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Algebra II : Logarithms

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Example Questions

Example Question #5 : Adding And Subtracting Logarithms

What is the value of (log_7343 + log_749)-log_72401 ?

Possible Answers:

Correct answer:

Explanation:

Remember the rules of logarithms:

log_ab + log_ac = log_abc

$log_pq - log_pr = log_p\frac{q}{r}$

This means we can simplify it as follows:

(log_7343 + log_749)-log_72401

$log_7(343\cdot 49) - log_72401$

log_716807 - log_72401

$log_7\frac{16807}{2401}$

log_77

The logarithm of anything with the same base is always , so the correct answer is .

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Example Question #1 : Adding And Subtracting Logarithms

Which of the following is another way to express

$\small \log (8)-\log(4)$ ?

Possible Answers:

$\small \log(\frac{1}{2})$

$\small \log(4)$

$\small \log(12)$

$\small \log (2)$

$\small \log (6)$

Correct answer:

$\small \log (2)$

Explanation:

Use the rule

$\small \log(a)-\log (b)=\log(\frac{a}{b})$

therefore

$\small \log (8)-\log(4)=\log(\frac{8}{4})=\log (2)$

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Example Question #3 : Adding And Subtracting Logarithms

Which is another way of expressing

$\small \log(4)+\log(5)$ ?

Possible Answers:

$\small \log(9)$

$\small \log(20)$

$\small \small \frac{\log (4)}{\log (5)}$

$\small \log(\frac{4}{5})$

$\small \log _{4}(5)$

Correct answer:

$\small \log(20)$

Explanation:

Use the rule:

$\small \log(a)+\log(b)=\log(a\times b)$

therefore

$\small \log (4)+\log (5)=\log (4\times 5)=\log (20)$

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Example Question #3 : Adding And Subtracting Logarithms

Simplify

log_5x-log_52y

Possible Answers:

$log_5\frac{2y}{x}$

2ylog_5x

log_5x2y

$log_5\frac{x}{2y}$

Correct answer:

$log_5\frac{x}{2y}$

Explanation:

This problem can be solved using the properties of logs. When two logs are being subtracted from each other, it is the same thing as dividing two logs together. Remember that to use this rule, the logs must have the same base in this case log_5 .

$log_5x-log_52y=log_5\frac{x}{2y}$

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Example Question #2 : Adding And Subtracting Logarithms

Condense this logarithm: $\frac{1}{2}\log_{10}x+3\log_{10}(x+1)$

Possible Answers:

$\log_{10}\left[\sqrt{x}+\log_{10}(x+1)^3\right]$

$\log_{10}\left[\sqrt{x}+3\log_{10}(x+1)\right]$

$\frac{1}{2}\log_{10}\left[x+\log_{10}(x+1)^3\right]$

$\log_{10}\left( \sqrt{x}+\sqrt{x+1}\right)$

$\log_{10}\left[\sqrt{x}(x+1)^3\right]$

Correct answer:

$\log_{10}\left[\sqrt{x}(x+1)^3\right]$

Explanation:

In order to solve this problem you must understand the product property of logarithms $\log_{10}uv=\log_{10}u+\log_{10}v$ and the power property of logarithms $\log_{10}u^n=n\log_{10}u$ . Note that these apply to logs of all bases not just base 10.

$\frac{1}{2}\log_{10}x+3\log_{10}(x+1)$

first move the constants in front of the logarithmic functions to their proper place using the power rule.

$\log_{10}x^{\frac{1}{2}}+\log_{10}(x+1)^3$

next factor out the logarithmic equation:

$\log_{10}[x^\frac{1}{2}+(x+1)^3]$

change the fractional exponent to a radical

$\log_{10}[\sqrt{x}(x+1)^3]$

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Example Question #1 : Adding And Subtracting Logarithms

Expand $log_{8}(\frac{15}{8})$

Possible Answers:

$log_{8}(15)-log_{8}(8)$

$log_8(15)\ast log_8(8)$

$\frac{log_8(15)}{log_8(8)}$

$log_{8}(15)+log_8(8)$

Correct answer:

$log_{8}(15)-log_{8}(8)$

Explanation:

The rule for expanding and dividing logarithms is that you can subtract the terms inside the log. In this case, the question is not asking for an actual number, but just what the expanded version would be. Therefore you separate the terms inside the log by subtracting the denominator from the numerator. Therefore the answer is

$log_{8}(15)-log_{8}(8)$

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Example Question #81 : Logarithms

Add the logarithms:

$log_{10}(2)+log_{10}(7)$

Possible Answers:

$log_{10}(12)$

$log_{10}(4)$

$log_{10}(9)$

$log_{10}(14)$

Correct answer:

$log_{10}(14)$

Explanation:

When adding logarithms of the same base, all you have to do is multiply the numbers inside the function as shown below:

$log_{10}(2)+log_{10}(7)$

$log_{10}(2*7)$

$log_{10}(14)$

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Example Question #82 : Logarithms

Add the logarithms:

$log_{10}(12)+log_{10}(3)$

Possible Answers:

$log_{10}(36)$

$log_{10}(15)$

$log_{10}(9)$

$log_{10}(16)$

Correct answer:

$log_{10}(36)$

Explanation:

When adding logarithms of the same base, all you have to do is multiply the numbers inside the function as shown below:

$log_{10}(12)+log_{10}(3)$

$log_{10}(12*3)$

$log_{10}(36)$

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Example Question #83 : Logarithms

Add the logarithms:

$log_{10}(5)+log_{10}(4)$

Possible Answers:

$log_{10}(20)$

$log_{10}(12)$

$log_{10}(2)$

$log_{10}(9)$

Correct answer:

$log_{10}(20)$

Explanation:

When adding logarithms of the same base, all you have to do is multiply the numbers inside the function as shown below:

$log_{10}(5)+log_{10}(4)$

$log_{10}(5*4)$

$log_{10}(20)$

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Example Question #84 : Logarithms

Subtract the logarithms:

$log_{10}(14)-log_{10}(2)$

Possible Answers:

$log_{10}(28)$

$log_{10}(3)$

$log_{10}(12)$

$log_{10}(7)$

Correct answer:

$log_{10}(7)$

Explanation:

When subtracting logarithms of the same base, all you have to do is divide the numbers inside the function as shown below:

$log_{10}(14)-log_{10}(2)$

$log_{10}(14\div 2)$

$log_{10}(7)$

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Algebra II : Logarithms

Study concepts, example questions & explanations for Algebra II

All Algebra II Resources

Example Questions

Example Question #5 : Adding And Subtracting Logarithms

Example Question #1 : Adding And Subtracting Logarithms

Example Question #3 : Adding And Subtracting Logarithms

Example Question #3 : Adding And Subtracting Logarithms

Example Question #2 : Adding And Subtracting Logarithms

Example Question #1 : Adding And Subtracting Logarithms

Example Question #81 : Logarithms

Example Question #82 : Logarithms

Example Question #83 : Logarithms

Example Question #84 : Logarithms

All Algebra II Resources

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