Add the ones digits.

$\displaystyle 9+1+2 =12$

The carryover is the tens place.

Add the tens digits.

$\displaystyle 1+4+4+(1) = 10$

The carryover for the next calculation is the tens place.

$\displaystyle 4+8+5+(1) = 18$

Combine this number with the ones digits of the previous calculations.

The answer is:  $\displaystyle 1802$

Add the ones digits.

$\displaystyle 4+1=5$

There is no carryover.

Add the tens digits.

$\displaystyle 6+1=7$

There is also no carryover.

Add the hundreds digits.

$\displaystyle 2+8 = 10$

The carryover is the tens digit.

Add the thousands digits with the carryover.

$\displaystyle 1+9+(1) = 11$

Combine this value with the ones digits of the previous calculations.

The answer is:  $\displaystyle 11075$

Add the ones digits.

$\displaystyle 9+4 = 13$

The carryover is the tens digit.

Add the tens digits with the carryover.

$\displaystyle 7+5+(1) =13$

The carryover is the tens digit.

$\displaystyle 8+6+(1) =15$

Combine this value with the one digits of the previous calculations.

The answer is:  $\displaystyle 1533$

Add the ones digits.

$\displaystyle 8+9+7 = 24$

Carry over the tens digit to the next calculation.

Add the tens digits with the carryover.

$\displaystyle 1+1+9+(2) = 13$

Repeat the process for the hundreds digits.

$\displaystyle 3+2+7+(1) = 13$

Combine this number with the ones digits of the previous calculations.

The answer is:  $\displaystyle 1334$

Add the ones digits.

$\displaystyle 9+1+9+4+9 = 32$

Add the tens digit with the carryover, 3.

$\displaystyle 4+8+7+2+9+(3) = 33$

Combine this number with the ones digit of the first number.

The answer is:  $\displaystyle 332$

We cannot subtract the numbers like how we can easily add numbers.  As a result, we will have to subtract each number at a time and this may be time consuming.

However, in order to save calculation time, we can simply take out a common factor of negative one so that we can add all the positive terms, and then subtract. 

$\displaystyle 95-15-85-87-31 = -1(-95+[15+85+87+31])$

$\displaystyle = -1(-95+[218])$

We can then rearrange the numbers to subtract.

$\displaystyle -1(218-95)$

Subtract the ones digits.

$\displaystyle 8-5 = 3$

Borrow a one from the 2 in 218 and then subtract the tens digits.  The hundreds digit becomes a 1.

$\displaystyle 11-9 = 2$

Combine the hundreds digit with the other ones digits.  The expression becomes:

$\displaystyle -1(218-95) = -1(123) = -123$

The answer is:  $\displaystyle -123$

Add the ones digits.

$\displaystyle 4+6+3=13$

Add the tens digits with the one as the carryover.

$\displaystyle 7+1+6+(1)=15$

Add the hundreds digits with the new carryover.

$\displaystyle 9+3+1+(1) =14$

Combine this number with the ones digits of the previous numbers.

The answer is:  $\displaystyle 1453$

Add the ones digits.

$\displaystyle 4+8+2 = 14$

Add the tens digits with the one as the carryover.

$\displaystyle 7+7+9+(1)= 24$

Add the hundreds digits with the two as the carryover.

$\displaystyle 9+9+1+(2) = 21$

Combine this number with the ones digits of the previous calculations.

The answer is:  $\displaystyle 2144$

Add the ones digits.

$\displaystyle 4+4+1= 9$

Add the tens digits.  There is no carryover.

$\displaystyle 4+9+1 = 14$

Add the hundreds digits.   The carryover is 1.

$\displaystyle 6+4+9+(1) = 20$

Combine this number with the ones digits of the previous calculations.

The answer is:  $\displaystyle 2049$

Add the ones digits.

$\displaystyle 6+6+7 = 19$

Add the tens digits with the 1 as the carryover.

Add the tens digits.

$\displaystyle 5+9+7+(1) = 22$

Add the hundreds digits with the 2 as the carryover.

$\displaystyle 8+1+8+(2) = 19$

Combine this value with the ones digits of the first two calculations.

The answer is:  $\displaystyle 1929$