Algebra 1 : Algebra 1

Study concepts, example questions & explanations for Algebra 1

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Example Questions

Example Question #31 : How To Use Foil In The Distributive Property

We usually use the FOIL method of distribution for expanding polynomials, but it is actually a property of numbers. Try to solve the product by foiling instead of computing directly.

Possible Answers:

Correct answer:

Explanation:

Using the FOIL distribution method:

First: 

Outer: 

Inner: 

Last: 

Resulting in: 

Example Question #32 : How To Use Foil In The Distributive Property

Expand and simplify.

Possible Answers:

Correct answer:

Explanation:

Using the FOIL distribution method:

First: 

Outer: 

Inner: 

Last: 

Resulting in: 

Combining like terms, the 's combine for a final answer of:

Example Question #33 : How To Use Foil In The Distributive Property

Expand and simplify.

Possible Answers:

Correct answer:

Explanation:

Using the FOIL distribution method:

First: 

Outer: 

Inner: 

Last: 

Resulting in: 

Combining like terms, the 's cancel for a final answer of:

Expressions of this form are commonly referred to as "difference of squares". If you can spot them, they are easy to expand and to factor because the middle terms always cancel.

Example Question #38 : Distributive Property

Expand by FOILing:

Possible Answers:

Correct answer:

Explanation:

First:

Outside:

Inside:

Last:

Add the values together and combine like terms:

Example Question #4851 : Algebra 1

Expand by FOILing:

Possible Answers:

Correct answer:

Explanation:

First:

Outside:

Inside:

Last:

Add the values together and combine like terms:

Example Question #4852 : Algebra 1

Use FOIL to combine like terms in the following expression:

Possible Answers:

Correct answer:

Explanation:

FOIL (first, outside, inside, last) is a device to help students remember to multiply every term by every other term exactly one time. The steps of using FOIL progress as follows:

1) Multiply the first term of each parenthetical expression together:

2) Next, multiply the "outside" terms together:

Add that to the first product, since the terms are all being added together in the parentheses, and the distributive property requires that we maintain the sign:

3) Multiply the "inside" terms together:

Add that to the first two products:

4) Finally, multiply the last terms from each parenthetical expression together:

Add all of the terms together and combine like terms where possible:

Example Question #4853 : Algebra 1

Multiply the following expressions together using FOIL:

Possible Answers:

Correct answer:

Explanation:

FOIL (first, outside, inside, last) is a device to help students remember to multiply every term by every other term exactly one time. The steps of using FOIL progress as follows:

1) Multiply the first term of each parenthetical expression together:

2) Next, multiply the "outside" terms together:

Add that to the first product, since the terms are all being added together in the parentheses, and the distributive property requires that we maintain the sign:

3) Multiply the "inside" terms together:

Add that to the first two products:

4) Finally, multiply the last terms from each parenthetical expression together:

Add all of the terms together and combine like terms where possible:

Example Question #4857 : Algebra 1

We usually use the FOIL method of distribution for expanding polynomials, but it is actually a property of numbers.  Try to solve the product by foiling instead of computing directly.

Possible Answers:

Correct answer:

Explanation:

Using the FOIL distribution method:

First: 

Outer: 

Inner: 

Last: 

Resulting in: 

The 50's cancel leaving us with:

Example Question #4854 : Algebra 1

Expand and simplify.

Possible Answers:

Correct answer:

Explanation:

Using the FOIL distribution method:

First: 

Outer: 

Inner: 

Last: 

Resulting in: 

Combining like terms, the 's combine for a final answer of:

Example Question #4855 : Algebra 1

Use the FOIL method to simplify the expression .

Possible Answers:

Correct answer:

Explanation:

Begin by considering the first part of this expression, . Multiplying the first terms gives 

The product of the outside terms is  and that of the inside terms is , and the product of the last terms is . Altogether, this yields 

 

as the value of the first part of the expression.

Finally, we just need to add the value of the second part,

The final, simplified value of the expression is .

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