SSAT Elementary Level Math : Rectangles

Study concepts, example questions & explanations for SSAT Elementary Level Math

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Example Questions

Example Question #151 : Rectangles

What is the length of a rectangular room with an area of \(\displaystyle 63ft^2\) and a width of \(\displaystyle 9ft?\)

 

Possible Answers:

\(\displaystyle 11ft\)

\(\displaystyle 7ft\)

\(\displaystyle 9ft\)

\(\displaystyle 8ft\)

\(\displaystyle 10ft\)

Correct answer:

\(\displaystyle 7ft\)

Explanation:

\(\displaystyle A=l\times w\)

We have the area and the width, so we can plug those values into our equation and solve for our unknown. 

\(\displaystyle 63=l\times 9\)

\(\displaystyle \frac{63}{9}=\frac{l\times 9}{9}\)

\(\displaystyle 7=l\)

Example Question #37 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular room with an area of \(\displaystyle 77ft^2\) and a width of \(\displaystyle 11ft?\)

 

Possible Answers:

\(\displaystyle 9ft\)

\(\displaystyle 10ft\)

\(\displaystyle 7ft\)

\(\displaystyle 8ft\)

\(\displaystyle 6ft\)

Correct answer:

\(\displaystyle 7ft\)

Explanation:

\(\displaystyle A=l\times w\)

We have the area and the width, so we can plug those values into our equation and solve for our unknown. 

\(\displaystyle 77=l\times 11\)

\(\displaystyle \frac{77}{11}=\frac{l\times 11}{11}\)

\(\displaystyle 7=l\)

Example Question #91 : Parallelograms

What is the length of a rectangular room with an area of \(\displaystyle 132ft^2\) and a width of \(\displaystyle 11ft?\)

 

Possible Answers:

\(\displaystyle 12ft\)

\(\displaystyle 10ft\)

\(\displaystyle 14ft\)

\(\displaystyle 11ft\)

\(\displaystyle 13ft\)

Correct answer:

\(\displaystyle 12ft\)

Explanation:

\(\displaystyle A=l\times w\)

We have the area and the width, so we can plug those values into our equation and solve for our unknown. 

\(\displaystyle 132=l\times 11\)

\(\displaystyle \frac{132}{11}=\frac{l\times 11}{11}\)

\(\displaystyle 12=l\)

Example Question #31 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular room with an area of \(\displaystyle 64ft^2\) and a width of \(\displaystyle 8ft?\)

 

Possible Answers:

\(\displaystyle 8ft\)

\(\displaystyle 5ft\)

\(\displaystyle 6ft\)

\(\displaystyle 9ft\)

\(\displaystyle 7ft\)

Correct answer:

\(\displaystyle 8ft\)

Explanation:

\(\displaystyle A=l\times w\)

We have the area and the width, so we can plug those values into our equation and solve for our unknown. 

\(\displaystyle 64=l\times 8\)

\(\displaystyle \frac{64}{8}=\frac{l\times 8}{8}\)

\(\displaystyle 8=l\)

Example Question #40 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular room with an area of \(\displaystyle 65ft^2\) and a width of \(\displaystyle 5ft?\)

 

Possible Answers:

\(\displaystyle 10ft\)

\(\displaystyle 13ft\)

\(\displaystyle 11ft\)

\(\displaystyle 12ft\)

\(\displaystyle 9ft\)

Correct answer:

\(\displaystyle 13ft\)

Explanation:

\(\displaystyle A=l\times w\)

We have the area and the width, so we can plug those values into our equation and solve for our unknown. 

\(\displaystyle 65=l\times 5\)

\(\displaystyle \frac{65}{5}=\frac{l\times 5}{5}\)

\(\displaystyle 13=l\)

Example Question #41 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular room with an area of \(\displaystyle 84ft^2\) and a width of \(\displaystyle 12ft?\)

 

Possible Answers:

\(\displaystyle 10ft\)

\(\displaystyle 9ft\)

\(\displaystyle 8ft\)

\(\displaystyle 7ft\)

\(\displaystyle 11ft\)

Correct answer:

\(\displaystyle 7ft\)

Explanation:

\(\displaystyle A=l\times w\)

We have the area and the width, so we can plug those values into our equation and solve for our unknown. 

\(\displaystyle 84=l\times 12\)

\(\displaystyle \frac{84}{12}=\frac{l\times 12}{12}\)

\(\displaystyle 7=l\)

Example Question #42 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular room with an area of \(\displaystyle 90ft^2\) and a width of \(\displaystyle 15ft?\)

 

Possible Answers:

\(\displaystyle 5ft\)

\(\displaystyle 6ft\)

\(\displaystyle 9ft\)

\(\displaystyle 7ft\)

\(\displaystyle 8ft\)

Correct answer:

\(\displaystyle 6ft\)

Explanation:

\(\displaystyle A=l\times w\)

We have the area and the width, so we can plug those values into our equation and solve for our unknown. 

\(\displaystyle 90=l\times 15\)

\(\displaystyle \frac{90}{15}=\frac{l\times 15}{15}\)

\(\displaystyle 6=l\)

Example Question #1341 : Common Core Math: Grade 4

What is the length of a rectangular room with an area of \(\displaystyle 96ft^2\) and a width of \(\displaystyle 8ft?\)

 

Possible Answers:

\(\displaystyle 12ft\)

\(\displaystyle 11ft\)

\(\displaystyle 13ft\)

\(\displaystyle 14ft\)

\(\displaystyle 10ft\)

Correct answer:

\(\displaystyle 12ft\)

Explanation:

\(\displaystyle A=l\times w\)

We have the area and the width, so we can plug those values into our equation and solve for our unknown. 

\(\displaystyle 96=l\times 8\)

\(\displaystyle \frac{96}{8}=\frac{l\times 8}{8}\)

\(\displaystyle 12=l\)

Example Question #101 : Parallelograms

What is the length of a rectangular room with an area of \(\displaystyle 20ft^2\) and a width of \(\displaystyle 4ft?\)

 

Possible Answers:

\(\displaystyle 4ft\)

\(\displaystyle 6ft\)

\(\displaystyle 5ft\)

\(\displaystyle 2ft\)

\(\displaystyle 3ft\)

Correct answer:

\(\displaystyle 5ft\)

Explanation:

\(\displaystyle A=l\times w\)

We have the area and the width, so we can plug those values into our equation and solve for our unknown. 

\(\displaystyle 20=l\times 4\)

\(\displaystyle \frac{20}{4}=\frac{l\times 4}{4}\)

\(\displaystyle 5=l\)

Example Question #45 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular room with an area of \(\displaystyle 48ft^2\) and a width of \(\displaystyle 4ft?\)

 

Possible Answers:

\(\displaystyle 10ft\)

\(\displaystyle 11ft\)

\(\displaystyle 8ft\)

\(\displaystyle 12ft\)

\(\displaystyle 9ft\)

Correct answer:

\(\displaystyle 12ft\)

Explanation:

\(\displaystyle A=l\times w\)

We have the area and the width, so we can plug those values into our equation and solve for our unknown. 

\(\displaystyle 48=l\times 4\)

\(\displaystyle \frac{48}{4}=\frac{l\times 4}{4}\)

\(\displaystyle 12=l\)

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