ACT Math : Arithmetic

Study concepts, example questions & explanations for ACT Math

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Example Questions

Example Question #11 : Permutation / Combination

A student is taking a test consisting of six questions. It is a multiple choice test and each question has four answers labelled A, B, C, and D. How many ways can the student answer all six questions if he does not choose the same answer for any two consecutive questions?

Possible Answers:

625

30

972

324

100

Correct answer:

972

Explanation:

the student has four choices for the first question, but only three choices for each of the remaining questions since he does not choose answers with the same letter twice in a row. From the multiplicative counting principle, there are 4 × 3 × 3 × 3 × 3 x 3 = 972 ways Steve can answer the six questions.

 

Example Question #12 : Permutation / Combination

Ashley is modeling a new mix-and-match clothing line. Her stylist has selected 5 tops, 3 skirts, and 4 jackets for her photo shoot. Assuming that an outfit consists of one top, one skirt, and one jacket, how many outfits can Ashley create for the photo shoot?

 

Possible Answers:

20

12

60

45

30

Correct answer:

60

Explanation:

In order to calculate the total possible number of combinations, we must multiply the number of possibilities for each piece by one another.

 

Example Question #651 : Arithmetic

In how many ways can the seven members of a students’ council pose in a line for a yearbook photograph if the chair and vice-chair must be side by side?

 

Possible Answers:

Correct answer:

Explanation:

First find the number of arrangements in which the chair and vice-chair are together. Consider the chair and vice-chair as a unit. This pair as one unit can be arranged with the remaining five members in  ways. For each of these ways, the chair could be either on the left or the right of the vice-chair.

Therefore, there is a total of 2 * 720 = 1440 ways in which the chair and vice-chair are together. 

Example Question #141 : Integers

Sally is putting on jewelry and has decided to wear one necklace, one pair of earrings, and one ring. Her jewelry collection is listed below. How many different combinations of jewelry can she wear?

 

Necklace

Earrings

Ring

short

studs

gold

long

hoops

silver

 

dangling

 

 

Possible Answers:

36

3

18

7

12

Correct answer:

12

Explanation:

To find the number of different combinations, we must use the fundamental counting principal to multiply the number of options in each category together:

(2)(3)(2) = 12

 

 

Example Question #1 : How To Find Permutation Notation

In permutation notation, what does 8P4 represent?

 

Possible Answers:

336

6720

1680

210

Correct answer:

1680

Explanation:

The expression  8P4 represents the number of permutations of 8 objects arranged 4 at a time. Thus, 8 x 7 x 6 x 5 = 1680

                                                                                               

 

 

Example Question #11 : Permutation / Combination

How many different ways can five books be lined up on a shelf?

Possible Answers:

100

120

80

150

60

Correct answer:

120

Explanation:

Order matters, so we use permutations:  (5)(4)(3)(2)(1) = 120

There are five possibilities for the first book, four possibilities for the second book, three for the third, and two for the fourth, and one possibility for the last book.

Example Question #3 : How To Find Permutation Notation

How many different ways can cheese slices be stacked in piles containing  unique types if you are presented with a selection of  different cheeses?  (Presume that the order of the cheese slices does matter.)

Possible Answers:

Correct answer:

Explanation:

Since the order matters, you are dealing with a permutation in this question. A permutation like this could be done with the equation:

For our values, this would be:

However, it is easiest just to think of this like it has  slots. Into the first, you have  choices, into the second , and so forth. This generates for you

more easily.

This is . That is a lot of cheese arrangements!

Example Question #651 : Arithmetic

A car averages 29 miles per gallon.  If gas costs $3.75 per gallon how much money would need to be spent on gas to travel 1464.5 miles?

Possible Answers:

None of the other answers

$5491.88

$108.75

$189.38

$50.5

Correct answer:

$189.38

Explanation:

The question is asking for the amount of money that would need to be spent on gas.  Using the value given for the miles per gallon of the car and the amount of miles traveled it is possible to determine the gallons of fuel that will be required.  This will be set up as 1464.5 miles travelled divided by the 29 miles per gallon that the car gets.  This leaves us with 50.5 gallons of fuel used.  From this point we can multiply the amount of fuel used, 50.5 gallons, by the price of fuel per gallon, $3.75, to obtain the amount of money that will spent on fuel, $189.38.

Example Question #2 : How To Divide Integers

Connie's car gets 35 miles per gallon of gas.  How much gas will she need to take a 525 mile trip?  Round to the nearest gallon.

Possible Answers:

25

20

17

23

15

Correct answer:

15

Explanation:

This becomes a division problem: 525 miles ÷ 35 miles per gallon = 15 gallons

Example Question #651 : Arithmetic

A father buys a bag of marbles.  He divides the marbles among his 5 children, who receive 24 marbles each. If there had been 6 children, how many marbles would each one get?

Possible Answers:

20

24

22

18

Correct answer:

20

Explanation:

There were a total of 120 marbles to begin with, since 5 * 24 = 120.

If the marbles are split between 6 children, then each child gets 120/6 = 20 marbles each.

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