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Algebra 1 : Algebra 1

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10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #127 : Fractions And Percentage

Convert $130\%$ to a fraction.

Possible Answers:

$\frac{10}{13}$

$\frac{13}{10}$

$\frac{100}{13}$

$\frac{13}{100}$

$\frac{13000}{1}$

Correct answer:

$\frac{13}{10}$

Explanation:

A percent is defined as a number over 100 parts.

Remove the percentage sign and divide the 130 by 100.

$\frac{130}{100}$

Reduce this fraction by cancelling the zeros in the ones place.

The answer is: $\frac{13}{10}$

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Example Question #128 : Fractions And Percentage

Convert 60% into a reduced fraction.

Possible Answers:

$\frac{3}{5}$

$\frac{60}{100}$

$\frac{15}{30}$

$\frac{3}{4}$

$\frac{4}{5}$

Correct answer:

$\frac{3}{5}$

Explanation:

We first convert to an unsimplified fraction. We know that all percentages have 100 as the denominator, so we begin by putting in the numerator, to get $\frac{60}{100}$ . This is one of the answer choices, but we are not quite finished, because this can be reduced, or simplified. Because and 100 both end in a zero, we know they are divisible by . So we must divide both the numerator and denominator by . This leaves us with $\frac{6}{10}$ . We check to see if there are any other common factors and discover that both and are even numbers. This means that both are divisible by . So when we divide the numerator and denominator by , we are left with $\frac{3}{5 }$ . This is fully reduced, because there are no factors that and have in common. (Note that there are several ways we could have started this--i.e. beginning by dividing by 5,2,20,etc. --but this is one way to go about it. No matter what, if you do it correctly you will arrive at the same answer.)

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Example Question #1 : Whole And Part

70% of a quantity is 35. What is the quantity?

Possible Answers:

45.5

44.5

24.5

Correct answer:

Explanation:

We can write this as an equation:

$0.70\cdot x=35$

$x=\frac{35}{0.7}$

x=50

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Example Question #1 : How To Find The Whole From The Part With Percentage

80% of ____ = 72?

Possible Answers:

Correct answer:

Explanation:

$\frac{80}{100}=\frac{4}{5}$

$\frac{4}{5}x=72$

Divide by fractions:

$x=\frac{5}{4}\cdot 72=90$

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Example Question #2 : Whole And Part

Malcolm spent 15% of his money on a bicycle that costs $300. How many dollars does Malcolm have left?

Possible Answers:

1500

1800

2000

1700

1600

Correct answer:

1700

Explanation:

If $300 was 15% of Malcolm's money, then we can figure out how much money Malcolm had by creating this equation:

.15x=300

In this case, Malcolm had $2,000. Since he spent $300 of it on a bicycle, he has only $1,700 left.

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Example Question #3 : How To Find The Whole From The Part With Percentage

If 45 is 15% of , find the value of .

Possible Answers:

33.3

275

300

450

Correct answer:

300

Explanation:

The key to this problem is identifying that "15% of " is the same as 0.15x . With this information, we can write out the simple equation

45=0.15x

Dividing both sides by 0.15 gives us

x=300

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Example Question #4 : How To Find The Whole From The Part With Percentage

$1\tfrac{1}{2}$ % of what number is 900?

Possible Answers:

13,500

120,000

60,000

12,000

135,000

Correct answer:

60,000

Explanation:

$1\tfrac{1}{2}$ % of a number, or, equivalently, 1.5% of a number, is the same as 0.015 multiplied by that number. If we call that number , then

0.015x=900

$x = 900\div 0.015 = 60,000$

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Example Question #6 : How To Find The Whole From The Part With Percentage

Dana spent 24% of her savings on a laptop that costs $900. How much savings does she have left?

Possible Answers:

3250

2850

3750

4500

3550

Correct answer:

2850

Explanation:

We know that prior to her purchase, $900 was 24% of Dana's Savings. Therefore, Dana's total savings prior to her purchase can be modeled as 0.24x=900 , where is Dana's total savings. Solving for would give you x=3750 , which indicates that Dana's savings was $3750 prior to her purchase. After her purchase, she will have $2850 left.

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Example Question #3161 : Algebra 1

There are 36 blue marbles in a bag. If blue marbles made up 24% of the marbles in the bag, what is the total number of marbles are in the bag?

Possible Answers:

150

152

144

148

Correct answer:

150

Explanation:

If is the total number of marbles in the bag, then 0.24x=36 , since 24% of marbles in the bag are blue and there are 36 marbles. Solving for this equation will give you x=150 , which means there must be a total of 150 marbles in the bag.

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Example Question #8 : How To Find The Whole From The Part With Percentage

12% of the students at a certain high school have perfect attendance. If 27 students have perfect attendance, how many total students does the school contain?

Possible Answers:

300

225

248

550

180

Correct answer:

225

Explanation:

From the given information here, we know that 12% of the total number equals 27. Mathematically, if we use to represent the total that we are looking for, we can write this as

(0.12)(x)=27

The next step is dividing both sides by 0.12 .

$\frac{27}{0.12}=225$

so there are 225 students in the school.

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Algebra 1 : Algebra 1

Study concepts, example questions & explanations for Algebra 1

All Algebra 1 Resources

Example Questions

Example Question #127 : Fractions And Percentage

Example Question #128 : Fractions And Percentage

Example Question #1 : Whole And Part

Example Question #1 : How To Find The Whole From The Part With Percentage

Example Question #2 : Whole And Part

Example Question #3 : How To Find The Whole From The Part With Percentage

Example Question #4 : How To Find The Whole From The Part With Percentage

Example Question #6 : How To Find The Whole From The Part With Percentage

Example Question #3161 : Algebra 1

Example Question #8 : How To Find The Whole From The Part With Percentage

All Algebra 1 Resources

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