Call Now to Set Up Tutoring:

(888) 888-0446

Algebra 1 : Equations of Lines

Study concepts, example questions & explanations for Algebra 1

Create An Account

All Algebra 1 Resources

10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #69 : How To Find The Midpoint Of A Line Segment

Find the midpoint of the line segment with points $\left ( 6, 2\right )$ and $\left ( 5, 16\right )$ .

Possible Answers:

$\left ( 4, 10.5\right )$

$\left ( -5.5, 9\right )$

(5.5, 9 )

$\left ( 11, 3.5\right )$

$\left ( 4, -10.5\right )$

Correct answer:

(5.5, 9 )

Explanation:

In order to solve this problem, you must know the midpoint formula.

$\left(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2}\right)$ .

The first step is to plug in the coordinates of the endpoints given into the formula.

$\left(\frac{6+5}{2},\frac{2+16}{2}\right)$ .

Do the addition written, and you would end up with $\left(\frac{11}{2},\frac{18}{2}\right)$ .

This simplifies to $\left ( 5.5,9\right )$ .

The midpoint of the line segment with coordinates $\left ( 6,2\right )$ and $\left ( 5, 16\right )$ is $\left ( 5.5, 9\right )$ .

Report an Error

Example Question #901 : Functions And Lines

Find the midpoint of the line segment with the following endpoints:

(-3,-4)(17,6)

Possible Answers:

(-7,-1)

(1,9)

(7,1)

(7,9)

Correct answer:

(7,1)

Explanation:

Finding the midpoint of a line segment only requires that we find the midpoint, or average of both the x and y components. In order to do that, we use the following formula:

$(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

For the points (-3,-4) and (17,6) plug in the numbers and solve:

$(\frac{-3+17}{2},\frac{-4+6}{2})=(\frac{14}{2},\frac{2}{2})=(7,1)$

This gives a final answer of (7,1)

Report an Error

Example Question #662 : Equations Of Lines

Find the midpoint of (2,9) and (-1,7) .

Possible Answers:

$\left (\frac{3}{2},8 \right )$

$\left (0,8 \right )$

$\left (\frac{1}{2},8 \right )$

$\left (\frac{3}{2},1 \right )$

$\left (\frac{1}{2},16 \right )$

Correct answer:

$\left (\frac{1}{2},8 \right )$

Explanation:

Write the formula for the midpoint. The midpoint is an order pair.

$(x,y) = (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Substitute the points.

$(x,y) = (\frac{2+ (-1 )}{2},\frac{9+7}{2})$

Simplify the expressions.

$(x,y) = (\frac{1}{2},\frac{16}{2}) = (\frac{1}{2},8)$

The midpoint is located at: $(\frac{1}{2},8)$

Report an Error

Example Question #663 : Equations Of Lines

Find the midpoint of the line containing endpoings (-1, -1) and (-3, 9).

Possible Answers:

(-4, 8)

(3, -9)

(-2, 5)

(-2, 4)

(2, -10)

Correct answer:

(-2, 4)

Explanation:

To find the midpoint, we use the midpoint formula

$(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

where (x_1, y_1) and (x_2, y_2) are the endpoints.

Given the endpoints (-1, -1) and (-3, 9), we can substitute into the formula. We get

$(\frac{-1 + -3}{2}, \frac{-1 + 9}{2})$

$(\frac{-4}{2}, \frac{8}{2})$

(-2, 4)

Therefore, the midpoint is (-2, 4).

Report an Error

Example Question #664 : Equations Of Lines

Find the midpoint of a line segment with endpoints of (-2, 0) and (-6, -4).

Possible Answers:

(-8, -4)

(-4, -8)

(-4, -2)

(4, 4)

(-2, -4)

Correct answer:

(-4, -2)

Explanation:

To find the midpoint of a line segment given the endpoints, we will use the following formula:

$\text{midpoint} = (\frac{x_1+x_2}{2}, \frac{y_1 + y_2}{2})$

where (x_1, y_1) and (x_2, y_2) are the endpoints given.

Now, we can substitute the points given into the formula. We get

$\text{midpoint} = (\frac{-2+-6}{2}, \frac{0+-4}{2})$

$\text{midpoint} = (\frac{-2 - 6}{2}, \frac{0-4}{2})$

$\text{midpoint} = (\frac{-8}{2}, \frac{-4}{2})$

$\text{midpoint} = (-4, -2)$

Therefore, the midpoint of the endpoints (-2, 0) and (-6, -4) is (-4, -2).

Report an Error

Example Question #665 : Equations Of Lines

Find the midpoint of the line that contains the following endpoints:

(0, 1) and (-2, -5)

Possible Answers:

(-1, -2)

(1, 2)

(1, -3)

(-2, -1)

(2, 1)

Correct answer:

(-1, -2)

Explanation:

When finding the midpoint of a line, we use the following formula

$(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

where (x_1, y_1) and (x_2, y_2) are the endpoints.

Given the points

(0, 1) and (-2, -5)

we can substitute into the formula. We get

$(\frac{0+-2}{2}, \frac{1+-5}{2})$

$(\frac{0-2}{2}, \frac{1-5}{2})$

$(\frac{-2}{2}, \frac{-4}{2})$

(-1, -2)

Report an Error

Example Question #666 : Equations Of Lines

Find the midpoint of the line containing the following endpoints:

(-1, -1) and (-3, -7)

Possible Answers:

(1, 3)

(-2, -4)

(-1, -3)

(-4, -8)

(2, 4)

Correct answer:

(-2, -4)

Explanation:

When finding the midpoint of a line, we use the following formula

$(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

where (x_1, y_1) and (x_2, y_2) are the endpoints.

Given the points

(-1, -1) and (-3, -7)

we can substitute into the formula. We get

$(\frac{-1+-3}{2}, \frac{-1+-7}{2})$

$(\frac{-1-3}{2}, \frac{-1-7}{2})$

$(\frac{-4}{2}, \frac{-8}{2})$

(-2, -4)

Report an Error

Example Question #661 : Equations Of Lines

Find the midpoint of the line segment containing the two points

(3,8) and (7,4)

Possible Answers:

(3,6)

(5,6)

(2,2)

(5,4)

Correct answer:

(5,6)

Explanation:

To find the midpoint we follow the formula

$M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Plugging in the points (3,8) and (7,4) for (x_1,y_1) and (x_2,y_2)

$M=(\frac{3+7}{2},\frac{8+4}{2})$

and we get

(5,6)

Report an Error

Example Question #661 : Equations Of Lines

A line is connected by points (2,5) and (-1,3) on a graph. What is the midpoint?

Possible Answers:

$(-\frac{1}{2},4)$

$(\frac{9}{2},4)$

$(-\frac{3}{2},4)$

$(-\frac{3}{2},1)$

$(\frac{1}{2},4)$

Correct answer:

$(\frac{1}{2},4)$

Explanation:

Write the midpoint formula.

$(x,y) = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

Let (x_1,y_1) = (2,5) and (x_2,y_2) = (-1,3) .

Substitute the given points.

$(x,y) = (\frac{2+(-1)}{2}, \frac{5+3}{2})$

Simplify the coordinate.

$(x,y) =(\frac{1}{2},4)$

The answer is: $(\frac{1}{2},4)$

Report an Error

Example Question #668 : Equations Of Lines

Find the midpoint between the following two endpoints: (-2,5) and (4,9) .

Possible Answers:

(1,14)

(2,14)

(2,7)

(-3,-2)

(1,7)

Correct answer:

(1,7)

Explanation:

The midpoint formula is $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$ . All we need to do is add the x-values and divide by 2, then add the y-values and divide by 2. This leaves us with a midpoint of (1,7) .

Report an Error

View Algebra Tutors

Midori
Certified Tutor

University of Connecticut, Bachelor in Arts, Applied Mathematics. University of Southern California, Master of Arts Teaching,...

View Algebra Tutors

Mariam
Certified Tutor

Yarmouk University, Bachelor of Science, Mathematics. Touro College, Master of Science, Teacher Education, Multiple Levels.

View Algebra Tutors

Tajrin
Certified Tutor

CUNY Brooklyn College, Bachelor of Science, Computer Science.

All Algebra 1 Resources

10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

LSAT Tutors in Dallas Fort Worth, Physics Tutors in Denver, Reading Tutors in Houston, SSAT Tutors in Boston, Chemistry Tutors in Phoenix, Algebra Tutors in San Francisco-Bay Area, French Tutors in Miami, Chemistry Tutors in San Diego, Statistics Tutors in San Francisco-Bay Area, Algebra Tutors in Seattle

Popular Courses & Classes

SAT Courses & Classes in Atlanta, SAT Courses & Classes in Miami, SSAT Courses & Classes in Dallas Fort Worth, MCAT Courses & Classes in Miami, Spanish Courses & Classes in Philadelphia, ACT Courses & Classes in Houston, LSAT Courses & Classes in Seattle, ISEE Courses & Classes in Atlanta, ISEE Courses & Classes in San Diego, Spanish Courses & Classes in Denver

Popular Test Prep

ISEE Test Prep in San Francisco-Bay Area, SAT Test Prep in Phoenix, LSAT Test Prep in Chicago, SAT Test Prep in San Francisco-Bay Area, GMAT Test Prep in Chicago, ACT Test Prep in New York City, GMAT Test Prep in Los Angeles, GRE Test Prep in Philadelphia, MCAT Test Prep in Houston, ACT Test Prep in Washington DC

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Algebra 1 : Equations of Lines

Study concepts, example questions & explanations for Algebra 1

All Algebra 1 Resources

Example Questions

Example Question #69 : How To Find The Midpoint Of A Line Segment

Example Question #901 : Functions And Lines

Example Question #662 : Equations Of Lines

Example Question #663 : Equations Of Lines

Example Question #664 : Equations Of Lines

Example Question #665 : Equations Of Lines

Example Question #666 : Equations Of Lines

Example Question #661 : Equations Of Lines

Example Question #661 : Equations Of Lines

Example Question #668 : Equations Of Lines

All Algebra 1 Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: