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Algebra II : Understanding Logarithms

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Example Questions

Example Question #2964 : Algebra Ii

Simplify, if possible: 2log(125)

Possible Answers:

5log(5)

6log(3)

10log(3)

6log(5)

$\textup{The answer is already simplified.}$

Correct answer:

6log(5)

Explanation:

Notice that the term in the log can be rewritten as a base raised to a certain power.

Rewrite the number in terms of base five.

2log(125)=2log(5^3)

According to log rules, the exponent can be dropped as a coefficient in front of the log.

$2\cdot 3log(5) = 6log(5)$

The answer is: 6log(5)

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Example Question #2965 : Algebra Ii

Solve: $3log_{5}(5^{10})$

Possible Answers:

1000

300

Correct answer:

Explanation:

Evaluate the log using the following property:

log_xx^y = y

The log based and the base of the term will simplify.

The expression becomes:

$3log_{5}(5^{10}) = 3(10) = 30$

The answer is:

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Example Question #61 : Logarithms

Try to answer without a calculator.

True or false:

$\log_{7} 700 = 2$

Possible Answers:

False

True

Correct answer:

False

Explanation:

By definition, $\log_{7} 700 = 2$ if and only if $7^{2} = 700$ . However,

$7^{2} = 7 \times 7 = 49 \ne 700$ ,

making this false.

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Example Question #64 : Understanding Logarithms

Try without a calculator:

Evaluate $\log_{16} 8$

Possible Answers:

$-\frac{3}{4}$

$\frac{4}{3}$

None of the other choices gives the correct response.

$\frac{3}{4}$

$-\frac{4}{3}$

Correct answer:

$\frac{3}{4}$

Explanation:

By definition, $\log_{16} 8 = N$ if and only if $16^{N} = 8$ .

8 and 16 are both powers of 2; specifically, $8= 2^{3} , 16 = 2^{4}$ . The latter equation can be rewritten as

$\left (2 ^{4} \right ) ^{N} = 2^{3}$

By the Power of a Power Property, the equation becomes

$2 ^{4\cdot N} = 2^{3}$

$2 ^{4N} = 2^{3}$

It follows that

4N = 3 ,

and

$N = \frac{3}{4}$ ,

the correct response.

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Example Question #2967 : Algebra Ii

Solve for (nearest tenth):

$\log_{7} N = 1.8$ .

Possible Answers:

2.9

12.6

61.2

33.2

Correct answer:

33.2

Explanation:

By definition, $\log_{a}N = M$ if and only if $a^{M}= N$ . Set a= 7, M = 1.8 , and

$\log_{7} N = 1.8$

if and only if

$N= 7^{1.8}$

Through calculation, we see that

$N \approx 33.2$ .

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Example Question #62 : Logarithms

Try to answer without a calculator:

Which is true about $\log_{0}1$ ?

Possible Answers:

Cannot be determined

$\log_{0}1 = 1$

$\log_{0}1 = 0$

$\log_{0}1$ is an undefined quantity

Correct answer:

$\log_{0}1$ is an undefined quantity

Explanation:

The question asks for the value of the "base 0 logarithm" of 0. However, this is not defined, as a logarithm can only have as its base a positive number not equal to 1.

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Example Question #2971 : Algebra Ii

Given the following:

$\log_{8} M = N$

Decide if the following expression is true or false:

$\log_{M} 8 = \frac{1}{N}$ for all positive .

Possible Answers:

True

False

Correct answer:

True

Explanation:

By definition of a logarithm,

$\log_{8} M = N$

if and only if

$8^{N } = M$

Take the th root of both sides, or, equivalently, raise both sides to the power of $\frac{1}{N}$ , and apply the Power of a Power Property:

$\left (8^{N } \right ) ^{\frac{1}{N}} = M ^{\frac{1}{N}}$

$8^{N \cdot \frac{1}{N} } = M ^{\frac{1}{N}}$

$8^{1 } = M ^{\frac{1}{N}}$

$M ^{\frac{1}{N}} = 8$

By definition, it follows that $\log_{M} 8 = \frac{1}{N}$ , so the statement is true.

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Example Question #2972 : Algebra Ii

$\log_{N }10 = M$ , with positive and not equal to 1.

Which of the following is true of $\log_{N }100$ for all such ?

Possible Answers:

$\log_{N }100 = \frac{M}{2}$

$\log_{N }100 = M + 2$

$\log_{N }100 = M + 1$

$\log_{N }100 = 2M$

$\log_{N }100 = M^{2}$

Correct answer:

$\log_{N }100 = 2M$

Explanation:

By definition,

$\log_{N }10 = M$

If and only if

$N^{M}= 10$

Square both sides, and apply the Power of a Power Property to the left expression:

$(N^{M})^{2}= 10^{2}$

$N^{M\cdot 2}= 100$

$N^{2M}= 100$

It follows that for all positive not equal to 1,

$\log_{N }100 = 2M$

for all .

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Example Question #2 : Logarithms

What is the value of that satisfies the equation $\log_x128=7$ ?

Possible Answers:

$\frac{1}{2}$

Correct answer:

Explanation:

$\log_xa=b$ is equivalent to x^b=a . In this case, you know the value of (the argument of a logarithmic equation) and b (the answer to the logarithmic equation). You must find a solution for the base.

$x^{7}=128$

$\sqrt[7]{x}=\sqrt[7]{128}$

x=2

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Algebra II : Understanding Logarithms

Study concepts, example questions & explanations for Algebra II

All Algebra II Resources

Example Questions

Example Question #2964 : Algebra Ii

Example Question #2965 : Algebra Ii

Example Question #61 : Logarithms

Example Question #64 : Understanding Logarithms

Example Question #2967 : Algebra Ii

Example Question #62 : Logarithms

Example Question #2971 : Algebra Ii

Example Question #2972 : Algebra Ii

Example Question #2 : Logarithms

All Algebra II Resources

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