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SAT Math : Squares

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Example Questions

Example Question #1 : How To Find The Area Of A Square

ABCD and EFGH are squares such that the perimeter of ABCD is 3 times that of EFGH. If the area of EFGH is 25, what is the area of ABCD?

Possible Answers:

225

Correct answer:

225

Explanation:

Assign variables such that

One side of ABCD = a

and One side of EFGH = e

Note that all sides are the same in a square. Since the perimeter is the sum of all sides, according to the question:

4a = 3 x 4e = 12e or a = 3e

From that area of EFGH is 25,

e x e = 25 so e = 5

Substitute a = 3e so a = 15

We aren’t done. Since we were asked for the area of ABCD, this is a x a = 225.

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Example Question #1 : Squares

A square has an area of 36. If all sides are doubled in value, what is the new area?

Possible Answers:

144

108

132

Correct answer:

144

Explanation:

Let S be the original side length. S*S would represent the original area. Doubling the side length would give you 2S*2S, simplifying to 4*(S*S), giving a new area of 4x the original, or 144.

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Example Question #1 : Squares

Freddie is building a square pen for his pig. He plans to buy x feet of fencing to build the pen. This will result in a pen with an area of p square feet. Unfortunately, he only has enough money to buy one third of the planned amount of fencing. Which expression represents the area of the pen he can build with this limited amount of fencing?

Possible Answers:

p/3

p/6

p/9

Correct answer:

p/9

Explanation:

If Freddie uses x feet of fencing makes a square, each side must be x/4 feet long. The area of this square is (x/4)² = x²/16 = p square feet.

If Freddie uses one third of x feet of fencing makes a square, each side must be x/12 feet long. The area of this square is (x/12)² = x²/144 = 1/9(x²/16) = 1/9(p) = p/9 square feet.

Alternate method:

The scale factor between the small perimeter and the larger perimeter = 1 : 3. Since we're comparing area, a two-dimensional measurement, we can square the scale factor and see that the ratio of the areas is 1²: 3² = 1 : 9.

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Example Question #1 : How To Find The Area Of A Square

If the diagonal of a square measures $16\sqrt{2} \ cm$ , what is the area of the square?

Possible Answers:

$256\ cm^{2}$

$512\ cm^{2}$

$128\ cm^{2}$

$64\sqrt{2}\ cm^{2}$

$32\sqrt{2}\ cm^{2}$

Correct answer:

$256\ cm^{2}$

Explanation:

This is an isosceles right triangle, so the diagonal must equal $\sqrt{2}$ times the length of a side. Thus, one side of the square measures $16\ cm$ , and the area is equal to $(16 \ cm)^{2} = 256\ cm^{2}$

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Example Question #2 : Squares

A square $A$ has side lengths of $z$ . A second square $B$ has side lengths of $2.25z$ . How many $A's$ can you fit in a single $B$ ?

Possible Answers:

$3$

$2.25$

$5.06$

$4$

$1$

Correct answer:

$5.06$

Explanation:

The area of $A$ is $n$ , the area of $B$ is $5.0625n$ . Therefore, you can fit 5.06 $A's$ in $B$ .

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Example Question #3 : How To Find The Area Of A Square

The perimeter of a square is $12\ in.$ If the square is enlarged by a factor of three, what is the new area?

Possible Answers:

$81\ in.^{2}$

$48\ in.^{2}$

$36\ in.^{2}$

$27\ in.^{2}$

$9\ in.^{2}$

Correct answer:

$81\ in.^{2}$

Explanation:

The perimeter of a square is given by $P=4s=12$ so the side length of the original square is $3\ in.$ The side of the new square is enlarged by a factor of 3 to give $s=9\ in.$

So the area of the new square is given by $A = s^{2} = (9)^{2} = 81 in^{2}$ .

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Example Question #3 : Squares

A half circle has an area of $18\pi$ . What is the area of a square with sides that measure the same length as the diameter of the half circle?

Possible Answers:

108

144

Correct answer:

144

Explanation:

If the area of the half circle is $18\pi$ , then the area of a full circle is twice that, or $36\pi$ .

Use the formula for the area of a circle to solve for the radius:

36π = πr²

r = 6

If the radius is 6, then the diameter is 12. We know that the sides of the square are the same length as the diameter, so each side has length 12.

Therefore the area of the square is 12 x 12 = 144.

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Example Question #41 : Quadrilaterals

In square WXYZ, point Q is the midpoint of side WZ. If the area of quadrilateral WXYQ is $\frac{1}{12}$ , what is the length of one side of square WXYZ?

Possible Answers:

$\frac{1}{3}$

$\frac{1}{9}$

$\frac{1}{2}$

$\frac{1}{6}$

$\frac{1}{12}$

Correct answer:

$\frac{1}{3}$

Explanation:

Let equal the length of one side of the square. Drawing a diagram yields WXYQ is a trapezoid with two right angles, parallel bases of and $\frac{1}{2}s$ , and a height of .

Area of WXYQ = $\frac{s+\frac{1}{2} s}{2}\cdot s=\frac{\frac{3}{2} s}{2}\cdot s =\frac{3}{4} s^2=\frac{1}{12}$

$\frac{4}{3} \cdot \frac{3}{4} s^2=\frac{1}{12} \cdot \frac{4}{3}$

$s^2=\frac{1}{9}$

$s=\frac{1}{3}$

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Example Question #7 : Squares

Four perfect circles with equal dimensions fit perfectly in a square with a length and width of $4\:cm$ . What is the area of the space inside the square that does not include the circles? (Use 3.14 for the value of $\pi$ .)

Varsity_sat_problems

Possible Answers:

$2.00\:cm^2$

$16.00\:cm^2$

$12.86\:cm^2$

$3.44\:cm^2$

$9.13\:cm^2$

Correct answer:

$3.44\:cm^2$

Explanation:

Solving for the area not occupied by circles involves subtracting the area of all four circles from the total area of the square, so let's start by calculating the area of the square. We are told that it has a length and width of $4\:cm$ , so we just need to multiply these together:

$Area_{square} = 4\:cm\cdot 4\:cm=16\:cm^{2}$

Now, we need to calculate the area of one of the circles. Since the four circles fit perfectly into the square, each one has a diameter of $2\:cm$ and a radius of $1\:cm$ , because 2+2=4 and the square's sides are each $4\:cm$ long.

Knowing this, we can calculate the area of one of the circles using the equation for the area of a circle, $A_{circle}=\pi r^2$ . Substituting in $1\:cm$ for the value of the radius of one of the circles, we get:

$Area_{circle}=\pi\cdot (1\:cm)^{2}$

$Area_{circle}=\pi\cdot 1\:cm^2$

$Area_{circle}=\pi\:cm^2$

Now, we can multiply our result by to calculate the area encompassed by the four circles together and subtract that value from the area of the square to find the answer:

$Area_{four\:circles}=4\cdot \pi\:cm^2$

$Area_{four\:circles}=4\pi\:cm^2$

$Area_{square}-Area_{four\:circles}=16\:cm^2-4\pi\:cm^2$

$Area_{square}-Area_{four\:circles}=16\:cm^2-4(3.14)\:cm^2$

$Area_{square}-Area_{four\:circles}=16\:cm^2-12.56\:cm^2$

$Area_{square}-Area_{four\:circles}= 3.44\:cm^2$

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Example Question #1 : Squares

Find the area of a square with side length 4.

Possible Answers:

Correct answer:

Explanation:

To solve, simply use the formula for the area of a square.

Substitute the side length of four into the following equation.

Thus,

A=s^2=4^2=16

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SAT Math : Squares

Study concepts, example questions & explanations for SAT Math

All SAT Math Resources

Example Questions

Example Question #1 : How To Find The Area Of A Square

Example Question #1 : Squares

Example Question #1 : Squares

Example Question #1 : How To Find The Area Of A Square

Example Question #2 : Squares

Example Question #3 : How To Find The Area Of A Square

Example Question #3 : Squares

Example Question #41 : Quadrilaterals

Example Question #7 : Squares

Example Question #1 : Squares

All SAT Math Resources

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