Call Now to Set Up Tutoring:

(888) 888-0446

Algebra II : Equations

Study concepts, example questions & explanations for Algebra II

Create An Account

All Algebra II Resources

10 Diagnostic Tests 630 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #61 : Solving Equations

Solve for x: bx-cx=x-2

Possible Answers:

$x=\frac{-2}{b-c-1}$

$x=\frac{b-c-1}{2}$

Cannot be solved

$x=\frac{-1}{b-c}$

$x=\frac{b-c-1}{-2}$

Correct answer:

$x=\frac{-2}{b-c-1}$

Explanation:

bx-cx=x-2

Subtract to move all x terms to the same side:

bx-cx-x=-2

Factor out an x:

x(b-c-1)=-2

Divide to isolate x completely:

$\mathbf{x=\frac{-2}{b-c-1}}$

Report an Error

Example Question #71 : Solving Equations

Solve for x: $\sqrt{2x-4x}=\sqrt{x-2}$

Possible Answers:

$x=\frac{3}{2}$

x=-2

$x=\frac{2}{3}$

x=2

x=1

Correct answer:

$x=\frac{2}{3}$

Explanation:

$\sqrt{2x-4x}=\sqrt{x-2}$

Square both sides to remove the radicals:

2x-4x=x-2

Combine x terms:

-2x=x-2

Combine x terms to one side by subtracting:

-3x=-2

Isolate x completely:

$x=\frac{2}{3}$

Report an Error

Example Question #72 : Solving Equations

Find the solution to the following equation.

9x+23=59

Possible Answers:

x=4

x=36

x=40.5

x=-4

Correct answer:

x=4

Explanation:

Find the solution to the following equation.

9x+23=59

To find the solution of this equation, we need to find the value for x, which makes the given equation true.

We do this by working backwards and manipulating the equation.

The easiest first step would probably be to subtract 23 from both sides:

9x+23(-23)=59(-23)

By doing so, we can simplify the equation to get:

9x=36

Next, simply divide both sides by 9 to get the answer!

$9x\div 9=36\div9$

So we get:

x=4

Report an Error

Example Question #2391 : Algebra Ii

Given the following equation, find the value of

355=7b+12

Possible Answers:

343

117649

Correct answer:

117649

Explanation:

Given the following equation, find the value of

355=7b+12

To find the value of , we first need to find the value of b

Let's begin by subtracting 12

355(-12)=7b+12(-12)

Simplify

343=7b

Finally, divide by 7

$b=\frac{343}{7}=49$

But, we need

So:

b^3=49^3=117649

Report an Error

Example Question #201 : Equations

27x-9=-18

Possible Answers:

$x=-\frac{1}{3}$

None of these

x=3

x=-3

$x=\frac{1}{3}$

Correct answer:

$x=-\frac{1}{3}$

Explanation:

27x-9=-18

Add 9 to both sides:

27x=-9

Divide both sides by 27:

$\mathbf{x=-\frac{1}{3}}$

Report an Error

Example Question #201 : Equations

27x-9=-18

Possible Answers:

$x=-\frac{1}{3}$

None of these

x=3

x=-3

$x=\frac{1}{3}$

Correct answer:

$x=-\frac{1}{3}$

Explanation:

27x-9=-18

Add 9 to both sides:

27x=-9

Divide both sides by 27:

$\mathbf{x=-\frac{1}{3}}$

Report an Error

Example Question #75 : Solving Equations

I sell bagels for cents plus ten cents for the bag it comes in. How many bagels can u buy if you brought $ 3.35 ?

Possible Answers:

Correct answer:

Explanation:

Let's set-up an equation.

.25x+.10=3.35 represents the amount of bagels. After subtracting on both sides and dividing by 0.25 , our answer should be bagels.

Report an Error

Example Question #2393 : Algebra Ii

Bob rides in a NYC taxi in which the opening fare is $ 2.00 . The taxi charges cents for every $\frac{1}{5}$ of a mile. How far did Bob go if the fare costs $ 21.80 ?

Possible Answers:

14.6

13.2

12.8

Correct answer:

13.2

Explanation:

Let's set-up an equation.

2+0.3x=21.80 how many fifth miles the taxi charges. After subtracting on both sides and dividing by 0.3 , our answer should be . But of course, this is not the final answer because that's how many times the taxi charges for every fifth mile. So $66*\frac{1}{5}=13.2$ miles.

Report an Error

Example Question #77 : Solving Equations

A gas tank holds gallons. A car uses $\frac{1}{40}$ of a gallon per mile. How many gallons is left if the person travelled 600 miles?

Possible Answers:

Correct answer:

Explanation:

Since the person has traveled 600 miles and each mile uses $\frac{1}{40}$ gallon, we can determine how many gallons used. $\frac{600}{40}=15$ gallons used. Since a tank holds gallons, we subtract and to get gallons.

Report an Error

Example Question #211 : Equations

Josh weighs 300 pounds. He goes on a diet and loses pounds every days. How long does it take for him to drop to 180 pounds?

Possible Answers:

120

300

360

Correct answer:

300

Explanation:

Let's set-up an equation.

300-2x=180 represents how many times he lost the pounds. By subtracting 300 on both sides and dividing by later, we get . That's not our answer as he loses weight every five days. So we do 60*5=300 days.

Report an Error

View Algebra 2 Tutors

Travis
Certified Tutor

Delaware State University, Bachelor of Science, Mathematics.

View Algebra 2 Tutors

Sharon
Certified Tutor

Tabor College, Bachelor of Science, Mathematics Teacher Education. Tabor College, Masters in Education, Education.

View Algebra 2 Tutors

Abhisek
Certified Tutor

University of Florida, Bachelor of Engineering, Computer Science.

All Algebra II Resources

10 Diagnostic Tests 630 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Physics Tutors in Denver, Statistics Tutors in Denver, Biology Tutors in Seattle, Computer Science Tutors in Chicago, Chemistry Tutors in Phoenix, GMAT Tutors in San Francisco-Bay Area, ACT Tutors in Seattle, LSAT Tutors in Washington DC, GMAT Tutors in Phoenix, Spanish Tutors in San Diego

Popular Courses & Classes

SAT Courses & Classes in Miami, GRE Courses & Classes in Dallas Fort Worth, LSAT Courses & Classes in Seattle, SSAT Courses & Classes in Atlanta, GRE Courses & Classes in Seattle, ISEE Courses & Classes in Phoenix, ACT Courses & Classes in San Diego, SAT Courses & Classes in Los Angeles, Spanish Courses & Classes in San Diego, LSAT Courses & Classes in Houston

Popular Test Prep

GMAT Test Prep in Phoenix, GRE Test Prep in Atlanta, MCAT Test Prep in San Francisco-Bay Area, ACT Test Prep in Houston, ACT Test Prep in Seattle, GRE Test Prep in Denver, LSAT Test Prep in Denver, ISEE Test Prep in Miami, GMAT Test Prep in Houston, GRE Test Prep in Houston

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Algebra II : Equations

Study concepts, example questions & explanations for Algebra II

All Algebra II Resources

Example Questions

Example Question #61 : Solving Equations

Example Question #71 : Solving Equations

Example Question #72 : Solving Equations

Example Question #2391 : Algebra Ii

Example Question #201 : Equations

Example Question #201 : Equations

Example Question #75 : Solving Equations

Example Question #2393 : Algebra Ii

Example Question #77 : Solving Equations

Example Question #211 : Equations

All Algebra II Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: