of the rectangle:

$\text{Area}=\text{length}\times\text{width}$

Now, using the area and the given width, we can then find the length.

$\text{length}=\frac{\text{Area}}{\text{width}}$

Plug in the given values.

$\text{length}=\frac{60}{12}=5$

Now that we have both length and width, find the perimeter of the rectangle.

$\text{Perimeter}=2(\text{length}+\text{width})$

$\text{Perimeter}=2(12+5)=2(17)=34$

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Example Question #52 : Quadrilaterals

If the area of the rectangle is 168 , what is the perimeter?

Possible Answers:

Correct answer:

Explanation:

In order to find the perimeter of a rectangle, you will need to know both length and width. The question, however, only provides us with the width.

Recall how to find the area of the rectangle:

$\text{Area}=\text{length}\times\text{width}$

Now, using the area and the given width, we can then find the length.

$\text{length}=\frac{\text{Area}}{\text{width}}$

Plug in the given values.

$\text{length}=\frac{168}{12}=14$

Now that we have both length and width, find the perimeter of the rectangle.

$\text{Perimeter}=2(\text{length}+\text{width})$

$\text{Perimeter}=2(12+14)=2(26)=52$

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Example Question #53 : Quadrilaterals

If the area of the rectangle is 600 , what is the perimeter?

Possible Answers:

100

130

160

190

Correct answer:

100

Explanation:

In order to find the perimeter of a rectangle, you will need to know both length and width. The question, however, only provides us with the width.

Recall how to find the area of the rectangle:

$\text{Area}=\text{length}\times\text{width}$

Now, using the area and the given width, we can then find the length.

$\text{length}=\frac{\text{Area}}{\text{width}}$

Plug in the given values.

$\text{length}=\frac{600}{20}=30$

Now that we have both length and width, find the perimeter of the rectangle.

$\text{Perimeter}=2(\text{length}+\text{width})$

$\text{Perimeter}=2(20+30)=2(50)=100$

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Example Question #54 : Quadrilaterals

If the area of the rectangle is 228 , what is the perimeter?

Possible Answers:

148

124

Correct answer:

Explanation:

In order to find the perimeter of a rectangle, you will need to know both length and width. The question, however, only provides us with the width.

Recall how to find the area of the rectangle:

$\text{Area}=\text{length}\times\text{width}$

Now, using the area and the given width, we can then find the length.

$\text{length}=\frac{\text{Area}}{\text{width}}$

Plug in the given values.

$\text{length}=\frac{228}{12}=19$

Now that we have both length and width, find the perimeter of the rectangle.

$\text{Perimeter}=2(\text{length}+\text{width})$

$\text{Perimeter}=2(12+19)=2(31)=62$

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Example Question #55 : Quadrilaterals

If the area of the rectangle is 128 , what is the perimeter?

Possible Answers:

Correct answer:

Explanation:

In order to find the perimeter of a rectangle, you will need to know both length and width. The question, however, only provides us with the width.

Recall how to find the area of the rectangle:

$\text{Area}=\text{length}\times\text{width}$

Now, using the area and the given width, we can then find the length.

$\text{length}=\frac{\text{Area}}{\text{width}}$

Plug in the given values.

$\text{length}=\frac{128}{8}=16$

Now that we have both length and width, find the perimeter of the rectangle.

$\text{Perimeter}=2(\text{length}+\text{width})$

$\text{Perimeter}=2(16+8)=2(24)=48$

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Example Question #56 : Quadrilaterals

If the area of the rectangle is 1440 , what is the perimeter?

Possible Answers:

168

152

324

204

Correct answer:

152

Explanation:

In order to find the perimeter of a rectangle, you will need to know both length and width. The question, however, only provides us with the width.

Recall how to find the area of the rectangle:

$\text{Area}=\text{length}\times\text{width}$

Now, using the area and the given width, we can then find the length.

$\text{length}=\frac{\text{Area}}{\text{width}}$

Plug in the given values.

$\text{length}=\frac{1440}{36}=40$

Now that we have both length and width, find the perimeter of the rectangle.

$\text{Perimeter}=2(\text{length}+\text{width})$

$\text{Perimeter}=2(36+40)=2(76)=152$

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Example Question #57 : Quadrilaterals

Find the perimeter of a rectangle given width 4 and length 6.

Possible Answers:

Correct answer:

Explanation:

To solve, simply use the fomula for the perimeter of a square. Thus,

P=2(w+l)=2*(4+6)=2*10=20

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Example Question #58 : Quadrilaterals

Find the perimeter of a rectangle given width of 6 and length of 8.

Possible Answers:

Correct answer:

Explanation:

The perimeter of a rectangle is found by adding all the side lengths together. In a rectangle there are two widths and two lengths.

In other words, simply use the formula for the perimeter of a rectangle and let,

$\\w=6 \\l=8$ .

Thus,

P=2(w+l)=2*(6+8)=2*14=28

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Example Question #59 : Quadrilaterals

Find the perimeter of a rectangle with width 9 and length 1.

Possible Answers:

Correct answer:

Explanation:

To solve, simply use the formula for the perimeter of a rectangle. Thus,

P=2(w+l)=2*(9+1)=2*10=20

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Basic Geometry : Quadrilaterals

Study concepts, example questions & explanations for Basic Geometry

All Basic Geometry Resources

Example Questions

Example Question #51 : Quadrilaterals

Example Question #460 : Plane Geometry

Example Question #52 : Quadrilaterals

Example Question #53 : Quadrilaterals

Example Question #54 : Quadrilaterals

Example Question #55 : Quadrilaterals

Example Question #56 : Quadrilaterals

Example Question #57 : Quadrilaterals

Example Question #58 : Quadrilaterals

Example Question #59 : Quadrilaterals

All Basic Geometry Resources

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