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Algebra 1 : Linear Equations

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10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #91 : How To Solve One Step Equations

Veronica works as a computer programmer who makes $\$120$ per hour. How many hours does she have to work in order to earn $\$1920$ ?

Possible Answers:

Correct answer:

Explanation:

Let be the number of hours Veronica must work.

Since we know that she is paid $\$120$ per hour, we can write the following equation:

120x=1920

To solve for , divide both sides by 120 .

$120x\div120=1920\div120$

x=16

Veronica needs to work for hours to earn $\$1920$ .

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Example Question #92 : How To Solve One Step Equations

After spending $\$45.10$ on groceries, Jimmy has $\$3.66$ remaining. How much money did Jimmy have before buying groceries?

Possible Answers:

$\$45.12$

$\$49.10$

$\$41.34$

$\$48.76$

Correct answer:

$\$48.76$

Explanation:

Let be the amount Jimmy had before buying groceries.

Since we know that he spent $\$45.10$ on groceries, we can write the following equation:

x-45.10=3.66

To solve for , add 45.10 to both sides of the equation.

x-45.10+45.10=3.66+45.10

x=48.76

Jimmy had $\$48.76$ before buying groceries.

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Example Question #93 : Linear Equations

Solve for :

3x=-9

Possible Answers:

x=-3

x=-2

x=3

x=2

Correct answer:

x=-3

Explanation:

To solve for , you will need to get on its own. To do so, divide both sides by .

3x=-9

$\frac{3x}{3}=\frac{-9}{3}$

x=-3

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Example Question #91 : Algebra 1

Solve for :

$4x=\frac{1}{2}$

Possible Answers:

$x=\frac{1}{6}$

x=2

$x=\frac{1}{8}$

x=8

Correct answer:

$x=\frac{1}{8}$

Explanation:

To solve for , you will need to get on its own. To do so, divide both sides by .

$4x=\frac{1}{2}$

$4x\div4=\frac{1}{2}\div4=\frac{1}{2}\times\frac{1}{4}$

$x=\frac{1}{8}$

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Example Question #92 : Algebra 1

Solve for :

$-5x=\frac{1}{3}$

Possible Answers:

x=-15

$x=-\frac{1}{15}$

$x=\frac{5}{3}$

$x=-\frac{3}{5}$

Correct answer:

$x=-\frac{1}{15}$

Explanation:

To solve for , you will need to get on its own. To do so, divide both sides by .

$-5x=\frac{1}{3}$

$-5x\div -5=\frac{1}{3}\div -5=\frac{1}{3}\times-\frac{1}{5}$

$x=-\frac{1}{15}$

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Example Question #93 : How To Solve One Step Equations

Catherine spends more hours practicing basketball every week than Michael does. If Catherine spent hours practicing basketball this week, how many hours did Michael practice baksetball?

Possible Answers:

Correct answer:

Explanation:

Let be the number of hours Michael spends practicing.

We know from the question that Catherine spends more hours practicing. We can then write the following expression to show the number of hours Catherine spends practicing in terms of :

x+4

Since we also know that Catherine spent hours practicing, we can then write the following equation:

x+4=15

To solve for , subtract from both sides.

x+4-4=15-4

x=11

Michael spent hours practicing basketball.

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Example Question #97 : Linear Equations

Solve for :

x+9=8

Possible Answers:

x=-1

x=1

x=8

x=17

Correct answer:

x=-1

Explanation:

In order to solve for , subtract from both sides of the equation.

x+9=8

x+9-9=8-9

x=-1

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Example Question #98 : Linear Equations

Solve for :

y-6=9

Possible Answers:

y=15

y=3

y=-6

y=-3

Correct answer:

y=15

Explanation:

In order to solve for , you will need to add to both sides of the equation.

y-6=9

y-6+6=9+6

y=15

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Example Question #99 : Linear Equations

Solve for :

$y-\frac{1}{2}=-2$

Possible Answers:

y=-1

$y=-\frac{3}{2}$

y=2

$y=-\frac{1}{2}$

Correct answer:

$y=-\frac{3}{2}$

Explanation:

In order to solve for , you will need to add $\frac{1}{2}$ to both sides of the equation.

$y-\frac{1}{2}=-2$

$y-\frac{1}{2}+\frac{1}{2}=-2+\frac{1}{2}$

$y=-\frac{4}{2}+\frac{1}{2}$

$y=-\frac{3}{2}$

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Example Question #100 : Linear Equations

Solve for :

y-0.8=1

Possible Answers:

y=-0.2

y=1.5

y=1.8

y=0.4

Correct answer:

y=1.8

Explanation:

In order to solve for , add 0.8 to both sides of the equation.

y-0.8=1

y-0.8+0.8=1+0.8

y=1.8

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Algebra 1 : Linear Equations

Study concepts, example questions & explanations for Algebra 1

All Algebra 1 Resources

Example Questions

Example Question #91 : How To Solve One Step Equations

Example Question #92 : How To Solve One Step Equations

Example Question #93 : Linear Equations

Example Question #91 : Algebra 1

Example Question #92 : Algebra 1

Example Question #93 : How To Solve One Step Equations

Example Question #97 : Linear Equations

Example Question #98 : Linear Equations

Example Question #99 : Linear Equations

Example Question #100 : Linear Equations

All Algebra 1 Resources

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