The angular velocity is given by:

One circle is equal to , thus

If the cars are racing side by side on a circular track, then they have the same angular velocity, because they complete their circles in the same amount of time.

This is a centripetal force problem. It's important to know that when you draw your free body diagram (FBD), centripetal force () isn't drawn, similar to how net forces () aren't drawn.  is actually the centripetal or circular form of. So when we talk about circular motion such as this, we can set the two equal to each other. Why is this? Well we are trying to translate this object's circular motion into it's linear velocity (our answer).

We can now set, or  equal to the combination of vertical forces in our FBD

But like we said earlier, we need to connect our linear forces to our centripetal forces. Remember this equation?

Now let's put it all together

Time to pull in some algebra now. Remember we want the speed of the bucket, or the velocity of the bucket at the lowest point of the circle, so solve for :

If you plut in everything and solve (remember to use PEMDAS), your answer should be

Centripetal acceleration is as follows:

All we need to do is solve and plug in for 

 = distance traveled and t is the time it took to travel that distance

We know that the yo-yo made 4 revolutions in .

One revolution is the circumference of the yo-yo path: 

So we can either solve for in terms of how far the yo-yo went in one second (I), or how long it took to make one revolution (II); I'll show both, either one is correct if you wish to plug in

or

REMEMBER: Both of these will give you the same answer (check it out if you're good at algebra). Physics is all about comfort in manipulation so choose the way that suits you!

Now plug this into our  equation. Lucky for you, the radius was 

Note: I put in the units so you can see how they cancel out algebraically 

In an isolated system, there is no net torque. If there is no net torque on the system, then the total angular momentum of the system remains the same. The angular momentum of a rotating object is equal to the moment of inertia of the object multiplied by the object's angular velocity.

 is the symbol for angular momentum,  is the moment of inertia, and  is the angular velocity.

Therefore, if the moment of inertia, , is halved, then for the angular momentum, , to remain constant, the angular velocity, , must be doubled. This is because , which is the multiplicative identity. Anything multiplied by one remains the same. So, the final angular velocity would be twice as large as it was originally.

The angular moment of the merry-go-round after 3 seconds is simply

Angular momentum is also given by

Plugging in 30 for  gives us

The formula for angular momentum is

where

 = angular momentum

 = moment of inertia

 = angular speed

Angular speed is defined as

The initial period of the satellite is 1 minute, so:

Plugging this in, we can solve for the initial angular momentum:

After Erin extends the the solar panels, momentum is the same (conservation of momentum), but the moment of inertia is now . Thus,

Therefore, 

Plugging this back into the definition, we get

Therefore,

Thus, the satellite now rotates once every 3 minutes.

Angular momentum is always conserved.

The equation relating angular momentum, moment of inertia and angular velocity is:

Moment of inertia can also be written as follows:

Plug in given values to find  and 

Set the initial angular momentum equal to the final angular momentum and solve.

This is a conservation of angular momentum problem, so we set the angular momentum of the rod  to the equivalent angular momentum of the ball 

Note that the  here is length, not angular momentum. Be careful not to cancel the  since it refers to the rod on the left and the ball on the right. Finally, the  on the right is the effective radius of the ball at the moment of impact, so it's simply the length of the rod.