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SSAT Upper Level Math : How to find the volume of a polyhedron

Study concepts, example questions & explanations for SSAT Upper Level Math

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All SSAT Upper Level Math Resources

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Example Questions

Example Question #1 : How To Find The Volume Of A Polyhedron

Find the volume of a square pyramid that has a height of and a side length of .

Possible Answers:

Correct answer:

Explanation:

The formula to find the volume of a square pyramid is

$\text{Volume}=(side)^2\frac{height}{3}$

So plugging in the information given from the question,

$\text{Volume}=4^2\frac{9}{3}=16\times3=48$

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Example Question #2 : How To Find The Volume Of A Polyhedron

Find the volume of a square pyramid with a height of and a length of a side of its square base of .

Possible Answers:

Correct answer:

Explanation:

The formula to find the volume of a square pyramid is

$\text{Volume}=(side)^2\frac{height}{3}$

So plugging in the information given from the question,

$\text{Volume}=(3^2)\frac{12}{3}=9\times 4=36$

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Example Question #3 : How To Find The Volume Of A Polyhedron

Find the volume of a regular hexagonal prism that has a height of . The side length of the hexagon base is .

Possible Answers:

$660\sqrt3$

$2160\sqrt3$

$1440\sqrt3$

$4320\sqrt3$

Correct answer:

$2160\sqrt3$

Explanation:

The formula to find the volume of a hexagonal prism is

$\text{Volume}=\frac{3\sqrt3}{2}(side)^2(height)$

Plugging in the values given by the question will give

$\text{Volume}=\frac{3\sqrt3}{2}(12^2)(10)=2160\sqrt3$

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Example Question #645 : Geometry

In terms of , find the volume of a regular hexagonal prism that has a height of . The hexagon base has side lengths of .

Possible Answers:

$360x^2\sqrt3$

$120x\sqrt3$

$240x\sqrt3$

$120x^2\sqrt3$

Correct answer:

$120x^2\sqrt3$

Explanation:

The formula to find the volume of a hexagonal prism is

$\text{Volume}=\frac{3\sqrt3}{2}(side)^2(height)$

Plugging in the values given by the question will give

$\text{Volume}=\frac{3\sqrt3}{2}(4x)^2(5)=120x^2\sqrt3$

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Example Question #871 : Ssat Upper Level Quantitative (Math)

Find the volume of a regular tetrahedron with a side length of .

Possible Answers:

$144\sqrt2$

$288\sqrt2$

$1728\sqrt2$

$966\sqrt2$

Correct answer:

$144\sqrt2$

Explanation:

The formula to find the volume of a tetrahedron is

$\text{Volume}=\frac{\sqrt2}{12}(side)^3$

Plugging in the information given by the question gives

$\text{Volume}=\frac{\sqrt2}{12}(12)^3=144\sqrt2$

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Example Question #872 : Ssat Upper Level Quantitative (Math)

Find the volume of a regular octahedron that has a side length of .

Possible Answers:

$\frac{512\sqrt2}{3}$

$100\sqrt2$

$512\sqrt2$

$\frac{500\sqrt2}{3}$

Correct answer:

$\frac{512\sqrt2}{3}$

Explanation:

Use the following formula to find the volume of a regular octahedron:

$\text{Volume}=\frac{\sqrt2}{3}(side)^3$

Plugging in the information from the question,

$\text{Volume}=\frac{\sqrt2}{3}(8)^3=\frac{512\sqrt2}{3}$

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Example Question #873 : Ssat Upper Level Quantitative (Math)

Find the volume of a regular octahedron that has a side length of .

Possible Answers:

$72y^3\sqrt2$

$144y^3\sqrt2$

$84y^3\sqrt2$

$216y^3\sqrt2$

Correct answer:

$72y^3\sqrt2$

Explanation:

Use the following formula to find the volume of a regular octahedron:

$\text{Volume}=\frac{\sqrt2}{3}(side)^3$

Plugging in the information from the question,

$\text{Volume}=\frac{\sqrt2}{3}(6y)^3=72y^3\sqrt2$

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Example Question #874 : Ssat Upper Level Quantitative (Math)

Find the volume of a regular hexahedron with a side length of .

Possible Answers:

$\frac{2744\sqrt2}{3}$

2744

$1372\sqrt3$

196

Correct answer:

2744

Explanation:

A regular hexahedron is another name for a cube.

To find the volume of a cube,

$\text{Volume}=(side)^3$

Plugging in the information given in the question gives

$\text{Volume}=(14)^3=2744$

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Example Question #875 : Ssat Upper Level Quantitative (Math)

Find the volume of a regular octahedron with side lengths of .

Possible Answers:

$81t^3\sqrt2$

$729t^3\sqrt2$

$243t\sqrt2$

$243t^3\sqrt2$

Correct answer:

$243t^3\sqrt2$

Explanation:

Use the following formula to find the volume of a regular octahedron:

$\text{Volume}=\frac{\sqrt2}{3}(side)^3$

Plugging in the information from the question,

$\text{Volume}=\frac{\sqrt2}{3}(9t)^3=243t^3\sqrt2$

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Example Question #876 : Ssat Upper Level Quantitative (Math)

Find the volume of a prism that has a right triangle base with leg lengths of and and a height of .

Possible Answers:

432

144

288

Correct answer:

144

Explanation:

To find the volume of a prism, multiply the area of the base by the height.

$\text{Area of Base}=\frac{3\times8}{2}=12$

$\text{Volume}=12\times height=12\times12=144$

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All SSAT Upper Level Math Resources

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SSAT Upper Level Math : How to find the volume of a polyhedron

Study concepts, example questions & explanations for SSAT Upper Level Math

All SSAT Upper Level Math Resources

Example Questions

Example Question #1 : How To Find The Volume Of A Polyhedron

Example Question #2 : How To Find The Volume Of A Polyhedron

Example Question #3 : How To Find The Volume Of A Polyhedron

Example Question #645 : Geometry

Example Question #871 : Ssat Upper Level Quantitative (Math)

Example Question #872 : Ssat Upper Level Quantitative (Math)

Example Question #873 : Ssat Upper Level Quantitative (Math)

Example Question #874 : Ssat Upper Level Quantitative (Math)

Example Question #875 : Ssat Upper Level Quantitative (Math)

Example Question #876 : Ssat Upper Level Quantitative (Math)

All SSAT Upper Level Math Resources

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