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SSAT Middle Level Math : How to find a ratio

Study concepts, example questions & explanations for SSAT Middle Level Math

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10 Diagnostic Tests 225 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #2 : Find A Percent Of A Quantity As A Rate Per 100: Ccss.Math.Content.6.Rp.A.3c

Red is a very popular car color. A production company manufactures cars and parks them in a lot behind the plant. There are 164 cars in the parking lot and $25 \%$ of them are red. How many red cars are in the parking lot?

Possible Answers:

Correct answer:

Explanation:

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means for every hundred. In the problem, we are told that $25\%$ of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

$25:100\rightarrow\frac{25}{100}$

Reduce.

$\frac{25}{100}\rightarrow \frac{1}{4}$

We know that there are 164 cars in the parking lot. We can write the following ratio by substituting the variable Red for the number of red cars:

$Red:164\rightarrow \frac{Red}{164}$

Now, we can create a proportion using our two ratios.

$\frac{1}{4}=\frac{Red}{164}$

Cross multiply and solve for Red .

$4 \times Red=1\times164$

Simplify.

4 Red=164

Divide both sides of the equation by .

$\frac{4Red}{4}=\frac{164}{4}$

Solve.

Red=41

There are red cars in the parking lot.

Report an Error

Example Question #5 : Find A Percent Of A Quantity As A Rate Per 100: Ccss.Math.Content.6.Rp.A.3c

Red is a very popular car color. A production company manufactures cars and parks them in a lot behind the plant. There are 135 cars in the parking lot and $60 \%$ of them are red. How many red cars are in the parking lot?

Possible Answers:

Correct answer:

Explanation:

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means for every hundred. In the problem, we are told that $60\%$ of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

$60:100\rightarrow\frac{60}{100}$

Reduce.

$\frac{60}{100}\rightarrow \frac{6}{10}\rightarrow \frac{3}{5}$

We know that there are 135 cars in the parking lot. We can write the following ratio by substituting the variable Red for the number of red cars:

$Red:135\rightarrow \frac{Red}{135}$

Now, we can create a proportion using our two ratios.

$\frac{3}{5}=\frac{Red}{135}$

Cross multiply and solve for Red .

$5 \times Red=3\times135$

Simplify.

5 Red=405

Divide both sides of the equation by .

$\frac{5Red}{5}=\frac{405}{5}$

Solve.

Red=81

There are red cars in the parking lot.

Report an Error

Example Question #745 : Ssat Middle Level Quantitative (Math)

Red is a very popular car color. A production company manufactures cars and parks them in a lot behind the plant. There are 400 cars in the parking lot and $40 \%$ of them are red. How many red cars are in the parking lot?

Possible Answers:

164

116

160

148

Correct answer:

160

Explanation:

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means for every hundred. In the problem, we are told that $40\%$ of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

$40:100\rightarrow\frac{40}{100}$

Reduce.

$\frac{40}{100}\rightarrow \frac{4}{10}\rightarrow \frac{2}{5}$

We know that there are 400 cars in the parking lot. We can write the following ratio by substituting the variable Red for the number of red cars:

$Red:400\rightarrow \frac{Red}{400}$

Now, we can create a proportion using our two ratios.

$\frac{2}{5}=\frac{Red}{400}$

Cross multiply and solve for Red .

$5 \times Red=2\times400$

Simplify.

5 Red=800

Divide both sides of the equation by .

$\frac{5Red}{5}=\frac{800}{5}$

Solve.

Red=160

There are 160 red cars in the parking lot.

Report an Error

Example Question #746 : Ssat Middle Level Quantitative (Math)

Red is a very popular car color. A production company manufactures cars and parks them in a lot behind the plant. There are 200 cars in the parking lot and $50 \%$ of them are red. How many red cars are in the parking lot?

Possible Answers:

120

100

102

210

120

Correct answer:

100

Explanation:

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means for every hundred. In the problem, we are told that $50\%$ of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

$50:100\rightarrow\frac{50}{100}$

Reduce.

$\frac{50}{100}\rightarrow \frac{5}{10}\rightarrow \frac{1}{2}$

We know that there are 200 cars in the parking lot. We can write the following ratio by substituting the variable Red for the number of red cars:

$Red:200\rightarrow \frac{Red}{200}$

Now, we can create a proportion using our two ratios.

$\frac{1}{2}=\frac{Red}{200}$

Cross multiply and solve for Red .

$2 \times Red=1\times200$

Simplify.

2 Red=200

Divide both sides of the equation by .

$\frac{2Red}{2}=\frac{200}{2}$

Solve.

Red=100

There are 100 red cars in the parking lot.

Report an Error

Example Question #747 : Ssat Middle Level Quantitative (Math)

Red is a very popular car color. A production company manufactures cars and parks them in a lot behind the plant. There are 300 cars in the parking lot and $30 \%$ of them are red. How many red cars are in the parking lot?

Possible Answers:

Correct answer:

Explanation:

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means for every hundred. In the problem, we are told that $30\%$ of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

$30:100\rightarrow\frac{30}{100}$

Reduce.

$\frac{30}{100}\rightarrow \frac{3}{10}$

We know that there are 300 cars in the parking lot. We can write the following ratio by substituting the variable Red for the number of red cars:

$Red:300\rightarrow \frac{Red}{300}$

Now, we can create a proportion using our two ratios.

$\frac{3}{10}=\frac{Red}{300}$

Cross multiply and solve for Red .

$10 \times Red=3\times300$

Simplify.

10 Red=900

Divide both sides of the equation by .

$\frac{10Red}{10}=\frac{900}{10}$

Solve.

Red=90

There are red cars in the parking lot.

Report an Error

Example Question #6 : Find A Percent Of A Quantity As A Rate Per 100: Ccss.Math.Content.6.Rp.A.3c

Red is a very popular car color. A production company manufactures cars and parks them in a lot behind the plant. There are 400 cars in the parking lot and $4 \%$ of them are red. How many red cars are in the parking lot?

Possible Answers:

Correct answer:

Explanation:

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means for every hundred. In the problem, we are told that $4\%$ of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

$4:100\rightarrow\frac{4}{100}$

Reduce.

$\frac{4}{100}\rightarrow \frac{2}{50}\rightarrow \frac{1}{25}$

We know that there are 400 cars in the parking lot. We can write the following ratio by substituting the variable Red for the number of red cars:

$Red:40\rightarrow \frac{Red}{400}$

Now, we can create a proportion using our two ratios.

$\frac{1}{25}=\frac{Red}{400}$

Cross multiply and solve for Red .

$25 \times Red=1\times400$

Simplify.

25 Red=400

Divide both sides of the equation by .

$\frac{25Red}{25}=\frac{400}{25}$

Solve.

Red=16

There are red cars in the parking lot.

Report an Error

Example Question #749 : Ssat Middle Level Quantitative (Math)

Red is a very popular car color. A production company manufactures cars and parks them in a lot behind the plant. There are 200 cars in the parking lot and $35 \%$ of them are red. How many red cars are in the parking lot?

Possible Answers:

Correct answer:

Explanation:

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means for every hundred. In the problem, we are told that $35\%$ of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

$35:100\rightarrow\frac{35}{100}$

Reduce.

$\frac{35}{100}\rightarrow \frac{7}{20}$

We know that there are 200 cars in the parking lot. We can write the following ratio by substituting the variable Red for the number of red cars:

$Red:200\rightarrow \frac{Red}{200}$

Now, we can create a proportion using our two ratios.

$\frac{7}{20}=\frac{Red}{200}$

Cross multiply and solve for Red .

$20 \times Red=7\times200$

Simplify.

20Red=1400

Divide both sides of the equation by .

$\frac{20Red}{20}=\frac{1400}{20}$

Solve.

Red=70

There are red cars in the parking lot.

Report an Error

Example Question #81 : Numbers And Operations

Red is a very popular car color. A production company manufactures cars and parks them in a lot behind the plant. There are 800 cars in the parking lot and $80\%$ of them are red. How many red cars are in the parking lot?

Possible Answers:

360

460

630

640

Correct answer:

640

Explanation:

We can use ratios and proportions to solve this problem. Percentages can be written as ratios. The word “percent” means for every hundred. In the problem, we are told that $80\%$ of the cars are red. In other words, for every hundred cars of them are red. We can write the following ratio:

$80:100\rightarrow\frac{80}{100}$

Reduce.

$\frac{80}{100}\rightarrow \frac{8}{10}\rightarrow \frac{4}{5}$

We know that there are 800 cars in the parking lot. We can write the following ratio by substituting the variable Red for the number of red cars:

$Red:800\rightarrow \frac{Red}{800}$

Now, we can create a proportion using our two ratios.

$\frac{4}{5}=\frac{Red}{800}$

Cross multiply and solve for Red .

$5 \times Red=4\times800$

Simplify.

5 Red=3200

Divide both sides of the equation by .

$\frac{5Red}{5}=\frac{3200}{5}$

Solve.

Red=640

There are 640 red cars in the parking lot.

Report an Error

Example Question #91 : New Sat Math Calculator

A carpenter is making a model house and he buys $8\textup{ feet}$ of crown moulding to use as accent pieces. He needs $9\textup{ inches}$ of the moulding for the house. How many feet of the material does he need to finish the model?

Possible Answers:

$\frac {3}{5} \textup{ feet}$

$\frac {3}{4} \textup{ feet}$

$\frac {1}{2} \textup{ feet}$

$\frac {2}{3} \textup{ feet}$

$\frac {1}{4} \textup{ feet}$

Correct answer:

$\frac {3}{4} \textup{ feet}$

Explanation:

We can solve this problem using ratios. There are $12\ inches$ in $1\ foot$ . We can write this relationship as the following ratio:

$12\ inches:1\ foot\rightarrow \frac{12\ inches}{1\ foot}$

We know that the carpenter needs $9 \ inches$ of material to finish the house. We can write this as a ratio using the variable to substitute the amount of feet.

$9\ inches:x\ feet\rightarrow \frac{9\ inches}{x\ feet}$

Now, we can solve for by creating a proportion using our two ratios.

$\frac{12\ inches}{1\ foot}=\frac{9\ inches}{x\ feet}$

Cross multiply and solve for .

$12\ inches \times (x\ feet)=9\ inches \times (1\ foot)$

Simplify.

12x=9

Divide both sides by .

$\frac{12x}{12}=\frac{9}{12}$

Solve.

$x=\frac{9}{12} \ feet$

Reduce.

$x=\frac{3}{4} \ feet$

The carpenter needs $\frac {3}{4} \ feet$ of material.

Report an Error

Example Question #3 : Solving Word Problems With One Unit Conversions

A carpenter is making a model house and he buys $8\textup{ feet}$ of crown moulding to use as accent pieces. He needs $24\textup{ inches}$ of the moulding for the house. How many feet of the material does he need to finish the model?

Possible Answers:

$2 \tfrac{1}{2}\textup{ feet}$

$1 \tfrac{1}{2}\textup{ feet}$

$2 \tfrac{3}{4}\textup{ feet}$

$2 \textup{ feet}$

$2 \tfrac{2}{3}\textup{ feet}$

Correct answer:

$2 \textup{ feet}$

Explanation:

We can solve this problem using ratios. There are $12\ inches$ in $1\ foot$ . We can write this relationship as the following ratio:

$12\ inches:1\ foot\rightarrow \frac{12\ inches}{1\ foot}$

We know that the carpenter needs $24\ inches$ of material to finish the house. We can write this as a ratio using the variable to substitute the amount of feet.

$24\ inches:x\ feet\rightarrow \frac{24\ inches}{x\ feet}$

Now, we can solve for by creating a proportion using our two ratios.

$\frac{12\ inches}{1\ foot}=\frac{24\ inches}{x\ feet}$

Cross multiply and solve for .

$12\ inches \times (x\ feet)=24\ inches \times (1\ foot)$

Simplify.

12x=24

Divide both sides by .

$\frac{12x}{12}=\frac{24}{12}$

Solve.

$x=2 \ feet$

The carpenter needs $2 \ feet$ of material.

Report an Error

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SSAT Middle Level Math : How to find a ratio

Study concepts, example questions & explanations for SSAT Middle Level Math

All SSAT Middle Level Math Resources

Example Questions

Example Question #2 : Find A Percent Of A Quantity As A Rate Per 100: Ccss.Math.Content.6.Rp.A.3c

Example Question #5 : Find A Percent Of A Quantity As A Rate Per 100: Ccss.Math.Content.6.Rp.A.3c

Example Question #745 : Ssat Middle Level Quantitative (Math)

Example Question #746 : Ssat Middle Level Quantitative (Math)

Example Question #747 : Ssat Middle Level Quantitative (Math)

Example Question #6 : Find A Percent Of A Quantity As A Rate Per 100: Ccss.Math.Content.6.Rp.A.3c

Example Question #749 : Ssat Middle Level Quantitative (Math)

Example Question #81 : Numbers And Operations

Example Question #91 : New Sat Math Calculator

Example Question #3 : Solving Word Problems With One Unit Conversions

All SSAT Middle Level Math Resources

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