All ACT Math Resources
Example Questions
Example Question #3 : Distance Formula
Line segment has end points of and .
Line segemet has end points of and .
What is the distance between the midpoints?
The midpopint is found by taking the average of each coordinate:
and
The distance formula is given by
.
Making the appropriate substitutions we get a distance of 13.
Example Question #121 : Coordinate Plane
In the standard coordinate plane, what is the perimeter of a triangle with vertices at , and .
This problem is a combination of two mathematical principles: the distance formula between two points, and the reduction of radicals.
To begin this problem we must find the lengths of all sides of the triangle. Because we have the coordinates of the end points of each side, we can apply the distance formula.
= distance between the two points and .
The application of this formula by writing out all the symbols and inserting the points and perhaps using a calculator is cumbersome and can be time consuming. There is a faster application of this formula in a geometric sense. Follow the steps below to give this process a try. This should be repeated for each distance you are trying to find and in our case, it is three different distances.
1) Draw a right triangle with one leg horizontal and one vertical.
2) For the horizontal leg, find the distance between the coordinates of the two choosen points and write down that distance: .
3) Repeat for the vertical leg substituting the coordinates: .
4) Apply the Pythagorean Theorem, where and are the horizontal and vertical leg in no particular order.
5) Solve for .
is the length of one of the sides of your triangle in which you wish to find the perimeter. If the formula is faster for you, use it. If the geometric method is faster and easier to visualize, use that one instead.
After applying the formula to all three legs, you’ll find that you have the lengths, , , and . Once you add them together to find the perimeter (the perimeter of a triangle is all sides added together), you have the value . Unfortunately you won’t find the answer as you still need to simplify the radical.
To go about reducing the radical you will need to break down 52 into its prime factors: 13, 2, and 2. (As an aside, any even number can be checked for prime factors by dividing it by two until it is no longer even.) Since there are two 2’s under the radical, we can rewrite the radical as or . Since we can reduce to .
Therefore, can be rewritten or , which is our perimeter.
Example Question #122 : Coordinate Plane
What is the distance of the line
Between and ?
Round to the nearest hundredth.
What is the distance of the line
Between and ?
To calculate this, you need to know the points for these two values. To find these, substitute in for the two values of given:
Likewise, do the same for :
Now, this means that you have two points:
and
The distance formulat between two points is:
For our data, this is:
This is:
or approximately
Example Question #123 : Coordinate Plane
What is the distance between the x and y intercepts of:
Round to the nearest hundredth.
In order to find the distance between these two points, we first need the points! To find them, substitute in for x and y. Thus, for each you get:
Thus, the two points are:
and
The distance formulat between two points is:
For your data, this is very simply:
or
Example Question #12 : How To Find The Length Of A Line With Distance Formula
What is the length of the line segment whose endpoints are:
To find the distance between two points, use the distance formula:
this gives .
Example Question #752 : Act Math
Two towns—Town A and Town B—are represented by points on a map overlaid with a standard x- and y-coordinate plane. Town A and Town B are represented by points and , respectively. If each unit on the map represents an actual distance of 20 miles, which of the following is closest to the actual distance, in miles, between these two towns?
13
261
64
169
260
260
In order to find the actual distance between these two towns, we must find the distance between these two points. We can find the distance between the points by using the distance formula, where the variable, , represents the distance:
The variables and represent the x-values at each point and and represent the y-values at each point. We can calculate the distance by substituting the x- and y-coordinates of each point into the distance formula.
Since each unit on the map represents an actual distance of miles, the actual distance between the two cities can be calculated using the the following operation:
Example Question #1 : Midpoint Formula
In the standard (x,y) coordinate plane, the midpoint of line XY is (12, –3) and point X is located at (3, 4). What are the coordinates of point Y?
(9, 7)
(21, –10)
(9, –7)
(7.5, 0.5)
(–4, 11)
(21, –10)
To get from the midpoint of (12, –3) to point (3,4), we travel –9 units in the x-direction and 7 units in the y-direction. To find the other point, we travel the same magnitude in the opposite direction from the midpoint, 9 units in the x-direction and –7 units in the y-direction to point (21, –10).
Example Question #1 : How To Find The Endpoints Of A Line Segment
The midpoint of a line segment is . If one endpoint of the line segment is , what is the other endpoint?
The midpoint formula can be used to solve this problem, where the midpoint is the average of the two coordinates.
We are given the midpoint and one endpoint. Plug these values into the formula.
Solve for the variables to find the coordinates of the second endpoint.
The final coordinates of the other endpoint are .
Example Question #3 : Midpoint Formula
Suppose the midpoint of a line segment is What are the endpoints of the segment?
The midpoint of a line segment is found using the formula .
The midpoint is given as Going through the answer choices, only the points and yield the correct midpoint of .
Example Question #4 : How To Find The Endpoints Of A Line Segment
What is the midpoint of the segment of
between and ?
What is the midpoint of the segment of
between and ?
To find this midpoint, you must first calculate the two end points. Thus, substitute in for :
Then, for :
Thus, the two points in question are:
and
The midpoint of two points is:
Thus, for our data, this is:
or