All ACT Math Resources
Example Questions
Example Question #1 : How To Find The Perimeter Of A Rectangle
A rectangle has an area of and one side has a length of , what is the perimeter of the rectangle?
To find the length and width of a rectangle given the area and one side, simply divide the area by the given side length:
Next, to find the perimeter use the formula:
Example Question #31 : Rectangles
Find the perimeter of a perimeter with width 5 and length 8.
To solve, simply use the formula for the perimeter of a rectangle. Thus,
Example Question #32 : Rectangles
Find the perimeter of a perimeter with width 5 and length 9.
To solve, simply use the formula for the perimeter of a rectangle. Thus,
Example Question #1 : How To Find If Rectangles Are Similar
Two rectangles are similar. The perimeter of the first rectangle is 36. The perimeter of the second is 12. If the base length of the second rectangle is 4, what is the height of the first rectangle?
4
6
10
2
8
6
Solve for the height of the second rectangle.
Perimeter = 2B + 2H
12 = 2(4) + 2H
12 = 8 + 2H
4 = 2H
H = 2
If they are similar, then the base and height are proportionally equal.
B1/H1 = B2/H2
4/2 = B2/H2
2 = B2/H2
B2 = 2H2
Use perimeter equation then solve for H:
Perimeter = 2B + 2H
36 = 2 B2 + 2 H2
36 = 2 (2H2) + 2 H2
36 = 4H2 + 2 H2
36 = 6H2
H2 = 6
Example Question #1 : How To Find If Rectangles Are Similar
Two rectangles are similar. The first rectangle has a perimeter of and the second has a perimeter of . If the first rectangle has a length of , what the length of the second rectangle?
1. Create a proportion comparing the two given rectangles:
2. Solve for the length of the second rectangle by cross-multiplying:
Example Question #2 : How To Find If Rectangles Are Similar
The width of a rectangle is 5 times the length of the rectangle. The width of the rectangle is 30. What is the perimeter of the rectangle?
If the width is 5 times the length, and the width is 30, then the length is 6. The perimeter of a rectangle is 2 x width + 2 x length. 2 x 30 + 2 x 6 = 72.
Example Question #1 : How To Find The Length Of The Diagonal Of A Square
The perimeter of a square is 48. What is the length of its diagonal?
Perimeter = side * 4
48 = side * 4
Side = 12
We can break up the square into two equal right triangles. The diagonal of the sqaure is then the hypotenuse of these two triangles.
Therefore, we can use the Pythagorean Theorem to solve for the diagonal:
Example Question #143 : Quadrilaterals
What is the area of a square with a diagonal of length ? Round to the nearest hundredth.
Based on the data provided, the square could be drawn like this:
Based on this, you can use the Pythagorean theorem to find :
or
From this, you know that
Since the area is equal to , this is your answer!
Example Question #3 : How To Find The Length Of The Diagonal Of A Square
The perimeter of a square is units. How many units long is the diagonal of the square?
From the perimeter, we can find the length of each side of the square. The side lengths of a square are equal by definition therefore, the perimeter can be rewritten as,
Then we use the Pythagorean Theorme to find the diagonal, which is the hypotenuse of a right triangle with each leg being a side of the square.
Example Question #2 : How To Find The Length Of The Diagonal Of A Square
Find the diagonal of a square with side length .
To solve, simply realize the triangle that is made by sides and the diagonal is an isoceles right triangle. Thus, the hypotenuse is side length time square root of . Thus,