AP Computer Science A : Evaluating Numerical Expressions
Study concepts, example questions & explanations for AP Computer Science A
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Example Questions
Example Question #1 : Evaluating Numerical Expressions
Consider the following code:
int i = 85, j = 2, k = 4;
i--;
j++;
k -= 6;
i = i / j + i / k;
What is the value of i in the code above?
It is probably easiest to give a running commentary on the code in order to understand it. See the comments in bold below:
int i = 85, j = 2, k = 4;
i--; // After this, i = 84
j++; // After this, j = 3
k -= 6; // After this, k = k - 6 or k = -2
/*
Consider this in several steps:
i / j = 84 / 3 = 28
i / k = 84 / -2 = -42
Thus, the final expression is:
i = 28 - 42 = -14
*/
i = i / j + i / k;
Example Question #32 : Primitive Data Types
Consider the code below:
int a = 24, b = 17, c = 5, d = 7;
b = b % d + a / b;
a %= b;
a -= 12;
What is the value of a at the end of the code above?
The easiest way to trace code like this is to provide running commentary in bold comments. See these below:
int a = 24, b = 17, c = 5, d = 7;
/*
The modulus (%) is the remainder of a division. So . . .
b % d = 17 % 7 = 3 (17 divided by 7 is 2 remainder 3.)
a / b = 1 (Remember, integer division truncates the decimal portion.)
Thus, we have:
b = 3 + 1 = 4
*/
b = b % d + a / b;
a %= b; // This is the same as a = a % d, which is a = 24 % 4 = 0 (No remainder)
a -= 12; // Remember that this is the same as a = a - 12, which is a = 0-12 or -12.
Example Question #32 : Primitive Data Types
What is the Unicode value for the letter "W"?
U+005C
U+0057
U+007C
U+0047
U+0087
U+0057
The Unicode Standard is Java's attempt to simplify the translation of characters and symbols to input the computer can understand, while being able to work on all Java machines. The first 128 numbers (0-127, 0x0000-0x007F) are for basic Latin. Under this character encoding scheme, the letter 'W' is denoted by U+0057.
The standard for writing Unicode values is U+####, where the number is in hexadecimal format, not a base 10 number.
Example Question #82 : Computer Science
#include <iostream>
using namespace std;
int main()
{
bool bin=true;
int var=bin*2 +1;
int triple=5;
int final= (bin&var) &triple;
cout<<final;
return 0;
}
What is the output of this code?
2
0
1
3
false
1
Taking a look at the first line in main, the variable bin is defined as true, which we know to be 1. We see in the next line that the variable var is 2 * bin +1. The trick here is that you can actually do math with boolean values, so the value of var is 3.
The value of triple is 5.
The the variable final asks us to AND bin and var first, then AND triple.
To do this, we can convert all three numbers into binary notation to make it easier.
1 in binary is 001.
3 in binary is 011.
5 in binary is 101.
1&3 =1.
1&5=1.
Final answer is 1.
Example Question #3 : Evaluating Numerical Expressions
int x = 2893;
- What does the expression " x / 10 " evaluate to?
- What does the expression " x % 10 " evaluate to?
- 289.3
- 3
- 289
- 3
- 3
- 289
- 289.3
- 893
- 289
- 2000
- 289
- 3
-
2893 / 10 = 289, since x is an int, it does not store the decimal value
- 2893 % 10 = 3 because the remainder of 2893/10 is 3
Example Question #4 : Evaluating Numerical Expressions
int a;
a= 1+1 * 2 + 4 / 5;
System.out.println(a);
What would the code output?
2
3
3.8
0
2.4
3
The expression 1+1 * 2 + 4 / 5 can be rewritten as
1 + (1*2) + (4/5) = 1 + 2 + 0
4/5 = 0 because a is an int and when dividing ints, there are no decimals and since 4/5=0.8 we keep the ones digit which is zero.
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