SAT Math : Geometry

Study concepts, example questions & explanations for SAT Math

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Example Questions

Example Question #112 : Triangles

Which of the following measurements can NOT represent the sides of a triangle. 

Possible Answers:

Correct answer:

Explanation:

Given the Triangle Inequality, the sum of any two sides of a triangle must be greater than the third side. 

Given the measurements :

Therefore, these lengths cannot represent a triangle. 

Example Question #335 : Plane Geometry

If triangle ABC has vertices (0, 0), (6, 0), and (2, 3) in the xy-plane, what is the area of ABC?

Possible Answers:

20

18

9

12

10

Correct answer:

9

Explanation:

Sat-triangle

Sketching ABC in the xy-plane, as pictured here, we see that it has base 6 and height 3. Since the formula for the area of a triangle is 1/2 * base * height, the area of ABC is 1/2 * 6 * 3 = 9.

Example Question #871 : High School Math

The height, , of triangle  in the figure is one-fourth the length of . In terms of h, what is the area of triangle ?

Vt_p5

 

Possible Answers:

3h^{2}

2h^{2}

h^{2}

\frac{1}{2}h^{2}

Correct answer:

2h^{2}

Explanation:

If \dpi{100} \small h=\frac{1}{4} *\dpi{100} \small \overline{PQ}, then the length of \dpi{100} \small \overline{PQ} must be \dpi{100} \small 4h.

Using the formula for the area of a triangle (\frac{1}{2}bh), with \dpi{100} \small b=4h, the area of the triangle must be 2h^{2}.

Example Question #143 : Sat Mathematics

Find the height of a triangle if the area of the triangle = 18 and the base = 4.

Possible Answers:

9

1

4

6

Correct answer:

9

Explanation:

The area of a triangle = (1/2)bh where b is base and h is height. 18 = (1/2)4h which gives us 36 = 4h so h =9.

Example Question #351 : Geometry

 and  are similar triangles.  The perimeter of Triangle A is 45” and the length of two of its sides are 15” and 10”.  If the perimeter of Triangle B is 135” and what are lengths of two of its sides?

Possible Answers:

Correct answer:

Explanation:

The perimeter is equal to the sum of the three sides.  In similar triangles, each side is in proportion to its correlating side.  The perimeters are also in equal proportion.

Perimeter A = 45” and perimeter B = 135”

The proportion of Perimeter A to Perimeter B is

This applies to the sides of the triangle.  Therefore to get the any side of Triangle B, just multiply the correlating side by 3.

15” x 3 = 45”

10” x 3 = 30“

 

 

Screen shot 2016 02 16 at 10.45.30 am

Example Question #71 : Triangles

A triangle has sides of length 8, 13, and L. Which of the following cannot equal L?

Possible Answers:

4

9

6

15

7

Correct answer:

4

Explanation:

The sum of the lengths of two sides of a triangle cannot be less than the length of the third side. 8 + 4 = 12, which is less than 13.

Example Question #2 : How To Find The Length Of The Side Of An Acute / Obtuse Triangle

Two sides of a triangle are 20 and 32.  Which of the following CANNOT be the third side of this triangle.

Possible Answers:

13

20

17

10

15

Correct answer:

10

Explanation:

Please remember the Triangle Inequality Theorem, which states that the sum of any two sides of a triangle must be greater than the third side.  Therefore, the correct answer is 10 because the sum of 10 and 20 would not be greater than the third side 32.

Example Question #146 : Sat Mathematics

A triangle has sides of length 5, 7, and x. Which of the following can NOT be a value of x?

Possible Answers:

5

11

3

7

13

Correct answer:

13

Explanation:

The sum of the lengths of any two sides of a triangle must exceed the length of the third side; therefore, 5+7 > x, which cannot happen if x = 13.

Example Question #1 : How To Find The Length Of The Side Of An Acute / Obtuse Triangle

The lengths of two sides of a triangle are 9 and 7. Which of the following could be the length of the third side?

Possible Answers:

17

2

1

16

12

Correct answer:

12

Explanation:

Let us call the third side x. According to the Triangle Inequality Theorem, the sum of any two sides of a triangle must be larger than the other two sides. Thus, all of the following must be true:

x + 7 > 9

x + 9 > 7

7 + 9 > x

We can solve these three inequalities to determine the possible values of x.

x + 7 > 9

Subtract 7 from both sides.

x > 2

Now, we can look at x + 9 > 7. Subtracting 9 from both sides, we obtain

x > –2

Finally, 7 + 9 > x, which means that 16 > x.

Therefore, x must be greater than 2, greater than –2, but also less than 16. The only number that satisfies all of these requirements is 12.

The answer is 12. 

Example Question #561 : Geometry

The lengths of a triangle are 8, 12, and x. Which of the following inequalities shows all of the possible values of x?

Possible Answers:

4 < x <12

4 ≤ x ≤ 20

4 ≤ x ≤12

4 < x < 20

8 < x < 12

Correct answer:

4 < x < 20

Explanation:

According to the Triangle Inequality Theorem, the sum of any two sides of a triangle must be greater (not greater than or equal) than the remaining side. Thus, the following inequalities must all be true:

x + 8 > 12

x + 12 > 8

8 + 12 > x

Let's solve each inequality.

x + 8 > 12

Subtract 8 from both sides.

x > 4

Next, let's look at the inequality x + 12 > 8

x + 12 > 8

Subtract 12 from both sides.

x > –4

Lastly, 8 + 12 > x, which means that x < 20.

This means that x must be less than twenty, but greater than 4 and greater than –4. Since any number greater than 4 is also greater than –4, we can exclude the inequality x > –4.

To summarize, x must be greater than 4 and less than 20. We can write this as 4 < x < 20. 

The answer is 4 < x < 20.

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