Call Now to Set Up Tutoring:

(888) 888-0446

Basic Geometry : Quadrilaterals

Study concepts, example questions & explanations for Basic Geometry

Create An Account

All Basic Geometry Resources

9 Diagnostic Tests 164 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #391 : Quadrilaterals

In the figure, a square is inscribed in a circle. If the perimeter of the square is , then what is the area of the shaded region?

Possible Answers:

The area of the shaded region cannot be determined.

26.30

27.97

28.63

Correct answer:

27.97

Explanation:

From the figure, you should notice that the diameter of the circle is also the diagonal of the square.

In order to find the area of the shaded region, we will first need to find the area of the circle and the area of the square.

First, let's find the area of the square.

From the given information, we can find the length of a side of the square.

$\text{Perimeter}=4(\text{side})$

$\text{side}=\frac{\text{Perimeter}}{4}$

Substitute in the value of the perimeter to find the length of a side of the square.

$\text{side}=\frac{28}{4}$

Simplify.

$\text{side}=7$

Now recall how to find the area of a square:

$\text{Area of square}=\text{side}^2$

Substitute in the value of the side of the square to find the area.

$\text{Area of square}=7^2$

Simplify.

$\text{Area of square}=49$

Now, use the Pythagorean theorem to find the length of the diagonal of the square.

$\text{Diagonal}^2=\text{side}^2+\text{side}^2$

$\text{Diagonal}=\sqrt{2(\text{side})^2}$

Simplify.

$\text{Diagonal}=\text{side}\sqrt2$

Substitute in the value of the side of the square to find the length of the diagonal.

$\text{Diagonal}=7\sqrt2$

Recall that the diagonal of the square is the same as the diameter of the circle.

$\text{Diameter}=\text{Diagonal}=7\sqrt2$

From the diameter, we can then find the radius of the circle:

$\text{Radius}=\frac{\text{Diameter}}{2}$

$\text{Radius}=\frac{7\sqrt2}{2}$

Now, use the radius to find the area of the circle.

$\text{Area of Circle}=\pi\times\text{radius}^2$

$\text{Area of circle}=\pi\times (\frac{7\sqrt2}{2})^2$

Simplify.

$\text{Area of circle}=\frac{49}{2}\pi$

To find the area of the shaded region, subtract the area of the square from the area of the circle.

$\text{Area of Shaded Region}=\text{Area of circle}-\text{Area of square}$

$\text{Area of shaded region}=\frac{49}{2}\pi-49$

Solve.

$\text{Area of shaded region}=27.97$

Report an Error

Example Question #143 : Squares

In the figure, a square is inscribed in a circle. If the perimeter of the square is , then what is the area of the shaded region?

Possible Answers:

33.00

36.53

37.54

39.63

Correct answer:

36.53

Explanation:

From the figure, you should notice that the diameter of the circle is also the diagonal of the square.

In order to find the area of the shaded region, we will first need to find the area of the circle and the area of the square.

First, let's find the area of the square.

From the given information, we can find the length of a side of the square.

$\text{Perimeter}=4(\text{side})$

$\text{side}=\frac{\text{Perimeter}}{4}$

Substitute in the value of the perimeter to find the length of a side of the square.

$\text{side}=\frac{32}{4}$

Simplify.

$\text{side}=8$

Now recall how to find the area of a square:

$\text{Area of square}=\text{side}^2$

Substitute in the value of the side of the square to find the area.

$\text{Area of square}=8^2$

Simplify.

$\text{Area of square}=64$

Now, use the Pythagorean theorem to find the length of the diagonal of the square.

$\text{Diagonal}^2=\text{side}^2+\text{side}^2$

$\text{Diagonal}=\sqrt{2(\text{side})^2}$

Simplify.

$\text{Diagonal}=\text{side}\sqrt2$

Substitute in the value of the side of the square to find the length of the diagonal.

$\text{Diagonal}=8\sqrt2$

Recall that the diagonal of the square is the same as the diameter of the circle.

$\text{Diameter}=\text{Diagonal}=8\sqrt2$

From the diameter, we can then find the radius of the circle:

$\text{Radius}=\frac{\text{Diameter}}{2}$

$\text{Radius}=\frac{8\sqrt2}{2}$

Simplify.

$\text{Radius}=4\sqrt2$

Now, use the radius to find the area of the circle.

$\text{Area of Circle}=\pi\times\text{radius}^2$

$\text{Area of circle}=\pi\times (4\sqrt2)^2$

Simplify.

$\text{Area of circle}=32\pi$

To find the area of the shaded region, subtract the area of the square from the area of the circle.

$\text{Area of Shaded Region}=\text{Area of circle}-\text{Area of square}$

$\text{Area of shaded region}=32\pi-64$

Solve.

$\text{Area of shaded region}=36.53$

Report an Error

Example Question #801 : Plane Geometry

In the figure, a square is inscribed in a circle. If the perimeter of the square is , then what is the area of the shaded region?

Possible Answers:

42.20

46.23

The area of the shaded region cannot be determined.

48.69

Correct answer:

46.23

Explanation:

From the figure, you should notice that the diameter of the circle is also the diagonal of the square.

In order to find the area of the shaded region, we will first need to find the area of the circle and the area of the square.

First, let's find the area of the square.

From the given information, we can find the length of a side of the square.

$\text{Perimeter}=4(\text{side})$

$\text{side}=\frac{\text{Perimeter}}{4}$

Substitute in the value of the perimeter to find the length of a side of the square.

$\text{side}=\frac{36}{4}$

Simplify.

$\text{side}=9$

Now recall how to find the area of a square:

$\text{Area of square}=\text{side}^2$

Substitute in the value of the side of the square to find the area.

$\text{Area of square}=9^2=81$

Now, use the Pythagorean theorem to find the length of the diagonal of the square.

$\text{Diagonal}^2=\text{side}^2+\text{side}^2$

$\text{Diagonal}=\sqrt{2(\text{side})^2}$

Simplify.

$\text{Diagonal}=\text{side}\sqrt2$

Substitute in the value of the side of the square to find the length of the diagonal.

$\text{Diagonal}=9\sqrt2$

Recall that the diagonal of the square is the same as the diameter of the circle.

$\text{Diameter}=\text{Diagonal}=9\sqrt2$

From the diameter, we can then find the radius of the circle:

$\text{Radius}=\frac{\text{Diameter}}{2}$

$\text{Radius}=\frac{9\sqrt2}{2}$

Now, use the radius to find the area of the circle.

$\text{Area of Circle}=\pi\times\text{radius}^2$

$\text{Area of circle}=\pi\times (\frac{9\sqrt2}{2})^2$

Simplify.

$\text{Area of circle}=\frac{81}{2}\pi$

To find the area of the shaded region, subtract the area of the square from the area of the circle.

$\text{Area of Shaded Region}=\text{Area of circle}-\text{Area of square}$

$\text{Area of shaded region}=\frac{81}{2}\pi-81$

Solve.

$\text{Area of shaded region}=46.23$

Report an Error

Example Question #392 : Quadrilaterals

In the figure, a square is inscribed in a circle. If the perimeter of the square is , then what is the area of the shaded region?

Possible Answers:

70.02

71.05

69.07

65.23

Correct answer:

69.07

Explanation:

From the figure, you should notice that the diameter of the circle is also the diagonal of the square.

In order to find the area of the shaded region, we will first need to find the area of the circle and the area of the square.

First, let's find the area of the square.

From the given information, we can find the length of a side of the square.

$\text{Perimeter}=4(\text{side})$

$\text{side}=\frac{\text{Perimeter}}{4}$

Substitute in the value of the perimeter to find the length of a side of the square.

$\text{side}=\frac{44}{4}$

Simplify.

$\text{side}=11$

Now recall how to find the area of a square:

$\text{Area of square}=\text{side}^2$

Substitute in the value of the side of the square to find the area.

$\text{Area of square}=11^2$

Simplify.

$\text{Area of square}=121$

Now, use the Pythagorean theorem to find the length of the diagonal of the square.

$\text{Diagonal}^2=\text{side}^2+\text{side}^2$

$\text{Diagonal}=\sqrt{2(\text{side})^2}$

Simplify.

$\text{Diagonal}=\text{side}\sqrt2$

Substitute in the value of the side of the square to find the length of the diagonal.

$\text{Diagonal}=11\sqrt2$

Recall that the diagonal of the square is the same as the diameter of the circle.

$\text{Diameter}=\text{Diagonal}=11\sqrt2$

From the diameter, we can then find the radius of the circle:

$\text{Radius}=\frac{\text{Diameter}}{2}$

$\text{Radius}=\frac{11\sqrt2}{2}$

Now, use the radius to find the area of the circle.

$\text{Area of Circle}=\pi\times\text{radius}^2$

$\text{Area of circle}=\pi\times (\frac{11\sqrt2}{2})^2$

Simplify.

$\text{Area of circle}=\frac{121}{2}\pi$

To find the area of the shaded region, subtract the area of the square from the area of the circle.

$\text{Area of Shaded Region}=\text{Area of circle}-\text{Area of square}$

$\text{Area of shaded region}=\frac{121}{2}\pi-121$

Solve.

$\text{Area of shaded region}=69.07$

Report an Error

Example Question #146 : Squares

In the figure, a square is inscribed in a circle. If the perimeter of the square is , then what is the area of the shaded region?

Possible Answers:

82.19

85.33

80.20

74.69

Correct answer:

82.19

Explanation:

From the figure, you should notice that the diameter of the circle is also the diagonal of the square.

In order to find the area of the shaded region, we will first need to find the area of the circle and the area of the square.

First, let's find the area of the square.

From the given information, we can find the length of a side of the square.

$\text{Perimeter}=4(\text{side})$

$\text{side}=\frac{\text{Perimeter}}{4}$

Substitute in the value of the perimeter to find the length of a side of the square.

$\text{side}=\frac{48}{4}$

Simplify.

$\text{side}=12$

Now recall how to find the area of a square:

$\text{Area of square}=\text{side}^2$

Substitute in the value of the side of the square to find the area.

$\text{Area of square}=12^2$

Simplify.

$\text{Area of square}=144$

Now, use the Pythagorean theorem to find the length of the diagonal of the square.

$\text{Diagonal}^2=\text{side}^2+\text{side}^2$

$\text{Diagonal}=\sqrt{2(\text{side})^2}$

Simplify.

$\text{Diagonal}=\text{side}\sqrt2$

Substitute in the value of the side of the square to find the length of the diagonal.

$\text{Diagonal}=12\sqrt2$

Recall that the diagonal of the square is the same as the diameter of the circle.

$\text{Diameter}=\text{Diagonal}=12\sqrt2$

From the diameter, we can then find the radius of the circle:

$\text{Radius}=\frac{\text{Diameter}}{2}$

$\text{Radius}=\frac{12\sqrt2}{2}$

Simplify.

$\text{Radius}=6\sqrt2$

Now, use the radius to find the area of the circle.

$\text{Area of Circle}=\pi\times\text{radius}^2$

$\text{Area of circle}=\pi\times (6\sqrt2)^2$

Simplify.

$\text{Area of circle}=72\pi$

To find the area of the shaded region, subtract the area of the square from the area of the circle.

$\text{Area of Shaded Region}=\text{Area of circle}-\text{Area of square}$

$\text{Area of shaded region}=72\pi-144$

Solve.

$\text{Area of shaded region}=82.19$

Report an Error

Example Question #147 : Squares

In the figure, a square is inscribed in a circle. If the perimeter of the square is , then what is the area of the shaded region?

Possible Answers:

2.98

2.31

2.14

2.28

Correct answer:

2.28

Explanation:

From the figure, you should notice that the diameter of the circle is also the diagonal of the square.

In order to find the area of the shaded region, we will first need to find the area of the circle and the area of the square.

First, let's find the area of the square.

From the given information, we can find the length of a side of the square.

$\text{Perimeter}=4(\text{side})$

$\text{side}=\frac{\text{Perimeter}}{4}$

Substitute in the value of the perimeter to find the length of a side of the square.

$\text{side}=\frac{8}{4}$

Simplify.

$\text{side}=2$

Now recall how to find the area of a square:

$\text{Area of square}=\text{side}^2$

Substitute in the value of the side of the square to find the area.

$\text{Area of square}=2^2$

Simplify.

$\text{Area of square}=4$

Now, use the Pythagorean theorem to find the length of the diagonal of the square.

$\text{Diagonal}^2=\text{side}^2+\text{side}^2$

$\text{Diagonal}=\sqrt{2(\text{side})^2}$

Simplify.

$\text{Diagonal}=\text{side}\sqrt2$

Substitute in the value of the side of the square to find the length of the diagonal.

$\text{Diagonal}=2\sqrt2$

Recall that the diagonal of the square is the same as the diameter of the circle.

$\text{Diameter}=\text{Diagonal}=2\sqrt2$

From the diameter, we can then find the radius of the circle:

$\text{Radius}=\frac{\text{Diameter}}{2}$

$\text{Radius}=\frac{2\sqrt2}{2}$

Simplify.

$\text{Radius}=\sqrt2$

Now, use the radius to find the area of the circle.

$\text{Area of Circle}=\pi\times\text{radius}^2$

$\text{Area of circle}=\pi\times (\sqrt2)^2$

Simplify.

$\text{Area of circle}=2\pi$

To find the area of the shaded region, subtract the area of the square from the area of the circle.

$\text{Area of Shaded Region}=\text{Area of circle}-\text{Area of square}$

$\text{Area of shaded region}=2\pi-4$

Solve.

$\text{Area of shaded region}=2.28$

Report an Error

Example Question #803 : Plane Geometry

In the figure, a square is inscribed in a circle. If the perimeter of the square is , then what is the area of the shaded region?

Possible Answers:

0.57

0.32

0.69

0.49

Correct answer:

0.57

Explanation:

From the figure, you should notice that the diameter of the circle is also the diagonal of the square.

In order to find the area of the shaded region, we will first need to find the area of the circle and the area of the square.

First, let's find the area of the square.

From the given information, we can find the length of a side of the square.

$\text{Perimeter}=4(\text{side})$

$\text{side}=\frac{\text{Perimeter}}{4}$

Substitute in the value of the perimeter to find the length of a side of the square.

$\text{side}=\frac{4}{4}$

Simplify.

$\text{side}=1$

Now recall how to find the area of a square:

$\text{Area of square}=\text{side}^2$

Substitute in the value of the side of the square to find the area.

$\text{Area of square}=1^2$

Simplify.

$\text{Area of square}=1$

Now, use the Pythagorean theorem to find the length of the diagonal of the square.

$\text{Diagonal}^2=\text{side}^2+\text{side}^2$

$\text{Diagonal}=\sqrt{2(\text{side})^2}=$

Simplify.

$\text{Diagonal}=\text{side}\sqrt2$

Substitute in the value of the side of the square to find the length of the diagonal.

$\text{Diagonal}=1\sqrt2$

Recall that the diagonal of the square is the same as the diameter of the circle.

$\text{Diameter}=\text{Diagonal}=\sqrt2$

From the diameter, we can then find the radius of the circle:

$\text{Radius}=\frac{\text{Diameter}}{2}$

$\text{Radius}=\frac{\sqrt2}{2}$

Now, use the radius to find the area of the circle.

$\text{Area of Circle}=\pi\times\text{radius}^2$

$\text{Area of circle}=\pi\times (\frac{\sqrt2}{2})^2$

Simplify.

$\text{Area of circle}=\frac{1}{2}\pi$

To find the area of the shaded region, subtract the area of the square from the area of the circle.

$\text{Area of Shaded Region}=\text{Area of circle}-\text{Area of square}$

$\text{Area of shaded region}=\frac{1}{2}\pi-1$

Solve.

$\text{Area of shaded region}=0.57$

Report an Error

Example Question #398 : Quadrilaterals

In the figure, a square is inscribed in a circle. If the perimeter of the square is , then what is the area of the shaded region?

Possible Answers:

5.14

6.98

The area of the shaded region cannot be determined.

4.66

Correct answer:

5.14

Explanation:

From the figure, you should notice that the diameter of the circle is also the diagonal of the square.

In order to find the area of the shaded region, we will first need to find the area of the circle and the area of the square.

First, let's find the area of the square.

From the given information, we can find the length of a side of the square.

$\text{Perimeter}=4(\text{side})$

$\text{side}=\frac{\text{Perimeter}}{4}$

Substitute in the value of the perimeter to find the length of a side of the square.

$\text{side}=\frac{12}{4}$

Simplify.

$\text{side}=3$

Now recall how to find the area of a square:

$\text{Area of square}=\text{side}^2$

Substitute in the value of the side of the square to find the area.

$\text{Area of square}=3^2$

Simplify.

$\text{Area of square}=9$

Now, use the Pythagorean theorem to find the length of the diagonal of the square.

$\text{Diagonal}^2=\text{side}^2+\text{side}^2$

$\text{Diagonal}=\sqrt{2(\text{side})^2}$

Simplify.

$\text{Diagonal}=\text{side}\sqrt2$

Substitute in the value of the side of the square to find the length of the diagonal.

$\text{Diagonal}=3\sqrt2$

Recall that the diagonal of the square is the same as the diameter of the circle.

$\text{Diameter}=\text{Diagonal}=3\sqrt2$

From the diameter, we can then find the radius of the circle:

$\text{Radius}=\frac{\text{Diameter}}{2}$

$\text{Radius}=\frac{3\sqrt2}{2}$

Now, use the radius to find the area of the circle.

$\text{Area of Circle}=\pi\times\text{radius}^2$

$\text{Area of circle}=\pi\times (\frac{3\sqrt2}{2})^2$

Simplify.

$\text{Area of circle}=\frac{9}{2}\pi$

To find the area of the shaded region, subtract the area of the square from the area of the circle.

$\text{Area of Shaded Region}=\text{Area of circle}-\text{Area of square}$

$\text{Area of shaded region}=\frac{9}{2}\pi-9$

Solve.

$\text{Area of shaded region}=5.14$

Report an Error

Example Question #802 : Plane Geometry

In the figure, a square is inscribed in a circle. If the perimeter of the square is , then what is the area of the shaded region?

Possible Answers:

57.08

52.07

60.98

58.15

Correct answer:

57.08

Explanation:

From the figure, you should notice that the diameter of the circle is also the diagonal of the square.

In order to find the area of the shaded region, we will first need to find the area of the circle and the area of the square.

First, let's find the area of the square.

From the given information, we can find the length of a side of the square.

$\text{Perimeter}=4(\text{side})$

$\text{side}=\frac{\text{Perimeter}}{4}$

Substitute in the value of the perimeter to find the length of a side of the square.

$\text{side}=\frac{40}{4}$

Simplify.

$\text{side}=10$

Now recall how to find the area of a square:

$\text{Area of square}=\text{side}^2$

Substitute in the value of the side of the square to find the area.

$\text{Area of square}=10^2$

Simplify.

$\text{Area of square}=100$

Now, use the Pythagorean theorem to find the length of the diagonal of the square.

$\text{Diagonal}^2=\text{side}^2+\text{side}^2$

$\text{Diagonal}=\sqrt{2(\text{side})^2}$

Simplify.

$\text{Diagonal}=\text{side}\sqrt2$

Substitute in the value of the side of the square to find the length of the diagonal.

$\text{Diagonal}=10\sqrt2$

Recall that the diagonal of the square is the same as the diameter of the circle.

$\text{Diameter}=\text{Diagonal}=10\sqrt2$

From the diameter, we can then find the radius of the circle:

$\text{Radius}=\frac{\text{Diameter}}{2}$

$\text{Radius}=\frac{10\sqrt2}{2}$

Simplify.

$\text{Radius}=5\sqrt2$

Now, use the radius to find the area of the circle.

$\text{Area of Circle}=\pi\times\text{radius}^2$

$\text{Area of circle}=\pi\times (5\sqrt2)^2$

Simplify.

$\text{Area of circle}=50\pi$

To find the area of the shaded region, subtract the area of the square from the area of the circle.

$\text{Area of Shaded Region}=\text{Area of circle}-\text{Area of square}$

$\text{Area of shaded region}=50\pi-100$

Solve.

$\text{Area of shaded region}=57.08$

Report an Error

Example Question #400 : Quadrilaterals

In the figure, a square is inscribed in a circle. If the diameter of the circle is , then what is the area of the shaded region?

Possible Answers:

The area of the shaded region cannot be determined.

42.15

41.10

40.98

Correct answer:

41.10

Explanation:

From the figure, you should notice that the diameter of the circle is also the diagonal of the square.

In order to find the area of the shaded region, we will first need to find the area of the circle and the area of the square.

First, recall how to find the area of a circle.

$\text{Area of circle}=\pi\times\text{radius}^2$

Now, use the diameter to find the radius.

$\text{Radius}=\frac{\text{Diameter}}{2}$

Substitute in the given value of the diameter to find the length of the radius.

$\text{Radius}=\frac{12}{2}$

Simplify.

$\text{Radius}=6$

Now, substitute in the value of the radius into the equation to find the area of the circle.

$\text{Area of circle}=\pi\times(6)^2$

Simplify.

$\text{Area of circle}=36\pi$

Now, we will need to find the area of the square.

Notice that the diagonal of the square is also the hypotenuse of a right isosceles triangle that has the sides of the square as the legs of the triangle. We can then use the Pythagorean theorem.

$\text{Diagonal}^2=\text{side}^2+\text{side}^2$

$\text{Diagonal}^2=2(\text{side})^2$

$\text{side}^2=\frac{\text{Diagonal}^2}{2}$

Now, recall how to find the area of a square:

$\text{Area of Square}=\text{side}^2$

Notice that the area of the square is the same as the equation we found through using the Pythagorean theorem.

So now, we can write the following equation:

$\text{Area of Square}=\frac{\text{Diagonal}^2}{2}$

Substitute in the value of the diagonal to find the area of the square.

$\text{Area of Square}=\frac{12^2}{2}$

Simplify.

$\text{Area of Square}=72$

Now, to find the area of the shaded region, subtract the area of the square from the area of the circle.

$\text{Area of Shaded Region}=\text{Area of Circle}-\text{Area of Square}$

$\text{Area of shaded region}=36\pi-72$

Solve.

$\text{Area of shaded region}=41.10$

Report an Error

View Tutors

Jane
Certified Tutor

Western Governors University, Bachelor in Business Administration, Business Administration and Management.

View Tutors

Vicky
Certified Tutor

Clemson University, Doctor of Science, Civil Engineering.

View Tutors

Stephanie
Certified Tutor

University of North Carolina at Charlotte, Bachelor in Arts, International Business.

All Basic Geometry Resources

9 Diagnostic Tests 164 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Biology Tutors in Denver, GMAT Tutors in Miami, MCAT Tutors in Dallas Fort Worth, Statistics Tutors in San Francisco-Bay Area, English Tutors in Houston, SAT Tutors in San Francisco-Bay Area, Computer Science Tutors in San Diego, LSAT Tutors in Los Angeles, Calculus Tutors in Miami, Computer Science Tutors in New York City

Popular Courses & Classes

SSAT Courses & Classes in San Francisco-Bay Area, ISEE Courses & Classes in Los Angeles, GRE Courses & Classes in Philadelphia, SAT Courses & Classes in Seattle, ISEE Courses & Classes in New York City, ACT Courses & Classes in Boston, GRE Courses & Classes in New York City, SAT Courses & Classes in Miami, GRE Courses & Classes in Miami, GRE Courses & Classes in San Diego

Popular Test Prep

ISEE Test Prep in Washington DC, LSAT Test Prep in Denver, GMAT Test Prep in Philadelphia, ACT Test Prep in Dallas Fort Worth, SSAT Test Prep in San Francisco-Bay Area, SAT Test Prep in Phoenix, ISEE Test Prep in Los Angeles, ACT Test Prep in Washington DC, ACT Test Prep in Boston, LSAT Test Prep in Los Angeles

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Basic Geometry : Quadrilaterals

Study concepts, example questions & explanations for Basic Geometry

All Basic Geometry Resources

Example Questions

Example Question #391 : Quadrilaterals

Example Question #143 : Squares

Example Question #801 : Plane Geometry

Example Question #392 : Quadrilaterals

Example Question #146 : Squares

Example Question #147 : Squares

Example Question #803 : Plane Geometry

Example Question #398 : Quadrilaterals

Example Question #802 : Plane Geometry

Example Question #400 : Quadrilaterals

All Basic Geometry Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: