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SSAT Middle Level Math : Lines

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Example Questions

Example Question #1 : How To Find Length Of A Line

Lines

Figure NOT drawn to scale.

AE = 80, AB = x, BC = x + 4, CD = 2x+1, DE = x-6

Evaluate .

Possible Answers:

13.8

17.8

15.2

12.8

16.2

Correct answer:

16.2

Explanation:

By the Segment Addition Postulate,

AB + BC + CD + DE = AE

x + (x+4) + (2x+1) + (x-6) = 80

5x-1= 80

5x-1+1 = 80+1

5x = 81

$5x \div 5 = 81 \div 5$

x = 16.2

AB = x = 16.2

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Example Question #2 : How To Find Length Of A Line

A right triangle has one leg with a length of 6 feet and a hypotenuse of 10 feet. What is the length of the other leg?

Possible Answers:

$8\ \text{ft}$

$5\ \text{ft}$

$4\ \text{ft}$

$10\ \text{ft}$

$6\ \text{ft}$

Correct answer:

$8\ \text{ft}$

Explanation:

In geometry, a right angle triangle can occur with the ratio of 3:4:5 in which 3 and 4 are each leg lengths, and 5 is the hypotenuse.

When you know the length of two sides of a right angle triangle like this, you can calculate the third side using this ratio.

Here, the ratio is:

6:x:10

This is double the 3:4:5 ratio. Therefore, we should multiply 4 by 2 in order to solve for the missing leg, which would be a value of 8 feet.

Another way to solve is to use the Pythagorean Theorem: a^2+b^2=c^2 .

We know that one leg is 6 feet and the hypotenuse is 10 feet.

(6)^2+b^2=(10)^2

36+b^2=100

b^2=64

$b=\sqrt{64}=8$

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Example Question #2 : How To Find Length Of A Line

The radius of a circle is 6 inches. What is one-third of the diameter?

Possible Answers:

$4\ \textup{inches}$

$2\ \textup{inches}$

$7\ \textup{inches}$

$12\ \textup{inches}$

$6\ \textup{inches}$

Correct answer:

$4\ \textup{inches}$

Explanation:

If the radius is equal to 6 inches, then the diameter will be double that value, or 12 inches. One-third of 12 is 4, which is therefore the correct answer.

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Example Question #4 : How To Find Length Of A Line

A right triangle has one leg with length $5\:cm$ and another leg with length $8\:cm$ . What is the length of the hypotenuse?

Possible Answers:

10.5

$\sqrt{55}$

$\sqrt{89}$

$\sqrt{67}$

Correct answer:

$\sqrt{89}$

Explanation:

Since we are dealing with a right triangle, we can use the Pythagorean Theorem:

$a^{2}+b^{2}=c^{2}$ ,

where and are leg lengths of and , respectively, and is the length of the hypotenuse.

Substituting values into the Theorem:

$5^{2}+8^{2}=c^{2}$

$25+64=c^{2}$

$89=c^{2}$

$\sqrt{89}=c$

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Example Question #4 : How To Find Length Of A Line

Line has a length of $60\:cm$ . It is bisected at point , and the resulting segment is bisected again at point . What is the length of the line segment ?

Possible Answers:

$7.5\:cm$

$30\:cm$

$45\:cm$

$20\:cm$

$15\:cm$

Correct answer:

$15\:cm$

Explanation:

A line that is bisected is split into two segments of equal length. Therefore, if line is bisected at point ,

$AC=\frac{1}{2}AB=30\: cm$ .

Consequently, bisecting line segment at point :

$AD=\frac{1}{2}AC=\frac{1}{2}(30)=15\:cm$

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Example Question #1 : Lines

Lines

Figure NOT drawn to scale.

AE = 40, AB = x, BC = x + 3, CD = 2x, DE = x-6

Evaluate .

Possible Answers:

9.6

6.2

7.2

8.6

Correct answer:

8.6

Explanation:

By the Segment Addition Postulate,

AB + BC + CD + DE = AE

x +( x + 3) +( 2x) +( x-6) = 40

5x-3 = 40

5x-3 +3 = 40 + 3

5x = 43

$5x \div 5 = 43 \div 5$

x = 8.6

AB = x = 8.6

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Example Question #221 : Geometry

What is the length of a line segment with end points (3,5) and (6,1) ?

Possible Answers:

Correct answer:

Explanation:

The length of a line segment can be determined using the distance formula:

$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$D=\sqrt{(3-6)^2+(5-1)^2}$

$D=\sqrt{-3^2+4^2}$

$D=\sqrt{9+16}=\sqrt{25}=5$

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Example Question #181 : Plane Geometry

What is the length of a line with endpoints (1,1) and (10,1) .

Possible Answers:

Correct answer:

Explanation:

To find the length of this line, you can subtract 10-1 to get . Since the y-coordinates are the same, you don't have to take any vertical direction into account. Therefore, you only look at the x-coordinates!

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Example Question #182 : Plane Geometry

Find the length of the line segment whose endpoints are (-3,5) and (5,4) .

Possible Answers:

8.06

Correct answer:

8.06

Explanation:

We can use the distance formula:

$D=\sqrt{(x_{1}-x_{2})^2+(y_{1}-y_{2})^2}$

$=\sqrt{(-3-5)^2+(5-4)^2}$

$=\sqrt{64+1}$

$=\sqrt{65}\approx 8.06$

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Example Question #2 : Lines

The point (4,4) lies on a circle. What is the length of the radius of the circle if the center is located at (3,8) ?

Possible Answers:

4.12

4.4

3.12

Correct answer:

4.12

Explanation:

The radius is the distance from the center of the circle to anypoint on the circle. So we can use the distance formula in order to find the radius of the circle:

$D=\sqrt{(x_{1}-x_{2})^2+(y_{1}-y_{2})^2}$

$=\sqrt{(4-3)^2+(4-8)^2}$

$=\sqrt{1+16}$

$=\sqrt{17}\approx 4.12$

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SSAT Middle Level Math : Lines

Study concepts, example questions & explanations for SSAT Middle Level Math

All SSAT Middle Level Math Resources

Example Questions

Example Question #1 : How To Find Length Of A Line

Example Question #2 : How To Find Length Of A Line

Example Question #2 : How To Find Length Of A Line

Example Question #4 : How To Find Length Of A Line

Example Question #4 : How To Find Length Of A Line

Example Question #1 : Lines

Example Question #221 : Geometry

Example Question #181 : Plane Geometry

Example Question #182 : Plane Geometry

Example Question #2 : Lines

All SSAT Middle Level Math Resources

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