Using our problem to make a rectangular array, we know that we are going to use a total of $\displaystyle 99$ squares, and one dimension of the rectangular array is going to have $\displaystyle 9$ squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height. 

We can start with $\displaystyle 9$ squares and keep adding $\displaystyle 9$ on top of the previous $\displaystyle 9$ until we've used all $\displaystyle 99$ squares. Our rectangular array is $\displaystyle 11$ squares high. 

$\displaystyle 99\div9=11$

Using our problem to make a rectangular array, we know that we are going to use a total of $\displaystyle 117$ squares, and one dimension of the rectangular array is going to have $\displaystyle 9$ squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height. 

We can start with $\displaystyle 9$ squares and keep adding $\displaystyle 9$ on top of the previous $\displaystyle 9$ until we've used all $\displaystyle 117$ squares. Our rectangular array is $\displaystyle 13$ squares high. 

$\displaystyle 117\div9=13$

Using our problem to make a rectangular array, we know that we are going to use a total of $\displaystyle 29$ squares, and one dimension of the rectangular array is going to have $\displaystyle 3$ squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height. 

We can start with $\displaystyle 3$ squares and keep adding $\displaystyle 3$ on top of the previous $\displaystyle 3$ until we've used all $\displaystyle 29$ squares. Our rectangular array is $\displaystyle 9$ squares high with $\displaystyle 2$ squares left over, which is our remainder.

$\displaystyle 29\div3=9\ R2$

Using our problem to make a rectangular array, we know that we are going to use a total of $\displaystyle 19$ squares, and one dimension of the rectangular array is going to have $\displaystyle 3$ squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height. 

We can start with $\displaystyle 3$ squares and keep adding $\displaystyle 3$ on top of the previous $\displaystyle 3$ until we've used all $\displaystyle 19$ squares. Our rectangular array is $\displaystyle 6$ squares high with $\displaystyle 1$ square left over, which is our remainder. 

$\displaystyle 19\div3=6\ R1$

Using our problem to make a rectangular array, we know that we are going to use a total of $\displaystyle 50$ squares, and one dimension of the rectangular array is going to have $\displaystyle 4$ squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height. 

We can start with $\displaystyle 4$ squares and keep adding $\displaystyle 4$ on top of the previous $\displaystyle 4$ until we've used all $\displaystyle 50$ squares. Our rectangular array is $\displaystyle 12$ squares high with $\displaystyle 2$ sqaures left over, which is our remainder. 

$\displaystyle 50\div4=12\ R2$

Using our problem to make a rectangular array, we know that we are going to use a total of $\displaystyle 63$ squares, and one dimension of the rectangular array is going to have $\displaystyle 4$ squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height. 

We can start with $\displaystyle 4$ squares and keep adding $\displaystyle 4$ on top of the previous $\displaystyle 4$ until we've used all $\displaystyle 63$ squares. Our rectangular array is $\displaystyle 15$ squares high with $\displaystyle 3$ squares left over, which is our remainder. 

$\displaystyle 63\div4=15\ R3$

Using our problem to make a rectangular array, we know that we are going to use a total of $\displaystyle 73$ squares, and one dimension of the rectangular array is going to have $\displaystyle 5$ squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height. 

We can start with $\displaystyle 5$ squares and keep adding $\displaystyle 5$ on top of the previous $\displaystyle 5$ until we've used all $\displaystyle 73$ squares. Our rectangular array is $\displaystyle 14$ squares high with $\displaystyle 3$ squares left over, which is our remainder. 

$\displaystyle 73\div5=14\ R3$

Using our problem to make a rectangular array, we know that we are going to use a total of $\displaystyle 89$ squares, and one dimension of the rectangular array is going to have $\displaystyle 6$ squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height. 

We can start with $\displaystyle 6$ squares and keep adding $\displaystyle 6$ on top of the previous $\displaystyle 6$ until we've used all $\displaystyle 89$ squares. Our rectangular array is $\displaystyle 14$ squares high with $\displaystyle 5$ quares left over, which is our remainder. 

$\displaystyle 89\div6=14 R\5$

Using our problem to make a rectangular array, we know that we are going to use a total of $\displaystyle 45$ squares, and one dimension of the rectangular array is going to have $\displaystyle 6$ squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height. 

We can start with $\displaystyle 6$ squares and keep adding $\displaystyle 6$ on top of the previous $\displaystyle 6$ until we've used all $\displaystyle 45$ squares. Our rectangular array is $\displaystyle 7$ squares high with $\displaystyle 3$ squares left over, which is our remainder. 

$\displaystyle 45\div6=7\ R3$

Using our problem to make a rectangular array, we know that we are going to use a total of $\displaystyle 91$ squares, and one dimension of the rectangular array is going to have $\displaystyle 6$ squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height. 

We can start with $\displaystyle 6$ squares and keep adding $\displaystyle 6$ on top of the previous $\displaystyle 6$ until we've used all $\displaystyle 91$ squares. Our rectangular array is $\displaystyle 15$ squares high with $\displaystyle 1$ square left over, which is our remainder. 

$\displaystyle 91\div6=15\ R1$