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Theory of Positive Integers : Logic

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Example Question #1 : Logic

$B\subseteq \begin{Bmatrix} {3,4,7,9,11} \end{Bmatrix}$ over the domain $S=P(\begin{Bmatrix} {4,7,10,12} \end{Bmatrix})$

For all $B\ \epsilon\ S$ which P(B) is true?

Possible Answers:

$B\ \epsilon\ \begin{Bmatrix} \O, 4,7 \end{Bmatrix}$

$B\ \epsilon\ \begin{Bmatrix} 4,7 \end{Bmatrix}$

$B\ \epsilon\ \begin{Bmatrix} 4,7,11 \end{Bmatrix}$

$B\ \epsilon\ \begin{Bmatrix} 3,7,10 \end{Bmatrix}$

$B\ \epsilon\ \begin{Bmatrix} 4,12 \end{Bmatrix}$

Correct answer:

$B\ \epsilon\ \begin{Bmatrix} \O, 4,7 \end{Bmatrix}$

Explanation:

This question is giving a subset who lives in the domain and it is asking for the partition or group of elements that live in both and .

Looking at what is given,

$B\subseteq \begin{Bmatrix} {3,4,7,9,11} \end{Bmatrix}$

$S=P(\begin{Bmatrix} {4,7,10,12} \end{Bmatrix})$

it is seen that both four and seven live in and therefore both these elements will be in the partition of . Another element that also exists in both sets is the empty set.

Thus the final solution is,

$B\ \epsilon\ \begin{Bmatrix} \O, 4,7 \end{Bmatrix}$

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Example Question #2 : Logic

Negate the following statement.

P: 17 is a prime number.

Possible Answers:

$\sim P:17$ is not a prime number

$\sim P:17$ is a prime number

P:17 is not a prime number

$\sim P:17$ is an odd number

$\sim P:17$ is an even number

Correct answer:

$\sim P:17$ is not a prime number

Explanation:

Negating a statement means to take the opposite of it.

To negate a statement completely, each component of the statement needs to be negated.

The given statement,

P: 17 is a prime number.

contains to components.

Component one: P:17

Component two: "is a prime number"

To negate component one, simply take the compliment of it. In mathematical terms this looks as follows,

$\sim P:17$

To negate component two, simply add a "not" before the phrase "a prime number".

Now, combine these two components back together for the complete negation.

$\sim P:17$ is not a prime number.

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Example Question #3 : Logic

Determine which statement is true giving the following information.

P: 17 is a prime number Q:50 is odd

Possible Answers:

$P\wedge Q$

$P\vee Q$

None of the answers.

$\sim P$

$\sim (P\vee Q)$

Correct answer:

$P\vee Q$

Explanation:

To determine which statement is true first state what is known.

The first component of this statement is:

P: 17 is a prime number

This is a true statement since only one and seventeen are factors of seventeen.

The second component of this statement is:

Q:50 is odd

This statement is false since $50 \mod 2=0$ .

Therefore, the only true statement is the one that uses the "or" operator because only one component is true.

Thus the correct answer is,

$P\vee Q$

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Example Question #4 : Logic

$B\subseteq \begin{Bmatrix} {2,10,11,23} \end{Bmatrix}$ over the domain $S=P(\begin{Bmatrix} {10,20,30} \end{Bmatrix})$

For all $B\ \epsilon\ S$ which P(B) is true?

Possible Answers:

$B\ \epsilon\ \begin{Bmatrix} 10,23 \end{Bmatrix}$

$B\ \epsilon\ \begin{Bmatrix} \O \end{Bmatrix}$

$B\ \epsilon\ \begin{Bmatrix} 10 \end{Bmatrix}$

$B\ \epsilon\ \begin{Bmatrix} \O, 10,20 \end{Bmatrix}$

$B\ \epsilon\ \begin{Bmatrix} \O, 10 \end{Bmatrix}$

Correct answer:

$B\ \epsilon\ \begin{Bmatrix} \O, 10 \end{Bmatrix}$

Explanation:

This question is giving a subset who lives in the domain and it is asking for the partition or group of elements that live in both and .

Looking at what is given,

$B\subseteq \begin{Bmatrix} {2,10,11,23} \end{Bmatrix}$

$S=P(\begin{Bmatrix} {10,20,30} \end{Bmatrix})$

it is seen that only ten lives in and therefore both these elements will be in the partition of . Another element that also exists in both sets is the empty set.

Thus the final solution is,

$B\ \epsilon\ \begin{Bmatrix} \O, 10 \end{Bmatrix}$

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Theory of Positive Integers : Logic

Study concepts, example questions & explanations for Theory of Positive Integers

All Theory of Positive Integers Resources

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Example Question #1 : Logic

Example Question #2 : Logic

Example Question #3 : Logic

Example Question #4 : Logic

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