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Algebra 1 : Linear Equations

Study concepts, example questions & explanations for Algebra 1

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10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #189 : How To Solve Two Step Equations

Solve for .

$\frac{x}{-4}-12=-38$

Possible Answers:

200

140

104

Correct answer:

104

Explanation:

$\frac{x}{-4}-12=-38$ Add on both sides. Since is greater than and is negative, our answer is negative. We treat as a normal subtraction.

$\frac{x}{-4}=-26$ Multiply on both sides. When multiplying with another negative number, our answer is positive.

x=104

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Example Question #190 : How To Solve Two Step Equations

Solve for .

$\frac{x}{5}+6=36$

Possible Answers:

130

150

125

Correct answer:

150

Explanation:

In order to solve for , you first must get it by itself on one side of the equal sign using opposite operations. Whatever you do to one side of the equation you must do to the other. In the case of:

$\frac{x}{5}+6=36$

You first subtract from both sides of the equation.

$\frac{x}{5}+6-6=36-6$

Giving you,

$\frac{x}{5}=30$

Next, you multiply each side of the equation by .

$\frac{x}{5}\times5=30\times5$

Solve.

x=150

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Example Question #721 : Algebra 1

Solve for

$\frac{a}{15}-21=-15$

Possible Answers:

115

Correct answer:

Explanation:

In order to solve for , you first must get it by itself on one side of the equal sign using opposite operations. Whatever you do to one side of the equation you must do to the other. In the case of:

$\frac{a}{15}-21=-15$

You first must add to both sides of the equation.

$\frac{a}{15}-21+21=-15+21$

Giving you,

$\frac{a}{15}=6$

Next, multiply both sides of the equation by ,

$\frac{a}{15}\times15=6\times15$

Solve.

a=90

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Example Question #722 : Algebra 1

Solve for .

5x-24=66

Possible Answers:

Correct answer:

Explanation:

In order to solve for , you first must get it by itself on one side of the equal sign using opposite operations. Whatever you do to one side of the equation you must do to the other. In the case of:

5x-24=66

You first must add to both sides of the equation.

5x-24+24=66+24

Giving you,

5x=90

Then you divide each side of the equation by .

$\frac{5x}{5}=\frac{90}{5}$

Solve.

x=18

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Example Question #723 : Algebra 1

Solve for .

14x+14=210

Possible Answers:

Correct answer:

Explanation:

In order to solve for , you first must get it by itself on one side of the equal sign using opposite operations. Whatever you do to one side of the equation you must do to the other. In the case of:

14x+14=210

You must first subrtract from both sides of the equation.

14x+14-14=210-14

Giving you,

14x=196

Now, divide each side of the equation by .

$\frac{14x}{14}=\frac{196}{14}$

Solve.

x=14

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Example Question #724 : Algebra 1

Solve for .

12x+7=67

Possible Answers:

Correct answer:

Explanation:

In order to solve for , you first must get it by itself on one side of the equal sign using opposite operations. Whatever you do to one side of the equation you must do to the other. In the case of:

12x+7=67

You first must subtract from both sides of the equation.

12x+7-7=67-7

Giving you,

12x=60

Now, divide each side of the equation by .

$\frac{12x}{12}=\frac{60}{12}$

Solve.

x=5

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Example Question #191 : How To Solve Two Step Equations

Solve for .

9b-37=62

Possible Answers:

Correct answer:

Explanation:

In order to solve for , you first must get it by itself on one side of the equal sign using opposite operations. Whatever you do to one side of the equation you must do to the other. In the case of:

9b-37=62

You first must add to both sides of the equation.

9b-37+37=62+37

Giving you,

9b=99

Next, divide each side of the equation by 9.

$\frac{9b}{9}=\frac{99}{9}$

Solve.

b=11

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Example Question #726 : Algebra 1

Solve for .

$\frac{3}{4}b+17=62$

Possible Answers:

100

Correct answer:

Explanation:

In order to solve for , you first must get it by itself on one side of the equal sign using opposite operations. Whatever you do to one side of the equation you must do to the other. In the case of:

$\frac{3}{4}b+17=62$

You first must subtract from both sides of the equation.

$\frac{3}{4}b+17-17=62-17$

Giving you,

$\frac{3}{4}b=45$

Now, divide each side of teh equation by $\frac{3}{4}$ .

$\frac{3}{4}b\div \frac{3}{4}=45\div \frac{3}{4}$

Remember that dividing by a fraction is the same as multiplying by its reciprocal. Rewrite.

$\frac{3}{4}b\times \frac{4}{3}=45\times \frac{4}{3}$

Solve.

b=60

Report an Error

Example Question #727 : Algebra 1

Solve for .

$\frac{a}{13}-57=-41$

Possible Answers:

230

208

156

265

Correct answer:

208

Explanation:

In order to solve for , you first must get it by itself on one side of the equal sign using opposite operations. Whatever you do to one side of the equation you must do to the other. In the case of:

$\frac{a}{13}-57=-41$

You first must add to both sides of the equation.

$\frac{a}{13}-57+57=-41+57$

Giving you,

$\frac{a}{13}=16$

Now, multiply each side of the equation by .

$\frac{a}{13}\times13=16\times13$

Solve.

a=208

Report an Error

Example Question #728 : Algebra 1

Solve for .

$\frac{b}{25}+47=76$

Possible Answers:

1025

650

875

475

725

Correct answer:

725

Explanation:

In order to solve for , you first must get it by itself on one side of the equal sign using opposite operations. Whatever you do to one side of the equation you must do to the other. In the case of:

$\frac{b}{25}+47=76$

You first must subtract from both sides of the equation.

$\frac{b}{25}+47-47=76-47$

Giving you,

$\frac{b}{25}=29$

Now, mulitiply each side of the equation by .

$\frac{b}{25}\times25=29\times25$

Solve.

b=725

Report an Error

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Algebra 1 : Linear Equations

Study concepts, example questions & explanations for Algebra 1

All Algebra 1 Resources

Example Questions

Example Question #189 : How To Solve Two Step Equations

Example Question #190 : How To Solve Two Step Equations

Example Question #721 : Algebra 1

Example Question #722 : Algebra 1

Example Question #723 : Algebra 1

Example Question #724 : Algebra 1

Example Question #191 : How To Solve Two Step Equations

Example Question #726 : Algebra 1

Example Question #727 : Algebra 1

Example Question #728 : Algebra 1

All Algebra 1 Resources

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