Call Now to Set Up Tutoring:

(888) 888-0446

Algebra 1 : Equations of Lines

Study concepts, example questions & explanations for Algebra 1

Create An Account

All Algebra 1 Resources

10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #632 : Functions And Lines

Find the length of the line with the following endpoints:

(6,7)(-6,-7)

Possible Answers:

$\sqrt{337}$

$2\sqrt{85}$

$2\sqrt{87}$

$\sqrt{341}$

Correct answer:

$2\sqrt{85}$

Explanation:

In order to find the distance between two points on a line, use the formula below:

$\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

Plug in the points (6,7) and (-6,-7) and solve:

$\sqrt{(6+6)^{2}+(7+7)^{2}}=\sqrt{(12)^{2}+(14)^{2}}=\sqrt{144+196}=\sqrt{340}=2\sqrt{85}$

This gives a final answer of $2\sqrt{85}$

Report an Error

Example Question #51 : Points And Distance Formula

What is the distance of the line connected by the points (2,8) and (-3,6) ?

Possible Answers:

$3\sqrt{5}$

$2\sqrt{5}$

$\sqrt{21}$

$\sqrt{29}$

$\sqrt{31}$

Correct answer:

$\sqrt{29}$

Explanation:

Use the distance formula to determine the line connected by the two points.

The distance formula is:

$d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Let:

(x_1,y_1) = (2,8)

(x_2,y_2) =(-3,6)

Substitute the points into the formula.

$d= \sqrt{(-3-2)^2+(6-8)^2}$

Simplify the inner terms.

$d= \sqrt{(-5)^2+(-2)^2}$

$d= \sqrt{25+4} = \sqrt{29}$

The distance of the line connect by the two points is: $\sqrt{29}$

Report an Error

Example Question #634 : Functions And Lines

Find the length of the line with the following endpoints:

(-5,-3)(4,2)

Possible Answers:

$\sqrt{106}$

$4\sqrt{29}$

$4\sqrt{27}$

$4\sqrt{28}$

Correct answer:

$\sqrt{106}$

Explanation:

In order to find the distance between two points on a line, use the formula below:

$\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

Plug in the points (-5,-3) and (4,2) and solve:

$\sqrt{(4+5)^{2}+(2+3)^{2}}=\sqrt{(9)^{2}+(5)^{2}}=\sqrt{81+25}=\sqrt{106}$

This gives a final answer of $\sqrt{106}$

Report an Error

Example Question #635 : Functions And Lines

Find the length of the line with the following endpoints:

(4,9)(-2,-1)

Possible Answers:

$2\sqrt{73}$

$9\sqrt{5}$

$\sqrt{136}$

$\sqrt{147}$

Correct answer:

$\sqrt{136}$

Explanation:

In order to find the distance between two points on a line, use the formula below:

$\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

Plug in the points (4,9) and (-2,-1) and solve:

$\sqrt{(9+1)^{2}+(4+2)^{2}}=\sqrt{(10)^{2}+(6)^{2}}=\sqrt{100+36}=\sqrt{136}$

This gives a final answer of $\sqrt{136}$

Report an Error

Example Question #3925 : Algebra 1

Find the length of the line between the two points

(1, 5) and (-3, 4)

Possible Answers:

$\sqrt{85}$

$\sqrt{17}$

$\sqrt{3}$

$\sqrt{5}$

$\sqrt{12}$

Correct answer:

$\sqrt{17}$

Explanation:

To find the length between two points, we use the following distance formula:

$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

where (x_1, y_1) and (x_2, y_2) are the points given.

Using the given points

(1, 5) and (-3, 4)

we can substitute into the formula. We get

$d = \sqrt{(-3-1)^2 + (4-5)^2}$

$d = \sqrt{(-4)^2 + (-1)^2}$

$d = \sqrt{16 + 1}$

$d = \sqrt{17}$

Therefore, the distance between the points (1, 5) and (-3, 4) is $\sqrt{17}$ .

Report an Error

Example Question #3926 : Algebra 1

Find the length of the line between the points

(-3, -3) and (-5, -8)

Possible Answers:

$\sqrt{7}$

$\sqrt{29}$

$\sqrt{-7}$

$\sqrt{185}$

$\sqrt{37}$

Correct answer:

$\sqrt{29}$

Explanation:

To find the length between two points, we use the following distance formula:

$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

where (x_1, y_1) and (x_2, y_2) are the points given.

Using the given points

(-3, -3) and (-5, -8)

we can substitute into the formula. We get

$d = \sqrt{(-5 - -3)^2 + (-8 - -3)^2}$

$d = \sqrt{(-5+3)^2 + (-8+3)^2}$

$d = \sqrt{(-2)^2 + (-5)^2}$

$d = \sqrt{4 + 25}$

$d = \sqrt{29}$

Therefore, the distance between the points (-3, -3) and (-5, -8) is $\sqrt{29}$ .

Report an Error

Example Question #3926 : Algebra 1

If the line $\overline{AB}$ is connected by the points (8,3) and (-3,5) , what is the exact length of this line?

Possible Answers:

$5\sqrt2$

$\sqrt{39}$

$\sqrt{89}$

$5\sqrt5$

$\sqrt{29}$

Correct answer:

$5\sqrt5$

Explanation:

Use the distance formula to determine the distance of this line.

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the points into the equation.

$d=\sqrt{(5-3)^2+(-3-8))^2}$

Simplify the radical.

$d=\sqrt{(2)^2+(-11)^2} = \sqrt{4+121} = \sqrt{125}$

Pull out the common factors. This radical can still be reduced.

$\sqrt{125} = \sqrt{25}\cdot \sqrt5 =5\sqrt5$

The exact length of the line is: $5\sqrt5$

Report an Error

Example Question #3927 : Algebra 1

Steven and Joel are on a massive grid. Steven is located at point (1,2) on the grid and Joel is located at (-1,-2) . How far away from each other are they?

Possible Answers:

$2\sqrt{5}units$

None of these

$5\sqrt{2}units$

20units

3units

Correct answer:

$2\sqrt{5}units$

Explanation:

The distance formula is:

$d= \sqrt{(x_{1}-x_{_{2}})^2+(y_{1}-y_2)^2}$

Plug in these points into the distance formula.

$d=\sqrt{(1-(-1))^2+(2-(-2))^2}$

$d=\sqrt{(2^2)+4^2}$

$d=\sqrt{20}$

Reduce:

$d=\sqrt{4}*\sqrt{5}$

$d=2\sqrt{5}$

Report an Error

Example Question #61 : How To Find The Length Of A Line With Distance Formula

Steven and Joel are on a massive grid. Steven is located at point (1,2) on the grid and Joel is located at (-2,-2) . How far away from each other are they?

Possible Answers:

$5\sqrt{2}units$

20units

Cannot be determined

5units

$2\sqrt5units$

Correct answer:

5units

Explanation:

The distance formula is:

$d= \sqrt{(x_{1}-x_{_{2}})^2+(y_{1}-y_2)^2}$

Plug in Seven and Joel's coordinates into this formula.

$d= \sqrt{(1-(-2))^2+(2-(-2))^2}$

$d=\sqrt{(3^2)+4^2}$

$d=\sqrt{25}=5units$

Report an Error

Example Question #61 : Points And Distance Formula

What is the distance of the line connected by the points (-3,-6) and (7,-3) ?

Possible Answers:

$\sqrt{7}$

$\sqrt{17}$

$\sqrt{109}$

$\sqrt{97}$

Correct answer:

$\sqrt{109}$

Explanation:

Write the distance formula.

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the given points into the formula.

$D=\sqrt{(7-(-3))^2+(-3-(-6))^2}$

Simplify the terms inside the parentheses.

$D=\sqrt{(10)^2+(3)^2} =\sqrt{100+9} = \sqrt{109}$

The answer is: $\sqrt{109}$

Report an Error

View Algebra Tutors

Chukwudi
Certified Tutor

University of Nigeria, Nsukka., Bachelor of Science, Biochemistry. African University of Science and Technology., Master of S...

View Algebra Tutors

Vaansh
Certified Tutor

Rutgers University-New Brunswick, Bachelor of Science, Biological and Physical Sciences.

View Algebra Tutors

Jeanene
Certified Tutor

Troy University, Bachelor of Science, Science Teacher Education.

All Algebra 1 Resources

10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

GMAT Tutors in Washington DC, Biology Tutors in Atlanta, Chemistry Tutors in San Diego, GMAT Tutors in Miami, SSAT Tutors in Seattle, GMAT Tutors in Los Angeles, Biology Tutors in Dallas Fort Worth, SAT Tutors in Phoenix, SAT Tutors in Dallas Fort Worth, MCAT Tutors in New York City

Popular Courses & Classes

ACT Courses & Classes in Seattle, SSAT Courses & Classes in Boston, LSAT Courses & Classes in Miami, GMAT Courses & Classes in San Diego, ISEE Courses & Classes in Houston, MCAT Courses & Classes in Houston, Spanish Courses & Classes in Chicago, LSAT Courses & Classes in San Francisco-Bay Area, SAT Courses & Classes in Dallas Fort Worth, SSAT Courses & Classes in Denver

Popular Test Prep

ACT Test Prep in Seattle, ISEE Test Prep in Atlanta, GRE Test Prep in Atlanta, MCAT Test Prep in Philadelphia, MCAT Test Prep in Miami, SSAT Test Prep in Seattle, SAT Test Prep in New York City, LSAT Test Prep in Chicago, GMAT Test Prep in Washington DC, SSAT Test Prep in Philadelphia

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Algebra 1 : Equations of Lines

Study concepts, example questions & explanations for Algebra 1

All Algebra 1 Resources

Example Questions

Example Question #632 : Functions And Lines

Example Question #51 : Points And Distance Formula

Example Question #634 : Functions And Lines

Example Question #635 : Functions And Lines

Example Question #3925 : Algebra 1

Example Question #3926 : Algebra 1

Example Question #3926 : Algebra 1

Example Question #3927 : Algebra 1

Example Question #61 : How To Find The Length Of A Line With Distance Formula

Example Question #61 : Points And Distance Formula

All Algebra 1 Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: