Algebra 1 : How to write expressions and equations

Study concepts, example questions & explanations for Algebra 1

varsity tutors app store varsity tutors android store

Example Questions

Example Question #1041 : Linear Equations

Write the expression:  Sixteen less than a number squared.

Possible Answers:

\displaystyle x^2-16

\displaystyle 16-x^2

\displaystyle (x^2-16)^2

\displaystyle (x-16)^2

\displaystyle (16-x)^2

Correct answer:

\displaystyle x^2-16

Explanation:

Separate the sentence into parts.

A number squared:  \displaystyle x^2

Sixteen less than a number squared:  \displaystyle x^2-16

Note that the number 16 is subtract from \displaystyle x^2 if 16 is less than the number.

The answer is:  \displaystyle x^2-16

Example Question #1042 : Linear Equations

Write as a variable expression:

Nine multiplied by the sum of a number and two thirds.

Possible Answers:

\displaystyle 9 \left ( x+\frac{2}{3}\right )

\displaystyle 9 x+\frac{2}{3}

\displaystyle 9 +\frac{2}{3} x

\displaystyle \frac{9 +2x}{3}

\displaystyle \frac{9 \left ( x+2 \right )}{3}

Correct answer:

\displaystyle 9 \left ( x+\frac{2}{3}\right )

Explanation:

"The sum of a number and two thirds" is the result of adding \displaystyle x and \displaystyle \frac{2}{3}:

\displaystyle x+ \frac{2}{3}

Nine multiplied by this, remembering to use parentheses to override the precedence of multiplication, is:

\displaystyle 9 \left ( x+\frac{2}{3}\right )

 

Example Question #1043 : Linear Equations

Write as a variable expression:

Twenty added to the product of seven tenths and a number

Possible Answers:

\displaystyle \frac{7x+20}{10}

\displaystyle \frac{7(x+20)}{10}

\displaystyle \frac{7}{10}(x+20)

\displaystyle \frac{7}{10}x+20 

\displaystyle \frac{7}{10}+20 x

Correct answer:

\displaystyle \frac{7}{10}x+20 

Explanation:

"The product of seven tenths and a number" is the result of multiplying \displaystyle \frac{7}{10} and \displaystyle x:

\displaystyle \frac{7}{10}x.

"Twenty added to" this is 

\displaystyle \frac{7}{10}x+20

Example Question #131 : How To Write Expressions And Equations

Which of the following English-language expressions can be rewritten as the algebraic expression \displaystyle \frac{2}{3} (x-7)  ?

Possible Answers:

Two thirds multiplied by the difference of a number and seven

The product of a number and seven, subtracted from two thirds

Two thirds multiplied by the difference of seven and a number

Two thirds subtracted from the product of a number and seven

None of the other responses is correct

Correct answer:

Two thirds multiplied by the difference of a number and seven

Explanation:

\displaystyle \frac{2}{3} (x-7) is two thirds multiplied by \displaystyle x-7, which is the difference of a number and seven. Putting this together, this expression is stated as:

"Two thirds multiplied by the difference of a number and seven"

Example Question #1051 : Linear Equations

"If seven is multiplied by the sum of an unknown number and twelve, the result is four times that unknown number."

Rewrite the above statement as a variable equation.

Possible Answers:

\displaystyle 12(x+7) = 4x

\displaystyle 7x = 4x + 12

\displaystyle 12x = 4x + 7

\displaystyle 7(x+12) = 4x

\displaystyle 7x+12= 4x

Correct answer:

\displaystyle 7(x+12) = 4x

Explanation:

If we call this unknown number \displaystyle x, then "the sum of an unknown number and twelve" is

\displaystyle x+12

"seven...multiplied by the sum of an unknown number and twelve" is seven multiplied by \displaystyle x+12; remembering to override the order of operations with parentheses, the expression is 

\displaystyle 7(x+12)

The result is four times that unknown number, which is 

\displaystyle 4x

Putting it together, the equation is

\displaystyle 7(x+12) = 4x

 

Example Question #132 : How To Write Expressions And Equations

Write the expression:  One more than the quantity of twice a number squared.

Possible Answers:

\displaystyle (2x)^2+1

\displaystyle 2(x^2+1)

\displaystyle 2x^2+1

\displaystyle 2(x+1)^2

\displaystyle 2x(x+1)^2

Correct answer:

\displaystyle (2x)^2+1

Explanation:

Split the sentence into parts.  Let a variable be the number.

Twice a number: \displaystyle 2x

The quantity of twice a number squared:  \displaystyle (2x)^2

One more than the quantity of twice a number squared: \displaystyle (2x)^2+1

The answer is:  \displaystyle (2x)^2+1

Example Question #1053 : Linear Equations

Write the expression:  Four less than half a number.

Possible Answers:

\displaystyle \frac{1}{2}x-2

\displaystyle \frac{1}{2}x-4

\displaystyle 4-\frac{1}{2}x

\displaystyle \frac{1}{2}(x-4)

\displaystyle (4-\frac{1}{2})x

Correct answer:

\displaystyle \frac{1}{2}x-4

Explanation:

Separate the sentence into parts.  Use a variable to denote the number.

Half a number:  \displaystyle \frac{1}{2}x

Four less than half a number:  \displaystyle \frac{1}{2}x-4

The answer is:  \displaystyle \frac{1}{2}x-4

Example Question #131 : How To Write Expressions And Equations

Write the following equation:  Five more than twice a number is nine.

Possible Answers:

\displaystyle 2x+5=9

\displaystyle 2x=5+9

\displaystyle x+10=9

\displaystyle (2+5)x=9

\displaystyle 2(x+5)=9

Correct answer:

\displaystyle 2x+5=9

Explanation:

Separate the sentence into parts.

Twice a number:  \displaystyle 2x

Five more than twice a number:  \displaystyle 2x+5

Is nine:  \displaystyle =9

Combine the parts.

The answer is:  \displaystyle 2x+5=9

Example Question #132 : How To Write Expressions And Equations

Write the expression:  Six more than the cube root of twice a number.

Possible Answers:

\displaystyle \sqrt[3]{2x+6}

\displaystyle 2\sqrt[3]{x+6}

\displaystyle 2\sqrt[3]{x}+6

\displaystyle 2\sqrt[3]{2(x+6)}

\displaystyle \sqrt[3]{2x}+6

Correct answer:

\displaystyle \sqrt[3]{2x}+6

Explanation:

Seperate the sentence into parts.

Twice a number:  \displaystyle 2x

The cube root of twice a number:  \displaystyle \sqrt[3]{2x}

Six more than the cube root of twice a number:  \displaystyle \sqrt[3]{2x}+6

The answer is:  \displaystyle \sqrt[3]{2x}+6

Example Question #1051 : Algebra 1

"If the product of one-tenths and a number is subtracted from six, the result is seven more than that number."

Rewrite the above statement as a variable equation.

Possible Answers:

\displaystyle \frac{1}{10}x -6 = x + 7

\displaystyle \frac{1}{10}(x -6) = x + 7

\displaystyle 6 - \frac{1}{10}x = x + 7

\displaystyle \frac{1}{10}(x -6) = 7x

\displaystyle \frac{1}{10}x -6 = 7x

Correct answer:

\displaystyle 6 - \frac{1}{10}x = x + 7

Explanation:

If we call this unknown number \displaystyle x, then "the product of one-tenths and a number" is \displaystyle \frac{1}{10}x.

"The product of one-tenths and a number...subtracted from six" is \displaystyle \frac{1}{10}x subtracted from six, or 

\displaystyle 6 - \frac{1}{10}x.

This result is equal to seven more than that number, which is \displaystyle x+7, so the equation is

\displaystyle 6 - \frac{1}{10}x = x + 7.

 

Learning Tools by Varsity Tutors