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Algebra II : Radicals

Study concepts, example questions & explanations for Algebra II

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Example Questions

Example Question #5 : Solving Radical Equations

Solve for x: $\sqrt{2x+1} = 11$

Possible Answers:

$\frac{\sqrt{11} + 1 }{2}$

240

$\sqrt{5}$

Correct answer:

Explanation:

To solve, perform inverse opperations, keeping in mind order of opperations:

$\sqrt{2x+1} = 11$ first, square both sides

2x + 1 = 121 subtract 1

2x = 120 divide by 2

x = 60

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Example Question #4 : Solving Radical Equations

Solve for x: $(\sqrt{x} + 19 )^2 = 10,000$

Possible Answers:

507.3158

1,899.5

9,999.999

6,561

Correct answer:

6,561

Explanation:

To solve, perform inverse opperations, keeping in mind order of opperations:

$(\sqrt x + 19 ) ^ 2 = 10,000$ take the square root of both sides

$\sqrt x + 19 = 100$ subtract 19 from both sides

$\sqrt{x } = 81$ square both sides

x = 6,561

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Example Question #1 : Solving And Graphing Radicals

Solve for x: $5\sqrt{x - 12 } = 20$

Possible Answers:

40.96

Correct answer:

Explanation:

To solve, use inverse opperations keeping in mind order of opperations:

$5\sqrt {x-12} = 20$ divide both sides by 5

$\sqrt{x-12 } = 4$ square both sides

x - 12 = 16 add 12 to both sides

x = 28

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Example Question #1 : Solving Radical Equations

Solve for .

$\sqrt{x}=4$

Possible Answers:

$\pm2$

Correct answer:

Explanation:

$\sqrt{x}=4$ To get rid of the radical, we square both sides.

x=4^2=16

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Example Question #2 : Solving Radical Equations

Solve for .

$\sqrt{x}=-5$

Possible Answers:

$\pm5$

No answer

$\pm25$

Correct answer:

No answer

Explanation:

To get rid of the radical, we need to square both sides. The issue is radicals don't generate negative numbers unless we talk about imaginary numbers. In this case, our answer choice should be no answer.

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Example Question #323 : Radicals

Solve for .

$\sqrt{x+1}=5$

Possible Answers:

Correct answer:

Explanation:

$\sqrt{x+1}=5$ Square both sides to get rid of the radical.

x+1=5^2=25 Subtract on both sides.

x=24

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Example Question #11 : Solving Radical Equations

Solve for .

$\sqrt{x-4}=7$

Possible Answers:

Correct answer:

Explanation:

$\sqrt{x-4}=7$ Square both sides to get rid of the radical.

x-4=7^2=49 Add on both sides.

x=53

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Example Question #321 : Radicals

Solve for .

$\sqrt{3x}=9$

Possible Answers:

Correct answer:

Explanation:

$\sqrt{3x}=9$ Square both sides to get rid of the radical.

3x=9^2=81 Divide on both sides.

x=27

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Example Question #326 : Radicals

Solve for .

$\sqrt{\frac{x}{2}}=8$

Possible Answers:

324

128

Correct answer:

128

Explanation:

$\sqrt{{\frac{x}{2}}{}}=8$ Square both sides to get rid of the radical.

$\frac{x}{2}=8^2=64$ Multiply on both sides.

x=128

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Example Question #327 : Radicals

Solve for .

$\sqrt{2x+3}=5$

Possible Answers:

Correct answer:

Explanation:

$\sqrt{2x+3}=5$ Square both sides to get rid of the radical.

2x+3=5^2=25 Subtract on both sides.

2x=22 Divide on both sides.

x=11

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Algebra II : Radicals

Study concepts, example questions & explanations for Algebra II

All Algebra II Resources

Example Questions

Example Question #5 : Solving Radical Equations

Example Question #4 : Solving Radical Equations

Example Question #1 : Solving And Graphing Radicals

Example Question #1 : Solving Radical Equations

Example Question #2 : Solving Radical Equations

Example Question #323 : Radicals

Example Question #11 : Solving Radical Equations

Example Question #321 : Radicals

Example Question #326 : Radicals

Example Question #327 : Radicals

All Algebra II Resources

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