All AP Physics 1 Resources
Example Questions
Example Question #2 : Current And Voltage
A student has created the given circuit diagram. It consists of a battery, a resistor, and a light bulb. In one minute, 1.2C of charge flows through the resistor. How much charge flows through the light bulb in one minute?
Since the bulb and the resistor are connected in series, the current is the same in each. Electric current is just the flow of charge through the circuit, so the same amount of charge flows through each in one minute.
Example Question #5 : Current And Voltage
If a TV uses of energy over the course of , and it has a voltage of , how many coulombs passed through it during that time?
Because the TV uses , and it was used for , it must have used
.
so:
, and since the TV was used for
Example Question #201 : Electricity And Waves
Give the SI units for voltage.
We have to know what SI units are for this problem. SI units are units that cannot be broken down into smaller component parts. Voltage is defined as:
, where is joules and is Coulombs. Coulombs are already in SI units. However, joules is composed of other terms.
Therefore, voltage can be written as
Example Question #132 : Electricity
of charge pass through a television during a movie. How much is being used by the television?
Current and charge are related by the equation where is the current in Amperes (), is the charge in Coulombs (), and is the time in seconds ().
Time must first be converted to seconds.
Solving for current,
Example Question #133 : Electricity
Who long (in hours) does it take a computer to use of charge ?
Current and charge are related by the equation where is the current in Amperes (), is the charge in Coulombs (), and is the time in seconds ().
For this problem
Example Question #134 : Electricity
What quantity of charge passes through a clock in if its current is ?
Current and charge are related by the equation where is the current in Amperes (), is the charge in Coulombs (), and is the time in seconds ().
Time must first be converted to seconds.
Solving for charge,
.
Example Question #1361 : Ap Physics 1
A circuit with one battery and one resistor with resistance has current flowing through it. It is modified to add two more identical resistors in series of the first resistor and 1 more resistor in parallel to the other three with resistance . Determine the current flowing through the original resistor.
To find our answer, we have to know how each of the new additions changes the circuit. The addition of the two resistors in series do not affect the current because current is equivalent for resistors in series. However, since there is a resistor in parallel with equivalent resistance to the sum of the 3 resistors in series, current will split evenly amongst the two pathways, thus leading to a current of flowing through the original resistor.
Example Question #131 : Electricity
Consider a circuit composed of a battery and three resistors in series. The three resistors are . Calculate the voltage drop across .
In order to find the voltage drop across , we will use Ohm's law:
.
However, we first need to solve for the current in the circuit. This will be calculated by applying Ohm's law to the entire circuit, using the total resistance for resistors in series.
Finally, we use this calculated current to find the voltage drop across .
Example Question #101 : Circuits
Determine the voltage drop across a resistor of experiencing a current flowing through it, if it is connected to a battery of ?
In circuits with resistors, the only thing necessary to determine voltage drop across a resistor is the current through it and the resistance, as given by Ohm's law.
Example Question #211 : Electricity And Waves
You have the following circuit. The values for the components are:
What is the current passing though R3?
The first step is to find the equivalent resistance of the entire circuit. Note that R2 and R3 are in parallel, and they are in series with R1. Therefore, in order to find the equivalent resistance:
Then, in order to find the total current, use Ohm's Law:
That means that will pass through R1, and will split when it reaches the junction between R2 and R3 based on the ratio of the two resistance:
of current passes through the resistor R3.