We must put all of the like terms together on either side of the inequality symbol. First, we need to subtract the  to the right side and add  to the left side to get all of the terms with  to the right side of the inequality and all of the integers to the left side.

We solve for  by dividing by .  

That leaves us with , which is the same as .  Remember, you only flip the direction of the inequality if you divide by a negative number!  

To solve an equality that has addition, simply treat it as an equation. Remember, the only time you have to do something to the inquality is when you are multiplying or dividing by a negative number.

Subrtract 4 from each side. Thus,

First, we want to group all of our like terms.  I will move all of my integers to the left side of the inequality. 

Since we are not dividing by a negative sign, we do not have to flip the inequality. 

The first thing that we have to do is deal with the absolute value.  We simply remove the absolute value by equating the left side with the positive and negative solution (of the right side). When we include the negative solution, we must flip the direction of the inequality. Shown explicitly:

Now, we simply solve the inequality by moving all of the integers to the right side, and we are left with:   This reduces down to 

To solve, simply treat it as an equation. This means you want to isolate the variable on one side and move all other constants to the other side through opposite operation manipulation.

Remember, you only flip the inequality sign if you multiply or divide by a negative number.

Thus,

Let us see if we can find counterexamples for each choice so that we can eliminate it. 

Let's look at the choice x+y > 0. We could let -0.75, and we could let y = 0.5, and this would satisfy the conditions for x and y. If x is -0.75 and y is 0.5, then x + y = -0.25 < 0, so this choice doesn't have to be true.

Let's then look at the choice -1 < xy < 1. If we let y be 10 and x be -0.5 then xy would be -5. This means that this choice isn't neccessarily true. 

Let's look at the choice (xy)² > 1. We could let x be -0.5 and we could let y be 1. Then xy would be -0.5, and (xy)² would be 0.25 < 1. This means that this choice isn't always true.

Let's look at the choice (x + y)² > 1. We could let y = 0.5 and x = -0.5. Then x + y would equal 0, and (x+y)² = 0 < 1. We can eliminate this choice as well.

We suspect that (x/y) < 1 might be the answer, because we can contradict every other statement. However, let's see if we can prove that (x/y) has to be less than 1. 

(x/y) < 1

We can multiply both sides by y, because y is positive, and this won't change the inequality sign. After multiplying both sides by y, we would have

x < y

Since y is always a positive number, and since x is always a negative number, this means that y will always be greater than x, so x < y must always be true. 

If we don't know anything for sure. 

could be less than , such as and .

could also be greater than , such as and .

In both of these cases, .

cannot be true.

The other three choices COULD be true, but do not HAVE to be true.

Remember that when you multiply both sides of the inequality by a negative number you must switch the inequality sign around (less than becomes greater than; greater than becomes less than)

The equation simplifies to x > -1.41. -1 is the answer.