Because this is a question about proportions, we know there's going to be one number divided by another number.  First, we're going to group our textbook length and height together:

$\displaystyle \frac{9.7ft}{6.9ft}$

As you can see, we choose to put the length of the moose in the numerator.  It doesn't matter if we put it in the numerator or the denominator yet.  When we group the height of the visible moose and it's length, we're going to put the length in the numerator because that's what we did for the textbook length:

$\displaystyle \frac{length}{5.8ft}$

Had we put the lengths in the denominators, that would have been fine (we just would have had an extra step when solving the problem).  Now we set our proportions equal to each other to get a final equation of:

$\displaystyle \frac{length}{5.8ft}=\frac{9.7ft}{6.9ft}$

It would help to first write out all our number with their units attached:

$\displaystyle \frac{4pepperionis}{slice}$

$\displaystyle \frac{8 slices}{pizza}$

$\displaystyle \frac{3}{4}pizza$

From here, we can use the units to cancel out until we have $\displaystyle \frac{pepperonis}{pizza}$:

$\displaystyle \frac{4pepperonis}{slice}\cdot\frac{8slices}{pizza}\cdot \frac{3pizza}{4pizza}$

Split the sentence into parts.

Twice a number:  $\displaystyle 2x$

Twice a number more than sixteen: $\displaystyle 2x+16$

Is forty:  $\displaystyle =40$

Combine the parts to form the equation.

The answer is:  $\displaystyle 2x+16=40$

Break up the sentence into parts.

Three times a number:  $\displaystyle 3x$

Five less than three times a number:  $\displaystyle 3x-5$

Is eight:  $\displaystyle =8$

Combine the parts to form the equation.

The answer is:  $\displaystyle 3x-5 =8$

Break up the sentence into parts.

The square root of a number:  $\displaystyle \sqrt{x}$

Three times the square root of a number:  $\displaystyle 3\sqrt{x}$

Six less than three times the square root of a number:  $\displaystyle 3\sqrt{x}-6$

Is four:  $\displaystyle =4$

Combine the parts to form the equation.

The answer is:  $\displaystyle 3\sqrt{x}-6=4$

The square root of a number:  $\displaystyle \sqrt{x}$

Twice the square root of a number:  $\displaystyle 2\sqrt{x}$

Four less than than twice the square root of a number:  $\displaystyle 2\sqrt{x}-4$

Is nine:  $\displaystyle =9$

Combine the parts to form the equation.

The answer is:  $\displaystyle 2\sqrt{x}-4=9$

Break up the sentence into parts.

Twice a number:  $\displaystyle 2x$

The fourth root of twice a number:  $\displaystyle \sqrt[4]{2x}$

Four times the fourth root of twice a number: $\displaystyle 4\sqrt[4]{2x}$

Is four:  $\displaystyle =4$

The answer is: $\displaystyle 4\sqrt[4]{2x} =4$

Break up the sentence into parts.

The square root of a number:  $\displaystyle \sqrt{x}$

The cube root of twice the number:  $\displaystyle \sqrt[3]{2x}$

The sum of the square root of a number and the cube root of twice the number:

$\displaystyle \sqrt{x}+\sqrt[3]{2x}$

Is seven:  $\displaystyle =7$

The answer is:  $\displaystyle \sqrt{x}+\sqrt[3]{2x} =7$

Break up the sentence into parts.

A fifth of a number squared:  $\displaystyle \frac{1}{5}x^2$

Two less than a fifth of a number squared:  $\displaystyle \frac{1}{5}x^2-2$

Is eighteen:  $\displaystyle =18$

Combine the parts to form the equation.

The answer is:  $\displaystyle \frac{1}{5}x^2-2=18$

Break up the sentence into parts.

Three times a number:  $\displaystyle 3x$

Fourth root of three times a number:  $\displaystyle \sqrt[4]{3x}$

Seven less than the fourth root of three times a number:  $\displaystyle \sqrt[4]{3x}-7$

Is nine:  $\displaystyle =9$

Combine the parts to form the equation.

The answer is:  $\displaystyle \sqrt[4]{3x}-7 = 9$