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SAT Math : How to find the length of the side of a trapezoid

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Example Question #3 : Quadrilaterals

Square 1

The above figure shows Square ABCD . is the midpoint of $\overline{AB}$ ; is the midpoint of $\overline{CD}$ ; is the midpoint of $\overline{CN}$ . Construct $\overline{MO}$ .

AM = t . Which of the following expresses the length of $\overline{MO}$ in terms of ?

Possible Answers:

$\frac{\sqrt{15}}{4} t$

$\frac{\sqrt{65}}{8} t$

$\frac{\sqrt{17}}{4} t$

$\frac{\sqrt{63}}{8} t$

$\frac{\sqrt{5}}{2} t$

Correct answer:

$\frac{\sqrt{17}}{4} t$

Explanation:

Construct $\overline{MN}$ as shown in the diagram below:

Square 1

Quadrilateral AMND is a rectangle, so opposite sides are congruent. Therefore, MN = AD = t .

Since is the midpoint of $\overline{CD}$ ,

$CN = \frac{1}{2} CD = \frac{1}{2} t$

Since is the midpoint of $\overline{CN}$ ,

$ON = \frac{1}{2} CN = \frac{1}{2} \cdot \frac{1}{2} t = \frac{1}{4} t$ .

$\bigtriangleup MNO$ is a right triangle, so, by the Pythagorean Theorem,

$MO = \sqrt{(MN)^{2}+(NO)^{2} }$

Substituting:

$MO= \sqrt{t^{2}+\left (\frac{1}{4}t \right)^{2} }$

$MO= \sqrt{t^{2}+ \frac {1}{16} t ^{2} }$

$MO= \sqrt{ \frac {17}{16} t ^{2} }$

Apply the Product of Radicals and Quotient of Radicals Rules:

$MO= \sqrt{ \frac {17}{16} t ^{2} }$

$= \sqrt{ \frac {17}{16} } \cdot \sqrt{t^{2}}$

$= \sqrt{ \frac {17}{16} } t$

$= \frac { \sqrt{17}}{ \sqrt{16}} \cdot t$

$= \frac { \sqrt{17}}{4} t$

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SAT Math : How to find the length of the side of a trapezoid

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Example Question #3 : Quadrilaterals

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