When we have a set of something that we are splitting up into groups, we divide. In this case, we are dividing students up into cars. We will let \(\displaystyle c\) represent the number of cars they will need.

\(\displaystyle 31\div5=c\)

\(\displaystyle \frac{\begin{array}[b]{r} \ 6\\ 5{\overline{\smash{)}31}}\\ -\ 30\end{array}}{ \ \ \ \space}\)

           \(\displaystyle 1\)

Our answer is \(\displaystyle 6\) with a remainder of \(\displaystyle 1\). This means that they will have \(\displaystyle 6\) full cars of \(\displaystyle 5\) people, but there is \(\displaystyle 1\) person left over. So they need \(\displaystyle 7\) cars in order for every student to be in a car. 

When we have a set of something that we are splitting up into groups, we divide. In this case, we are dividing students up into cars. We will let \(\displaystyle c\) represent the number of cars they will need.

\(\displaystyle 63\div5=c\)

\(\displaystyle \frac{\begin{array}[b]{r} \ 12\\ 5{\overline{\smash{)}63}}\\ -\ 60\end{array}}{ \ \ \ \ \ 3}\)

Our answer is \(\displaystyle 12\) with a remainder of \(\displaystyle 3\). This means that they will have \(\displaystyle 12\) full cars of \(\displaystyle 5\) people, but there are \(\displaystyle 3\) people left over. So they need \(\displaystyle 13\) cars in order for every student to be in a car. 

The computation shows that \(\displaystyle 284\div4=71\) with a remainder of \(\displaystyle 0\).

\(\displaystyle \frac{\begin{array}[b]{r} \ {\color{Green} 71}\\ {\color{Green} 4}{\overline{\smash{)}284}}\\ -\ 28 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }\)

                  \(\displaystyle 0\)

So it must be that:

\(\displaystyle 4\times71=284+0\)

Simplify.

\(\displaystyle 4\times71=284\)

The correct answer is \(\displaystyle 4\times 71\)

When we have a set of something that we are splitting up into groups, we divide. In this case, we are dividing students up into cars. We will let \(\displaystyle c\) represent the number of cars they will need.

\(\displaystyle 26\div5=c\)

\(\displaystyle \frac{\begin{array}[b]{r} \ 5\\ 5{\overline{\smash{)}26}}\\ -\ 25\end{array}}{ \ \ \ \ \ 1}\)

Our answer is \(\displaystyle 5\) with a remainder of \(\displaystyle 1\). This means that they will have \(\displaystyle 5\) full cars of \(\displaystyle 5\) people, but there is \(\displaystyle 1\) person left over. So they need \(\displaystyle 6\) cars in order for every student to be in a car. 

When we have a set of something that we are splitting up into groups, we divide. In this case, we are dividing students up into cars. We will let \(\displaystyle c\) represent the number of cars they will need.

\(\displaystyle 36\div5=c\)

\(\displaystyle \frac{\begin{array}[b]{r} \ 7\\ 5{\overline{\smash{)}36}}\\ -\ 35\end{array}}{ \ \ \ \ \ 1}\)

Our answer is \(\displaystyle 7\) with a remainder of \(\displaystyle 1\). This means that they will have \(\displaystyle 7\) full cars of \(\displaystyle 5\) people, but there is \(\displaystyle 1\) person left over. So they need \(\displaystyle 8\) cars in order for every student to be in a car. 

The computation shows that \(\displaystyle 324\div4=81\) with a remainder of \(\displaystyle 0\).

\(\displaystyle \frac{\begin{array}[b]{r} \ {\color{Green} 81}\\ {\color{Green} 4}{\overline{\smash{)}324}}\\ -\ 32 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }\)

                  \(\displaystyle 0\)

So it must be that:

\(\displaystyle 4\times81=324+0\)

Simplify.

\(\displaystyle 4\times81=324\)

The correct answer is \(\displaystyle 4\times 81\)

When we have a set of something that we are splitting up into groups, we divide. In this case, we are dividing students up into cars. We will let \(\displaystyle c\) represent the number of cars they will need.

\(\displaystyle 46\div4=c\)

\(\displaystyle \frac{\begin{array}[b]{r} \ 11\\ 4{\overline{\smash{)}46}}\\ -\ 44\end{array}}{ \ \ \ \ \ 2}\)     

Our answer is \(\displaystyle 11\) with a remainder of \(\displaystyle 2\). This means that they will have \(\displaystyle 11\) full cars of \(\displaystyle 4\) people, but there are \(\displaystyle 2\) people left over. So they need \(\displaystyle 12\) cars in order for every student to be in a car. 

When we have a set of something that we are splitting up into groups, we divide. In this case, we are dividing students up into cars. We will let \(\displaystyle c\) represent the number of cars they will need.

\(\displaystyle 18\div4=c\)

\(\displaystyle \frac{\begin{array}[b]{r} \ 4\\ 4{\overline{\smash{)}18}}\\ -\ 16\end{array}}{ \ \ \ \ \ 2}\)     

Our answer is \(\displaystyle 4\) with a remainder of \(\displaystyle 2\). This means that they will have \(\displaystyle 4\) full cars of \(\displaystyle 4\) people, but there are \(\displaystyle 2\) people left over. So they need \(\displaystyle 5\) cars in order for every student to be in a car. 

When we have a set of something that we are splitting up into groups, we divide. In this case, we are dividing students up into cars. We will let \(\displaystyle c\) represent the number of cars they will need.

\(\displaystyle 13\div4=c\)

\(\displaystyle \frac{\begin{array}[b]{r} \ 3\\ 4{\overline{\smash{)}13}}\\ -\ 12\end{array}}{ \ \ \ \ \ 1}\)     

Our answer is \(\displaystyle 3\) with a remainder of \(\displaystyle 1\). This means that they will have \(\displaystyle 3\) full cars of \(\displaystyle 4\) people, but there is \(\displaystyle 1\) person left over. So they need \(\displaystyle 4\) cars in order for every student to be in a car. 

When we have a set of something that we are splitting up into groups, we divide. In this case, we are dividing students up into cars. We will let \(\displaystyle c\) represent the number of cars they will need.

\(\displaystyle 10\div4=c\)

\(\displaystyle \frac{\begin{array}[b]{r} \ 2\\ 4{\overline{\smash{)}10}}\\ -\ 8\end{array}}{ \ \ \ \ 2}\)     

Our answer is \(\displaystyle 2\) with a remainder of \(\displaystyle 2\). This means that they will have \(\displaystyle 2\) full cars of \(\displaystyle 4\) people, but there are \(\displaystyle 2\) people left over. So they need \(\displaystyle 3\) cars in order for every student to be in a car.