We are open Saturday and Sunday!

Call Now to Set Up Tutoring:

(888) 888-0446

Trigonometry : Trigonometry

Study concepts, example questions & explanations for Trigonometry

Create An Account

All Trigonometry Resources

6 Diagnostic Tests 155 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #2 : Angles

What is the relationship between angles 1 and 2?

Screen_shot_2014-02-15_at_6.57.52_pm

Possible Answers:

supplementary

equal

complimentary

horizontal

vertical

Correct answer:

supplementary

Explanation:

These angles are supplementary, as the sum of the angles is 180^o.

Report an Error

Example Question #2 : Complementary And Supplementary Angles

What angle is supplementary to $34^\circ$ ?

Possible Answers:

$214^\circ$

$56^\circ$

$146^\circ$

$326^\circ$

$124^\circ$

Correct answer:

$146^\circ$

Explanation:

Two angles that are supplementary add up to $180^\circ$ . For our problem, that means that $x+34^\circ=180^\circ$ .

Subtract $34^\circ$ from both sides.

$x=180^\circ-34^\circ$

$x=146^\circ$

Report an Error

Example Question #3 : Complementary And Supplementary Angles

Find the complementary angle to $\frac{\pi}{4}$

Possible Answers:

$-\frac{5\pi}{4}$

$\frac{3\pi}{4}$

$\frac{7\pi}{4}$

$-\frac{\pi}{4}$

$\frac{\pi}{4}$

Correct answer:

$\frac{\pi}{4}$

Explanation:

Two angles that are complementary must add to $\frac{\pi}{2}$ , therefore we subtract the given angle from $\frac{\pi}{2}$ as follows:

$\frac{\pi}{2} - \frac{\pi}{4} = \frac{2\pi}{4} - \frac{\pi}{4} = \frac{\pi}{4}$

Report an Error

Example Question #2 : Complementary And Supplementary Angles

Find the complementary angle to $\frac{\pi}{12}$

Possible Answers:

$\frac{23\pi}{12}$

$-\frac{\pi}{12}$

$-\frac{5\pi}{12}$

$\frac{5\pi}{12}$

$\frac{11\pi}{12}$

Correct answer:

$\frac{5\pi}{12}$

Explanation:

Two angles are complementary if their sum is $\frac{\pi}{2}$ , therefore we subtract the given angle from $\frac{\pi}{2}$ as follows:

$\frac{\pi}{2} - \frac{\pi}{12} = \frac{6\pi}{12} - \frac{\pi}{12} = \frac{5\pi}{12}$

Report an Error

Example Question #3 : Angles

Find the angle that is supplementary to $45^{\circ}$

Possible Answers:

$45^{\circ}$

$135^{\circ}$

$315^{\circ}$

$-45^{\circ}$

$-225^{\circ}$

Correct answer:

$135^{\circ}$

Explanation:

Two angles are supplementary if their sum is $180^{\circ}$ , therefore we subtract the given angle from $180^{\circ}$ as follows:

$180^{\circ} - 45^{\circ} = 135^{\circ}$

Report an Error

Example Question #3 : Complementary And Supplementary Angles

Find the angle that is supplementary to $179^{\circ}$

Possible Answers:

$-180^{\circ}$

$-179^{\circ}$

$181^{\circ}$

$180^{\circ}$

$1^{\circ}$

Correct answer:

$1^{\circ}$

Explanation:

Two angles are supplementary if their sum is $180^{\circ}$ , therefore we subtract the given angle from $180^{\circ}$ as follows:

$180^{\circ} - 179^{\circ} = 1^{\circ}$

Report an Error

Example Question #6 : Complementary And Supplementary Angles

Find the angle that is supplementary to $\frac{7\pi}{8}$

Possible Answers:

$-\frac{\pi}{8}$

$\frac{9\pi}{8}$

$-\frac{3\pi}{8}$

$\frac{\pi}{8}$

$-\frac{7\pi}{8}$

Correct answer:

$\frac{\pi}{8}$

Explanation:

If two angles are supplementary their sum is $\pi$ , therefore we subtract the given angle from $\pi$ as follows:

$\pi - \frac{7\pi}{8} = \frac{8\pi}{8} - \frac{7\pi}{8} = \frac{\pi}{8}$

Report an Error

Example Question #4 : Complementary And Supplementary Angles

Find the complementary angle to $17^{\circ}$

Possible Answers:

$-17^{\circ}$

$163^{\circ}$

$117^{\circ}$

$73^{\circ}$

$-73^{\circ}$

Correct answer:

$73^{\circ}$

Explanation:

In order for two angles to be complementary their sum must be $90^{\circ}$ , therefore the complementary angle can be found by subtracting the given angle from $90^{\circ}$ :

$90^{\circ} - 17^{\circ} = 73^{\circ}$

Report an Error

Example Question #2 : Complementary And Supplementary Angles

Determine the complementary angle to $90^{\circ}$

Possible Answers:

$0^{\circ}$

$10^{\circ}$

$270^{\circ}$

$90^{\circ}$

$-90^{\circ}$

Correct answer:

$0^{\circ}$

Explanation:

The sum of two complementary angles must be $90^{\circ}$ , therefore in order to determine the complementary angle of $90^{\circ}$ we simply subtract from $90^{\circ}$ as follows:

$90^{\circ} - 90^{\circ} = 0^{\circ}$

Report an Error

Example Question #11 : Complementary And Supplementary Angles

Find the positive complementary angle of $100^{\circ}$

Possible Answers:

$10^{\circ}$

$260^{\circ}$

Does not exist

$-100^{\circ}$

$80^{\circ}$

Correct answer:

Does not exist

Explanation:

In order for two angles to be complementary their sum must equal $90^{\circ}$ , therefore we subtract the given angle from $90^{\circ}$ as follows:

$90^{\circ} - 100^{\circ} = -10^{\circ}$

However, it was stated that we are looking for the positive complementary angle, therefore, there is no positive complementary angle.

Report an Error

View Trigonometry Tutors

Sharif
Certified Tutor

NCCU, Bachelors, Physics and Mathematics.

View Trigonometry Tutors

Benjamin
Certified Tutor

Portland State University, Bachelor of Science, Computer Science.

View Trigonometry Tutors

Richie
Certified Tutor

Full Sail University, Bachelor of Science, Computer Science.

All Trigonometry Resources

6 Diagnostic Tests 155 Practice Tests Question of the Day Flashcards Learn by Concept

Trigonometry Tutors in Top Cities:

Popular Courses & Classes

GRE Courses & Classes in Dallas Fort Worth, MCAT Courses & Classes in Dallas Fort Worth, GMAT Courses & Classes in Philadelphia, ACT Courses & Classes in Miami, Spanish Courses & Classes in Chicago, GRE Courses & Classes in Miami, LSAT Courses & Classes in Denver, MCAT Courses & Classes in Seattle, MCAT Courses & Classes in Miami, LSAT Courses & Classes in Phoenix

Popular Test Prep

LSAT Test Prep in Chicago, GRE Test Prep in Miami, GRE Test Prep in Washington DC, GMAT Test Prep in Los Angeles, SAT Test Prep in Philadelphia, MCAT Test Prep in Boston, ISEE Test Prep in Phoenix, MCAT Test Prep in Phoenix, ISEE Test Prep in Atlanta, MCAT Test Prep in Denver

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Trigonometry : Trigonometry

Study concepts, example questions & explanations for Trigonometry

All Trigonometry Resources

Example Questions

Example Question #2 : Angles

Example Question #2 : Complementary And Supplementary Angles

Example Question #3 : Complementary And Supplementary Angles

Example Question #2 : Complementary And Supplementary Angles

Example Question #3 : Angles

Example Question #3 : Complementary And Supplementary Angles

Example Question #6 : Complementary And Supplementary Angles

Example Question #4 : Complementary And Supplementary Angles

Example Question #2 : Complementary And Supplementary Angles

Example Question #11 : Complementary And Supplementary Angles

All Trigonometry Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: