We can factor the original expression as . This gives us 2 factors that we need to individually set equal to 0.

The simpler one is:

. The two values for x that give a cosine of 0 are and .

Now set the second factor equal to 0:

add 1 to both sides

divide by 2

. The two values for x that give a cosine of are and .

In total we have 4 answers,

We can think of this equation as:

Then we can factor it as:

. Now we set both factors equal to 0 and solve.

The simpler one is . Sine is 0 when x is 0 or . would also work, although it is just another way of saying 0.

Now we will set the second factor equal to zero:

add to both sides

multiply both sides by

This must have no solution, because sine and cosine are never any larger than 1, and they are never 1 simultaneously. This means that our only answers are 0 and .

This expression can be factored as:

. We can solve by setting each factor equal to 0.

gives the answers since sine is 0 for those values of x.

To continue solving, set the second factor equal to 0:

add to both sides.

divide both sides by 2.

The values of x that give a sine of are and , so this equation has 4 solutions.

To solve, first add 3 to both sides:

square both sides

divide by 2

Consulting the unit circle, sine is positive when

There are multiple solution paths, including using the quadratic formula. This ends up looking a little complicated, and realizing that is necessary. Here is a different way to solve this.

First, re-write the expression by simplifying the second term, and subtracting from both sides

We can see that two of these expressions involve the square root of 3. We can factor by grouping if we change the order the expressions are written in:

We can factor from the first two expressions and from the second two:

Since both groups have a factor of , we can re-write this as:

This gives us two solutions:

and

If the tangent is 1, that means that sine and cosine have the same measure and sign, so

If the tangent is , that means that cosine and sine have opposite signs, sine is and cosine is . So,

First, using the trigonometric identity , re-write the expression so it is entirely in terms of :

 if we add  to both sides and re-order the terms, we can see that this is a quadratic equation in terms of sine:

 so we can use the quadratic formula to solve this way:

This gives us two potential answers:

this is outside of the range of sine, so it won't work.

Taking the inverse on a calculator yields , which we can add to 360 to give .

That's just one answer, however. To get the other answer, we need to know the other angle below the x-axis, so we can add.

We can factor this expression by grouping.

re-arrange the original expression so that the terms with sine are next to each other

factor our the

this factors to

Since we are finding the roots, we should set both factors equal to 0:

add 1 to both sides

subtract 1 from both sides

divide by 2

There are many ways to solve this problem, and here is one.

First, re-write the equation so that it is set equal to zero, since we're finding the roots, and so that it is all in one fraction. That is easy to do since both terms already have the common denominator of 3:

multiply both sides by 3

add the sine term to both sides

divide both sides by 2

multiply by 2

Factor the equation by grouping: the first 2 terms have in common, and the second 2 have 5 in common:

Since we are finding the roots, we can set each factor equal to 0:

subtract 5 from both sides

this is outside of the range for sine

add 1 to both sides

divide both sides by 2

take the square root of both sides

multiply by

That second one is greater than , so we want to figure out which angle between 0 and is coterminal with it. We can figure this out by subtracting , or in this case to get

Factor by grouping. The first 2 terms have in common.

We are finding the roots, so set each factor equal to 0:

subtract 1 from both sides

divide by 4 

add to both sides

divide both sides by 2