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Algebra 1 : Linear Equations

Study concepts, example questions & explanations for Algebra 1

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10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #61 : Linear Equations

Solve for $\displaystyle x$.

x+5=9 $\displaystyle x+5=9$

Possible Answers:

x=-2 $\displaystyle x=-2$

x=14 $\displaystyle x=14$

x=4 $\displaystyle x=4$

x=11 $\displaystyle x=11$

Correct answer:

x=4 $\displaystyle x=4$

Explanation:

In order to solve for $\displaystyle x$, we want to isolate it on one side of the equation.

x+5=9 $\displaystyle x+5=9$

Subtract $\displaystyle 5$ from both sides.

$\displaystyle x+5-5=9-5$

x=4 $\displaystyle x=4$

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Example Question #61 : Algebra 1

Solve for $\displaystyle x$.

-6+x=10 $\displaystyle -6+x=10$

Possible Answers:

x=8 $\displaystyle x=8$

x=2 $\displaystyle x=2$

x=16 $\displaystyle x=16$

x=4 $\displaystyle x=4$

Correct answer:

x=16 $\displaystyle x=16$

Explanation:

In order to solve for $\displaystyle x$, we want to isolate it on one side of the equation.

-6+x=10 $\displaystyle -6+x=10$

Add $\displaystyle 6$ to both sides of the equation.

$\displaystyle 6-6+x=10+6$

x=16 $\displaystyle x=16$

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Example Question #61 : How To Solve One Step Equations

Solve for $\displaystyle x$.

-3+x=5 $\displaystyle -3+x=5$

Possible Answers:

x=15 $\displaystyle x=15$

x=-2 $\displaystyle x=-2$

x=8 $\displaystyle x=8$

x=2 $\displaystyle x=2$

Correct answer:

x=8 $\displaystyle x=8$

Explanation:

In order to solve for $\displaystyle x$, we want to isolate it on one side of the equation.

-3+x=5 $\displaystyle -3+x=5$

Add $\displaystyle 3$ to both sides of the equation.

$\displaystyle 3-3+x=3+5$

x=8 $\displaystyle x=8$

Report an Error

Example Question #61 : Algebra 1

Solve for $\displaystyle x$:

x-16=-9 $\displaystyle x-16=-9$

Possible Answers:

x=-26 $\displaystyle x=-26$

x=7 $\displaystyle x=7$

x=10 $\displaystyle x=10$

x=-7 $\displaystyle x=-7$

Correct answer:

x=7 $\displaystyle x=7$

Explanation:

In order to solve for $\displaystyle x$, we want to isolate it on one side of the equation.

x-16=-9 $\displaystyle x-16=-9$

Add $\displaystyle 16$ to both sides of the equation.

$\displaystyle x-16+16=-9+16$

x=7 $\displaystyle x=7$

Report an Error

Example Question #65 : Algebra 1

Solve for $\displaystyle x$:

x+2=-5 $\displaystyle x+2=-5$

Possible Answers:

x=4 $\displaystyle x=4$

x=7 $\displaystyle x=7$

x=-7 $\displaystyle x=-7$

x=-3 $\displaystyle x=-3$

Correct answer:

x=-7 $\displaystyle x=-7$

Explanation:

In order to solve for $\displaystyle x$, we want to isolate it on one side of the equation.

x+2=-5 $\displaystyle x+2=-5$

Subtract $\displaystyle 2$ from both sides.

$\displaystyle x+2-2=-5-2$

x=-7 $\displaystyle x=-7$

Report an Error

Example Question #62 : Algebra 1

Solve for $\displaystyle x$:

18+x=26 $\displaystyle 18+x=26$

Possible Answers:

x=44 $\displaystyle x=44$

x=-8 $\displaystyle x=-8$

x=21 $\displaystyle x=21$

x=8 $\displaystyle x=8$

Correct answer:

x=8 $\displaystyle x=8$

Explanation:

In order to solve for $\displaystyle x$, we want to isolate it on one side of the equation.

18+x=26 $\displaystyle 18+x=26$

Subtract $\displaystyle 18$ from both sides.

$\displaystyle 18-18+x=26-18$

x=8 $\displaystyle x=8$

Report an Error

Example Question #61 : Linear Equations

Solve for $\displaystyle x$:

5x=15 $\displaystyle 5x=15$

Possible Answers:

x=75 $\displaystyle x=75$

x=5 $\displaystyle x=5$

x=2 $\displaystyle x=2$

x=3 $\displaystyle x=3$

Correct answer:

x=3 $\displaystyle x=3$

Explanation:

In order to solve for $\displaystyle x$, we want to isolate it on one side of the equation.

5x=15 $\displaystyle 5x=15$

Divide both sides by $\displaystyle 5$.

$\frac{5x}{5}=\frac{15}{5}$ $\displaystyle \frac{5x}{5}=\frac{15}{5}$

x=3 $\displaystyle x=3$

Report an Error

Example Question #61 : How To Solve One Step Equations

Solve for $\displaystyle x$:

14x=224 $\displaystyle 14x=224$

Possible Answers:

x=18 $\displaystyle x=18$

x=12 $\displaystyle x=12$

x=14 $\displaystyle x=14$

x=16 $\displaystyle x=16$

Correct answer:

x=16 $\displaystyle x=16$

Explanation:

In order to solve for $\displaystyle x$, we want to isolate it on one side of the equation.

14x=224 $\displaystyle 14x=224$

Divide both sides by $\displaystyle 14$.

$\frac{14x}{14}=\frac{224}{14}$ $\displaystyle \frac{14x}{14}=\frac{224}{14}$

x=16 $\displaystyle x=16$

Report an Error

Example Question #61 : Linear Equations

Solve for $\displaystyle x$:

7x=126 $\displaystyle 7x=126$

Possible Answers:

x=20 $\displaystyle x=20$

x=16 $\displaystyle x=16$

x=12 $\displaystyle x=12$

x=18 $\displaystyle x=18$

Correct answer:

x=18 $\displaystyle x=18$

Explanation:

In order to solve for $\displaystyle x$, we want to isolate it on one side of the equation.

7x=126 $\displaystyle 7x=126$

Divide both sides by $\displaystyle 7$.

$\frac{7x}{7}=\frac{126}{7}$ $\displaystyle \frac{7x}{7}=\frac{126}{7}$

x=18 $\displaystyle x=18$

Report an Error

Example Question #69 : Algebra 1

Solve for $\displaystyle x$:

$\frac{x}{6}=-2$ $\displaystyle \frac{x}{6}=-2$

Possible Answers:

x=-3 $\displaystyle x=-3$

x=-12 $\displaystyle x=-12$

x=-2 $\displaystyle x=-2$

x=-4 $\displaystyle x=-4$

Correct answer:

x=-12 $\displaystyle x=-12$

Explanation:

In order to solve for $\displaystyle x$, we want to isolate it on one side of the equation.

$\frac{x}{6}=-2$ $\displaystyle \frac{x}{6}=-2$

Multiply both sides by $\displaystyle 6$.

$6\times\frac{x}{6}=-2\times6$ $\displaystyle 6\times\frac{x}{6}=-2\times6$

x=-12 $\displaystyle x=-12$

Report an Error

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Algebra 1 : Linear Equations

Study concepts, example questions & explanations for Algebra 1

All Algebra 1 Resources

Example Questions

Example Question #61 : Linear Equations

Example Question #61 : Algebra 1

Example Question #61 : How To Solve One Step Equations

Example Question #61 : Algebra 1

Example Question #65 : Algebra 1

Example Question #62 : Algebra 1

Example Question #61 : Linear Equations

Example Question #61 : How To Solve One Step Equations

Example Question #61 : Linear Equations

Example Question #69 : Algebra 1

All Algebra 1 Resources

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