Let's think of the exams in terms of 100 points for a 100%. This means that the first 20 students received 20 * 83 or 1660 points.

Now, we must figure out how many points would be necessary for 23 students to have an average of exactly 84%. That would be found using the equation for a mean:

x / 23 = 84 → x = 1932

That means that our 3 students had to get a total of 1932 – 1660, or 272 points. The only answer that matches that among our answers is 84%, 92%, and 96%.

Convert each term, so a = a, b = a/2, c = a/4, and d = a/8

so then the average would be (a + a/2 + a/4 + a/8)/4

= (8a/8 + 4a/8 + 2a/8 + a/8)/4

= (15a/8)/4 = 15a/32

Let's let a, b, c, d, e, f, g, h, i, and j represent the integers in the set from least to greatest.

The set has an even number of integers. This means that the median will have to be the average of the two numbers in the middle. The middle numbers will have to be the fifth and the sixth numbers, which are represented by e and f. This means that the average of e and f must be –2.5. Because –2.5 is halfway between –3 and –2, this means e is –3 and f is –2. Our set looks like this so far:

a, b, c, d, -3, -2, g, h, i, j

Because the set consists of consecutive integers, each term must equal one more than the one before it. So, g, h, i, and j are the four numbers are –2, and a, b, c, and d are the four numbers before –3. Thus, our set is as follows:

–7, –6, –5, –4, –3, –2, –1, 0, 1, 2

The question asks us to find the mean, which is the sum of the elements in the set divided by the number of elements in the set.

The sum of the numbers in the set is –7 + –6 + –5 + . . . 1 + 2 = –25.

Because there are ten numbers in the set, the mean of the set is –25/10 = –2.5.

The answer is –2.5.

If the average of two numbers is 22, and the average of two more numbers is 22, the average of all of them will be 22.

Begin by writing out the values of our numbers.

Number 1: x (since it is our reference point for all the other numbers)

Number 2: 2x (simple from the problem)

Number 3: 3x + 2 (two more [i.e. + 2] than three times the first [i.e. 3x])

Number 4: 5 * (Number 3) = 5 (3x + 2) = 15x + 10

Now, to find the mean, we need to add together all of these three values and divide them by four. Their sum is:

x + 2x + 3x + 2 + 15x + 10 = 21x + 12

The mean is (21x + 12)/4 = (21x/4) + (12/4) = (21x/4) + 3

You multiply the number of hours that Jack went 70 mph by 3 hours, multiply the hours he went 55 by 5 hours, and add the totals giving you a total of 485 miles. You then divide this by 8 hours, giving you 60.625, rounding to 61 mph. 

You solve each variable in terms of i, giving you j = i/2 and k = i/5, then add both to i, giving you 17i/10 and then divide by 3 giving you 17i/30.

To find her average grade for the class, we need to multiply Mary's test scores by their corresponding weights and then add them up.

The five quizzes were each worth 10%, or 0.1, of her grade, and the midterm and final were both worth 25%, or 0.25.

average = (0.1 * 89) + (0.1 * 74) + (0.1 * 84) + (0.1 * 92) + (0.1 * 90) + (0.25 * 92) + (0.25 * 91) = 88.95 = 89. 

Looking at the answer choices, they are all spaced 2 percentage points apart, so clearly the closest answer choice to 88.95 is 89. 

Let's find out what values the function takes for the given x-values.

f(–1) = 3(–1) + 2 = –1

f(0) = 2, f(2) = 8, f(5) = 17, f(9) = 29

We're told that the function takes these different values with equal probability, so to find the average we need to sum up the f(x) terms and divide by the number of terms, 5.

average = (–1 + 2 + 8 + 17 + 29) / 5 = 11

To find the average number of points, we need to multiply the points by their corresponding weights and sum them up. 

Average = 1/5 * 25 + 3/5 * 50 + 1/5 * 0 = 35.