A kite must have two sets of equivalent sides. Since we know that this kite has a side length of \(\displaystyle 12\) and another side length of \(\displaystyle 17\), each of these two sides must have one equivalent side. Therefore, the perimeter of this kite can be found by applying the formula:

 \(\displaystyle p=2(a+b)\)

\(\displaystyle p=2(12+17)\)

\(\displaystyle p=2(29)=58\)

Note: the correct solution can also be found by: 

\(\displaystyle p=12+12+17+17=24+34=58\)

A kite must have two sets of equivalent sides. Since we know that this kite has a side length of \(\displaystyle 35\) and another side length of \(\displaystyle \frac{35}{2}=17.5\), each of these two sides must have one equivalent side. Therefore, the perimeter of this kite can be found by applying the formula:

 \(\displaystyle p=2(a+b)\)

\(\displaystyle p=2(35+17.5)\)

\(\displaystyle p=2(52.5)=105\)

Note: the correct solution can also be found by: 

\(\displaystyle p=35+35+17.5+17.5=70+35=105\)

A kite must have two sets of equivalent sides. Since we know that this kite has a side length of \(\displaystyle 7\) and another side length of \(\displaystyle 3.25\), each of these two sides must have one equivalent side. Therefore, the perimeter of this kite can be found by applying the formula:

 \(\displaystyle p=2(a+b)\)

\(\displaystyle p=2(7+3.25)\)

\(\displaystyle p=2(10.25)=20.5\)

Additionally, the correct solution can also be found by: 

\(\displaystyle p=7+7+3.25+3.25=14+6.5=20.5\)

By definition a kite must have two sets of equivalent sides. Since we know that this kite has a side length of \(\displaystyle 26\) and another side with a length of \(\displaystyle 39\), each of these two sides must have one equivalent side. Therefore, the perimeter of this kite can be found by applying the formula:

 \(\displaystyle p=2(a+b)\)

\(\displaystyle p=2(26+39)\)

\(\displaystyle p=2(65)=130\)

Note: the correct solution can also be found by: 

\(\displaystyle p=26+26+39+39=52+78=130\)

The original formula used in this solution is an application of the Distributive Property:  \(\displaystyle 2a+2b=2(a+b)\)

By definition a kite must have two sets of equivalent sides. Since we know that this kite has a side length of \(\displaystyle 40\) and another side with a length of \(\displaystyle 8\), each of these two sides must have one equivalent side.

The perimeter of this kite can be found by applying the formula:

 \(\displaystyle p=2(a+b)\)

\(\displaystyle p=2(40+8)\)

\(\displaystyle p=2(48)=96\)

Note: the correct solution can also be found by: 

\(\displaystyle p=8+8+40+40=16+80=96\)

The original formula used in this solution is an application of the Distributive Property:  \(\displaystyle 2a+2b=2(a+b)\)

A kite must have two sets of equivalent sides. Since we know that this kite has a side length of \(\displaystyle \frac{3}{4}\textup{feet}\) and another side with a length of \(\displaystyle \frac{1}{3}\textup{feet}\), each of these two sides must have one equivalent side.

The perimeter of this kite can be found by applying the formula:

 \(\displaystyle p=2(a+b)\)

Additionally, this problem first requires you to convert each side length from feet to inches. 

\(\displaystyle \frac{3}{4}\textup{ft}=\frac{3}{4}\times\frac{3}{3}=\frac{9}{12}=9\textup{ inches}\)

\(\displaystyle \frac{1}{3}\textup{ft}=\frac{1}{3}\times \frac{4}{4}=\frac{4}{12}=4\textup{ inches}\)

The solution is:

\(\displaystyle p=2(9+4)\)

\(\displaystyle p=2(13)=26\)

Note: the correct solution can also be found by: 

\(\displaystyle p=9+9+4+4=18+8=26\)

The original formula used in this solution is an application of the Distributive Property:  \(\displaystyle 2a+2b=2(a+b)\)

By definition a kite must have two sets of equivalent sides. Since we know that this kite has a side length of \(\displaystyle 20\) and another side with a length of \(\displaystyle 13.5\), each of these two sides must have one equivalent side.

The perimeter of this kite can be found by applying the formula:

 \(\displaystyle p=2(a+b)\)

\(\displaystyle p=2(20+13.5)\)

\(\displaystyle p=2(33.5)=67\)

Note: the correct solution can also be found by: 

\(\displaystyle p=20+20+13.5+13.5=40+27=67\)

By definition a kite must have two sets of equivalent sides. Since we know that this kite has a side length of \(\displaystyle 15\) and another side with a length of \(\displaystyle 30\), each of these two sides must have one equivalent side.

The perimeter of this kite can be found by applying the formula:

 \(\displaystyle p=2(a+b)\)

\(\displaystyle p=2(15+30)\)

\(\displaystyle p=2(45)=90\textup{ inches}\)

Note, though, that \(\displaystyle 90\textup{ inches}\) does not appear as an answer choice. Thus, convert \(\displaystyle 90\textup{ inches}\) into \(\displaystyle \textup{feet}\) by: \(\displaystyle 90\div12=7.5\textup{ feet}\)

 a kite must have two sets of equivalent sides. Since we know that this kite has a side length of \(\displaystyle 88\textup{mm}\) and another side with a length of \(\displaystyle 36\textup{mm}\), each of these two sides must have one equivalent side.

The perimeter of this kite can be found by applying the formula:

 \(\displaystyle p=2(a+b)\)

\(\displaystyle p=2(88+36)\)

\(\displaystyle p=2(124)=248\textup{mm}\)

Note: the correct solution can also be found by: 

\(\displaystyle p=88+88+36+36=176+72=248\)

 A kite must have two sets of equivalent sides. Since we know that this kite has a side length of \(\displaystyle 12\) and another side length of \(\displaystyle 16\), each of these two sides must have one equivalent side.

The perimeter of this kite can be found by applying the formula:

 \(\displaystyle p=2(a+b)\)

\(\displaystyle p=2(12+16)\)

\(\displaystyle p=2(28)=56\textup{cm}\)