AP Physics 1 : Work, Energy, and Power

Study concepts, example questions & explanations for AP Physics 1

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Example Questions

Example Question #22 : Gravitational Potential Energy

An object is above the floor on a table. Estimate it's velocity upon impact with the floor.

Possible Answers:

Correct answer:

Explanation:

Using conservation of energy:

Solving for :

Plugging in values:

Example Question #23 : Gravitational Potential Energy

Mass of Pluto:

Radius of Pluto:

Determine the escape velocity for a lander on Pluto.

Possible Answers:

None of these

Correct answer:

Explanation:

Using:

The escape velocity is the velocity necessary to have a kinetic energy that can overcome the gravitational potential. That is, the kinetic energy plus the "big G" gravitational potential energy need to add to zero or a positive number.

Solving for

Plugging in values:

Example Question #24 : Gravitational Potential Energy

An object with a weight of  is dropped from rest at a height of  above the ground. When it has been in free fall for  of the original height what is the velocity of the object with respect to the ground? 

Possible Answers:

Correct answer:

Explanation:

The energy before must be equal to the energy when the object is in motion.

Determine the mass of the object.

Plug into the conservation of energy statement above. 

The final velocity of the object will be .

Example Question #25 : Gravitational Potential Energy

John can throw a football with speeds exceeding . If a high school football has an average mass of . What total kinetic energy could John produce with his remarkably strong arm? 

Possible Answers:

Correct answer:

Explanation:

We must first convert to the proper units.

Now use the equation for kinetic energy.

Plug in and solve for the kinetic energy.

John Elway could throw a football with a kinetic energy of .

Example Question #26 : Gravitational Potential Energy

A man weighing  walks to the top of a tall building. How much gravitational potential energy does he have at the top of the  building compared to when he was on the street below?

Possible Answers:

Correct answer:

Explanation:

For this question we will use conservation of gravitational potential energy.

Plug in and solve for .

The man will gain  of gravitational potential energy by walking to the top of the building.

Example Question #21 : Gravitational Potential Energy

 bucket rests on the ground. If you apply  of energy to a rope tied to the bucket, how high can you lift the bucket off the ground?

Possible Answers:

Correct answer:

Explanation:

Use the equation for weight to determine the objects mass.

Plug in and solve for the objects mass.

Use the equation for the potential energy due to gravity.

Plug in and solve for the height.

The bucket can be lifted to a height of .

Example Question #21 : Gravitational Potential Energy

Mass of moon:

Radius of moon:

Determine the gravitational potential energy of a lander above the surface of the moon

Possible Answers:

None of these

Correct answer:

Explanation:

Using:

Combining the radius and the distance to the surface, converting to and plugging in values:

Example Question #22 : Gravitational Potential Energy

Mass of moon:

Radius of moon: 

Determine the work done by gravity on a lander as it moves from to  above the lunar surface

Possible Answers:

None of these

Correct answer:

Explanation:

First, determine the final gravitation potential energy:

Using:

Combining the radius and the distance to the surface, converting to and plugging in values:

Then, determine the initial gravitational potential energy:

Using:

Combining the radius and the distance to the surface, converting to and plugging in values:

Example Question #30 : Gravitational Potential Energy

A roller coaster of mass  is approaching a circular loop with a radius of . The average frictional force on the coaster is  and the velocity of the coaster is  as it enters the loop. How many g's are felt by the riders of the coaster when it reaches the top of the loop?

Possible Answers:

Correct answer:

Explanation:

There are two forces acting on the coaster at the top of the loop: gravity and centrifugal. It is important to note in this problem the difference between centripetal and centrifugal forces. Centripetal force the is actual force applied to the coaster (points inward) and the centrifugal force is that apparent force felt by the coaster as it travels in a loop (points outward). Just remember that these forces are equal, but in opposite directions. Therefore, we will be using the centrifugal force to calculate the g's felt by the coaster. To do this, we will begin with the expression for conservation of energy:

If we assume that the bottom of the loop has a height of zero, we can eliminate initial potential energy. Also, the only work is done by friction, and it is work done on the surrounds, so it will be negative. Therefore, we get:

Plugging in expressions for each of these, we get:

Rearranging for final velocity, we get:

Where d is half the circumference of the loop:

And the final height is twice the radius:

Plugging these in, we get:

Plugging in our values, we get:

Now we can use this to calculate the centrifugal force:

This is in the opposite direction of the other force acting on the system, gravity. Therefore, we get:

Plugging in expressions we get:

Rearranging for net acceleration, we get:

Then calculating g's we get:

Example Question #31 : Gravitational Potential Energy

Rollercoaster

The train car on the rollercoaster above has a mass of , and the potential energy at the top of the first hill is .

What is the height of the hill?

Possible Answers:

Correct answer:

Explanation:

Potential energy is equal to the mass of an object multiplied by gravity multiplied by the height at which the object rests. This is demonstrated by the following equation:

In this problem, you are given the mass and potential energy of the object. Gravity is a constant, therefore there is a single variable left to solve for and this is the height at which the object rests. By plugging in the given values the height is found to be:

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