All SAT Math Resources
Example Questions
Example Question #3 : Squaring / Square Roots / Radicals
Simplify:
If you don't already have the pattern memorized, use FOIL. It's best to write out the parentheses twice (as below) to avoid mistakes:
Example Question #581 : Algebra
x2 = 36
Quantity A: x
Quantity B: 6
Quantity A is greater
The two quantities are equal
Quantity B is greater
The relationship cannot be determined from the information given
The relationship cannot be determined from the information given
x2 = 36 -> it is important to remember that this leads to two answers.
x = 6 or x = -6.
If x = 6: A = B.
If x = -6: A < B.
Thus the relationship cannot be determined from the information given.
Example Question #3 : Squaring / Square Roots / Radicals
According to Heron's Formula, the area of a triangle with side lengths of a, b, and c is given by the following:
where s is one-half of the triangle's perimeter.
What is the area of a triangle with side lengths of 6, 10, and 12 units?
48√77
4√14
14√2
8√14
12√5
8√14
We can use Heron's formula to find the area of the triangle. We can let a = 6, b = 10, and c = 12.
In order to find s, we need to find one half of the perimeter. The perimeter is the sum of the lengths of the sides of the triangle.
Perimeter = a + b + c = 6 + 10 + 12 = 28
In order to find s, we must multiply the perimeter by one-half, which would give us (1/2)(28), or 14.
Now that we have a, b, c, and s, we can calculate the area using Heron's formula.
Example Question #181 : New Sat
Simplify the radical expression.
Look for perfect cubes within each term. This will allow us to factor out of the radical.
Simplify.
Example Question #582 : Algebra
Simplify the expression.
Use the distributive property for radicals.
Multiply all terms by .
Combine terms under radicals.
Look for perfect square factors under each radical. has a perfect square of . The can be factored out.
Since both radicals are the same, we can add them.
Example Question #4 : Squaring / Square Roots / Radicals
Which of the following expression is equal to
When simplifying a square root, consider the factors of each of its component parts:
Combine like terms:
Remove the common factor, :
Pull the outside of the equation as :
Example Question #5 : Squaring / Square Roots / Radicals
Which of the following is equal to the following expression?
First, break down the components of the square root:
Combine like terms. Remember, when multiplying exponents, add them together:
Factor out the common factor of :
Factor the :
Combine the factored with the :
Now, you can pull out from underneath the square root sign as :
Example Question #6 : Squaring / Square Roots / Radicals
Which of the following expressions is equal to the following expression?
First, break down the component parts of the square root:
Combine like terms in a way that will let you pull some of them out from underneath the square root symbol:
Pull out the terms with even exponents and simplify:
Example Question #1 : Complex Numbers
From , subtract its complex conjugate. What is the difference ?
The complex conjugate of a complex number is , so has as its complex conjugate. Subtract the latter from the former:
Example Question #2 : Complex Numbers
From , subtract its complex conjugate.
The complex conjugate of a complex number is . Therefore, the complex conjugate of is ; subtract the latter from the former by subtracting real parts and subtracting imaginary parts, as follows: