To determine the mean, first the data set should be re-written in sequential order:

The formula to determine mean is:

The mean is approximately 3.37 runs scored per game.

Adding up the total number of grandparents that were born outside the U.S. is our first step in solving this problem.

There are 

people who said they had at least 1 grandparent born outside of the US. Of those, only 976 had exactly 3.

So 

 or  is the answer.

No - normally distributed data has a low frequency of responses at the high and low ends. Also, the majority of the data is in the middle.

In this data set, the majority of people said "0," and the fewest people said "3" which is near the middle of the data. If this data was normally distributed we would have a higher frequency between 1 and 3 and much lower values for 0 and 4.

Count the number of times each number appears in the data set.

The number 1 appears 4 times, so the first line is .

Then number 2 appears 7 times, so the next line is .

Continuing in this fashion we see that the numbers 3, 4, and 5 appears 5 times and 6 appears once.

Therefore combining these together we get the following answer:

The frequency table represents the data set:

1, 1, 1, 2, 2, 2, 2, 4, 4.

The sum is 19 and there are 9 data points, so the mean is

.

The frequency table represents the data set:

1, 1, 1, 2, 2, 2, 2, 4, 4.

The median is 2 because 4 data points appear before and after the center 2.

The correct frequency table represents the data set 3, 4, 5, 5, 6, 6, 8.

Since there are 7 data points our median will be the 4th spot which makes the value 5. It occures at the 4th spot because at that spot half the data points are below it while the other half are above it.

The center number of that data set is 5 as required.

To find the first and third quartile of the data set we first need to find the median of the data set. The median is the middle entry of the data set when entries are in ascending order therefore, the median is 10.

To find the first quartile, we need to break our data set into a subset that is between the first entry and the median. This set is:

Because the first quartile is the median of this subset we get the first quartile to equal 3.

The third quartile is found by taking the subset that is the median to the last entry of the data set. This subset is:

Because the third quartile is the median of the new subset we get the third quartile to equal 25.

{11, 14, 9, 2, 27, 26, 5, 8, 19, 10, 12, 6}

First, arrange the values in numerical order.

{2, 5, 6, 8, 9, 10, 11, 12, 14, 19, 26, 27}

Quartiles are the values that divide a set into four equal parts. Since this set has twelve values, "cut" the data after the 3rd and 9th value to find the 1st and 3rd quartile, respectively.

{2, 5, 6,| 8, 9, 10, 11, 12, 14,| 19, 26, 27}

The quartile will be the average of the values on either side of the "cut."

First Quartile = (6+8)/2=7

Third Quartile = (14+19)/2=16.5

{98, 55, 67, 88, 85, 91, 83, 65, 77, 83}

Rearrange the values in order.

{55, 65, 67, 77, 83, 83, 85, 88, 91, 98}

To get quartiles, "cut" the data into four.

{55, 65, 6|7, 77, 83,| 83, 85, 8|8, 91, 98}

As you can see, the third "cut" is right at 88. Which means 88 is the cutoff for the top quartile based on this set of data.