Algebra II : Algebra II

Study concepts, example questions & explanations for Algebra II

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Example Questions

Example Question #42 : Solving And Graphing Logarithms

Solve 

Possible Answers:

Correct answer:

Explanation:

Rearranging the logarithm so that we exchange an exponent for the log we get:

Example Question #43 : Solving And Graphing Logarithms

Solve .

Possible Answers:

Correct answer:

Explanation:

First we rearrange the equation, trading the logarithm for an exponent:

And then we solve:

Example Question #3093 : Algebra Ii

Solve .

Possible Answers:

Correct answer:

Explanation:

The first thing we can do is combine the log terms:

Now we can change to exponent form:

We can combine terms and set the equation equal to  to have a quadratic equation:

We then solve the equation and get the answers:

 and 

 can't be an answer, because the values inside a log can't be negative, so that leaves us with a single answer of .

Example Question #3093 : Algebra Ii

Solve .

Possible Answers:

Correct answer:

Explanation:

The first thing we can do is combine log terms:

Simplifying the log term gives:

Now we can change the equation to exponent form:

And to solve:

Here, the solution can't be  because the term inside a logarithm can't be negative, so the only solution is .

Example Question #3094 : Algebra Ii

Solve 

Possible Answers:

Correct answer:

Explanation:

First, let's change the equation to exponent form:

Then simplify:

And solve:

Both answers are valid because  in the original equation is squared, so any negative numbers don't cause the logarithm to become negative.

Example Question #3095 : Algebra Ii

Solve 

Possible Answers:

Correct answer:

Explanation:

We can start by getting both the log terms on the same side of the equation:

Then we combine log terms:

Now we can change to exponent form:

Anything raised to the th power equals , and from here it becomes a simpler problem to solve:

Example Question #3096 : Algebra Ii

Solve 

Possible Answers:

Correct answer:

Explanation:

First we're going to get all the natural logs on one side of the equation:

Next, we're going to combine all the terms into one natural log:

Now we can change to exponent form:

Anything raised to the th power equals , which helps us simplify:

From here, we can factor and solve:

We have to notice, however, that  isn't a valid answer because if we were to plug it into the original formula we would have a negative value in a logarithm. 

Example Question #3097 : Algebra Ii

Solve .

Possible Answers:

Correct answer:

Explanation:

The first thing we can do is write the coefficients in front of the logs as exponents of the terms inside the logs:

Next, we combine the logs:

Now we can change the equation into exponent form:

When we simplify, we'll also move all the terms to one side of the equation:

From here, we factor to get our solutions:

The last thing we have to do is check our answers.   doesn't raise any problems, but  does.  If we plug it back into the original equation, we would be evaluating a negative value in a log, which we can't do.

Example Question #3098 : Algebra Ii

Solve:  

Possible Answers:

Correct answer:

Explanation:

In order to solve for the logs, we will need to write the log properties as follows:

 and 

This means that:

Replace the values into the expression.

The answer is:  

Example Question #3099 : Algebra Ii

Solve 

Possible Answers:

Correct answer:

Explanation:

First, we rewrite the equation as:

We can use log properties to simplify:

From here, simple algebra is used to solve:

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