Call Now to Set Up Tutoring:

(888) 888-0446

AP Physics 1 : Electricity

Study concepts, example questions & explanations for AP Physics 1

Create An Account

All AP Physics 1 Resources

7 Diagnostic Tests 170 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #161 : Electricity And Waves

Circuit diagram

I=30A

$R_1=2\Omega$

$R_2=3\Omega$

In the circuit above, what is the total voltage?

Possible Answers:

25V

75V

150 V

36V

30V

Correct answer:

36V

Explanation:

To find the voltage, first find the combined resistances of the resistors in parallel:

$\frac{1}{R_T}=\frac{1}{R_1}+\frac{1}{R_2}=\frac{1}{2\Omega }+\frac{1}{3\Omega }$

$\frac{1}{R_T}=\frac{5}{6\Omega }$

$R_T=\frac{6}{5}\Omega$

Use Ohm's law to find the voltage.

V=IR

$V=30A\left(\frac{6}{5}\Omega\right)=36V$

Report an Error

Example Question #3 : Understanding Circuit Diagrams

Circuit diagram

V=5V

I=1.25A

$R_1=6\Omega$

In the circuit above, what is the resistance of R_2 ?

Possible Answers:

$2\Omega$

$-2\Omega$

$12\Omega$

$2.4\Omega$

$10\Omega$

Correct answer:

$12\Omega$

Explanation:

Find the total resistance of the circuit, which can be determined using Ohm's law.

V=IR

$R_T=\frac{V}{I}$

$R_T=\frac{5}{1.25}\Omega=4\Omega$

Now, the resistance of the second resistor can be found. Since the two resistors are in parallel, they're related to the total resistance as follows:

$\frac{1}{R_T}=\frac{1}{R_1}+\frac{1}{R_2}$

Rearrange and solve for R_2

$\frac{1}{R_2}=\frac{1}{R_T}-\frac{1}{R_1}$

$\frac{1}{R_2}=\frac{1}{4\Omega }-\frac{1}{6\Omega }=\frac{6-4}{24\Omega }=\frac{1}{12\Omega }$

$R_2=12\Omega$

Report an Error

Example Question #5 : Understanding Circuit Diagrams

Circuit diagram2

$R_1=3\Omega$

$R_2=6\Omega$

$R_3=2\Omega$

$R_4=16\Omega$

In the circuit above, what is the total resistance?

Possible Answers:

$\frac{9}{32}\Omega$

$\frac{34}{5}\Omega$

$27\Omega$

$\frac{27}{2}\Omega$

$\frac{34}{9}\Omega$

Correct answer:

$\frac{34}{9}\Omega$

Explanation:

Find the combined resistances for the resistors in parallel:

$\frac{1}{R_A}=\frac{1}{R_1}+\frac{1}{R_2}$

$\frac{1}{R_A}=\frac{1}{3\Omega}+\frac{1}{6\Omega}=\frac{9}{18\Omega}$

$R_A=2\Omega$

$\frac{1}{R_B}=\frac{1}{R_3}+\frac{1}{R_4}$

$\frac{1}{R_B}=\frac{1}{2\Omega}+\frac{1}{16\Omega}=\frac{18}{32\Omega}$

$R_B=\frac{16}{9}\Omega$

Combine these two combined series resistors to find the total resistance:

$R_T=R_A+R_B=2\Omega+\frac{16}{9}\Omega=\frac{34}{9}\Omega$

Report an Error

Example Question #4 : Understanding Circuit Diagrams

Circuit diagram2

$R_1=1\Omega$

$R_2=2\Omega$

$R_3=3\Omega$

$R_4=4\Omega$

V=10V

In the circuit above, what is the voltage drop across R_3 ?

Possible Answers:

12.6 V

5.4V

1.3V

2.8 V

7.2V

Correct answer:

7.2V

Explanation:

Find the total resistance of the circuit. First, calculate the values of the combined resistances of the resistors in parallel:

$\frac{1}{R_A}=\frac{1}{R_1}+\frac{1}{R_2}$

$\frac{1}{R_A}=\frac{1}{1\Omega}+\frac{1}{2\Omega}=\frac{3}{2\Omega}$

$R_A=\frac{2}{3}\Omega$

$\frac{1}{R_B}=\frac{1}{R_3}+\frac{1}{R_4}$

$\frac{1}{R_B}=\frac{1}{3\Omega}+\frac{1}{4\Omega}=\frac{7}{12\Omega}$

$R_B=\frac{12}{7}\Omega$

Therefore, the total resistance is:

$R_T=R_A+R_B=\frac{2}{3}\Omega+\frac{12}{7}\Omega=\frac{50}{21}\Omega$

Now, note that since R_3 and R_4 are in parallel, the voltage drop across them is the same. Use Ohm's law to relate current in terms of voltage and resistance.

$I=\frac{V_T}{R_T}$

Substitute into Ohm's law for the resistance across R_3 :

$V_{3,4}=\frac{V}{R_T}R_B$

$V_{3,4}=10V\left(\frac{21}{50\Omega}\right)\left(\frac{12\Omega}{7}\right)$

$V_{3,4}=7.2V$

Report an Error

Example Question #1311 : Ap Physics 1

Circuit diagram2

$R_1=1\Omega$

$R_2=2\Omega$

$R_3=3\Omega$

$R_4=4\Omega$

V=10V

In the circuit above, what is the current passing through R_3 ?

Possible Answers:

4.2A

1.4A

2.4A

1.8A

2.8A

Correct answer:

2.4A

Explanation:

Find the total resistance of the circuit. First, calculate the values of the combined resistances of the resistors in parallel:

$\frac{1}{R_A}=\frac{1}{R_1}+\frac{1}{R_2}$

$\frac{1}{R_A}=\frac{1}{1\Omega}+\frac{1}{2\Omega}=\frac{3}{2\Omega}$

$R_A=\frac{2}{3}\Omega$

$\frac{1}{R_B}=\frac{1}{R_3}+\frac{1}{R_4}$

$\frac{1}{R_B}=\frac{1}{3\Omega}+\frac{1}{4\Omega}=\frac{7}{12\Omega}$

$R_B=\frac{12}{7}\Omega$

Therefore, the total resistance is:

$R_T=R_A+R_B=\frac{2}{3}\Omega+\frac{12}{7}\Omega=\frac{50}{21}\Omega$

From Ohm's law, we know that $\frac{V}{R_T}$ is the current traveling through the circuit.

$I=10V\left(\frac{21}{50\Omega}\right)=4.2A$

This current will be divided between and , with more current taking the path of lower resistance.

Total voltage drop across $R_{3,4}$ :

$V_{3,4}=I_TR_{3,4}$

$V_{3,4}=4.2A\cdot\frac{12}{7}\Omega$

$V_{3,4}=7.2V$

V_3=V_4=7.2V

The current through R_3 is given by:

$I_3=\frac{V_3}{R_3}$

$I_3=\frac{7.2V}{3\Omega}=2.4A$

Report an Error

Example Question #11 : Understanding Circuit Diagrams

Circuitdiagram3

$R_1=3\Omega$

$R_2=6\Omega$

$R_3=2\Omega$

$R_4=10\Omega$

In the circuit above, what is the total resistance?

Possible Answers:

$21\Omega$

$\frac{21}{108}\Omega$

$\frac{80}{21}\Omega$

$\frac{21}{80}\Omega$

$\frac{108}{21}\Omega$

Correct answer:

$\frac{80}{21}\Omega$

Explanation:

Begin by combining the resistors that are immediately in series:

$R_A=R_1+R_3=3\Omega+2\Omega=5\Omega$

$R_B=R_2+R_4=6\Omega+10\Omega=16\Omega$

Circuit diagramab

Now to find the total resistance, combine these two new resistance values, which are in parallel:

$\frac{1}{R_T}=\frac{1}{5\Omega}+\frac{1}{16\Omega}=\frac{21}{80\Omega}$

$R_T=\frac{80}{21}\Omega$

Report an Error

Example Question #11 : Understanding Circuit Diagrams

Circuitdiagram3

$R_1=1\Omega$

$R_2=2\Omega$

$R_3=3\Omega$

$R_4=4\Omega$

V=10V

In the circuit above, what is the voltage drop across R_3 ?

Possible Answers:

3.3V

2.5 V

5.0V

6.7V

7.5V

Correct answer:

7.5V

Explanation:

To approach this problem, note that there are no other resistors (or combinations or resistors) beyond the parallel arrangement shown, so the voltage drop across the top (R_1,R_3) and the bottom (R_2,R_4) is the same and equal to the voltage across the circuit, 10V .

The voltage drop across R_3 can be found as:

$V_3=\frac{R_3}{R_1+R_3}V=\frac{3\Omega}{1\Omega+3\Omega}10V=\frac{3}{4}\cdot10V$

V_3=7.5V

Report an Error

Example Question #12 : Understanding Circuit Diagrams

Circuitdiagram3

$R_1=1\Omega$

$R_2=2\Omega$

$R_3=3\Omega$

$R_4=4\Omega$

V=10V

In the circuit above, what is the current passing through R_3 ?

Possible Answers:

0.625A

1.667A

2.5A

1.875A

4.167A

Correct answer:

2.5A

Explanation:

To approach this problem, note that there are no other resistors (or combinations or resistors) beyond the parallel arrangement shown, so the voltage drop across the top (R_1,R_3) and the bottom (R_2, R_4) is the same and equal to the voltage across the circuit, 10V .

Furthermore, the current that passes through R_1 must be the same as the current that passes through R_3 .

Therefore, the current that passes through them can be found by rearranging Ohm's law, solving for current.

$I_{1,3}=\frac{V}{R_1+R_3}=\frac{10V}{1\Omega+3\Omega}$

$I_{1,3}=2.5A$

Report an Error

Example Question #13 : Understanding Circuit Diagrams

Basic circuit2

In the circuit above:

$V_{in}=12V$

$Z_1=11\Omega$

$Z_2=21\Omega$

$Z_3=16\Omega$

What is the current across Z_3 ?

Possible Answers:

0.38A

2.25A

1.13A

1.50A

0.75A

Correct answer:

0.75A

Explanation:

The quickest way to approach this problem is to realize that the voltage drop across Z_3 is the same as the voltage drop across the combined resistances of Z_1 and Z_2 . Since this parallel combination is the only presence of resistance in the circuit, this voltage drop must be the total voltage of the circuit, 12V .

Therefore, the current across Z_3 is:

$I_3=\frac{V_3}{Z_3}$

$I_3=\frac{12V}{16\Omega}$

I_3=0.75A

Report an Error

Example Question #14 : Understanding Circuit Diagrams

Basic circuit2

In the circuit above:

$V_{in}=12V$

$Z_1=11\Omega$

$Z_2=21\Omega$

$Z_3=16\Omega$

What is the current across Z_2 ?

Possible Answers:

0.375A

1.50A

0.750A

2.25A

1.125A

Correct answer:

0.375A

Explanation:

Realize that the voltage drop across the combined resistances of Z_1 and Z_2 must be equal to the voltage of the circuit, since the parallel combination is the only presence of resistance in the circuit. This voltage drop must be the total voltage of the circuit, 12V .

The current across Z_1 and Z_2 is the same, and is given as:

$I_1=I_2=\frac{12V}{Z_1+Z_2}$

$I_2=\frac{12V}{32\Omega}$

I_2=0.375A

Report an Error

View AP Physics 1 Tutors

Mohammad
Certified Tutor

Jamia Millia Islamia, Master of Science, Physics.

View AP Physics 1 Tutors

Taiwo
Certified Tutor

University of Windsor, Master's/Graduate, Economics.

View AP Physics 1 Tutors

Pankaj
Certified Tutor

University of Delhi, Electrical Engineer, Electrical Engineering. Columbia University in the City of New York, Master of Arts...

All AP Physics 1 Resources

7 Diagnostic Tests 170 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

English Tutors in Houston, GRE Tutors in Philadelphia, Computer Science Tutors in Dallas Fort Worth, SAT Tutors in Philadelphia, SSAT Tutors in Denver, Math Tutors in Phoenix, Statistics Tutors in Seattle, SAT Tutors in Washington DC, Reading Tutors in Phoenix, SAT Tutors in Chicago

Popular Courses & Classes

GMAT Courses & Classes in Miami, SAT Courses & Classes in Denver, LSAT Courses & Classes in Atlanta, ISEE Courses & Classes in Dallas Fort Worth, LSAT Courses & Classes in Miami, SAT Courses & Classes in Dallas Fort Worth, Spanish Courses & Classes in New York City, LSAT Courses & Classes in Boston, ACT Courses & Classes in Los Angeles, SSAT Courses & Classes in Dallas Fort Worth

Popular Test Prep

MCAT Test Prep in Philadelphia, MCAT Test Prep in San Francisco-Bay Area, ISEE Test Prep in Miami, MCAT Test Prep in San Diego, ACT Test Prep in Los Angeles, LSAT Test Prep in Miami, SSAT Test Prep in Chicago, ISEE Test Prep in Seattle, SAT Test Prep in Boston, LSAT Test Prep in Los Angeles

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

AP Physics 1 : Electricity

Study concepts, example questions & explanations for AP Physics 1

All AP Physics 1 Resources

Example Questions

Example Question #161 : Electricity And Waves

Example Question #3 : Understanding Circuit Diagrams

Example Question #5 : Understanding Circuit Diagrams

Example Question #4 : Understanding Circuit Diagrams

Example Question #1311 : Ap Physics 1

Example Question #11 : Understanding Circuit Diagrams

Example Question #11 : Understanding Circuit Diagrams

Example Question #12 : Understanding Circuit Diagrams

Example Question #13 : Understanding Circuit Diagrams

Example Question #14 : Understanding Circuit Diagrams

All AP Physics 1 Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: