All SAT Math Resources
Example Questions
Example Question #25 : Systems Of Equations
Let be the point of intersection between the lines given by the equations and . What is the slope of the line that passes through and the origin?
In order to solve this system of equations, it will probably be best to use the elimination method, in which we add or subtract two equations. In general, if , and , then . In other words, we can combine equations.
We need to solve the following equations:
We want to look for a way to combine these two equations that will eliminate at least one variable. If, for example, we multiplied the first equation by and then added this to the second equation, we could get rid of the terms. Let's multiply the first equation by . Remember, we must multiply both sides.
Distribute the .
We can now add to the equation . The sum of the left sides of each equation will equal the sum of the right sides.
We can simplify both sides. Notice that the terms on the left disappear, leaving only terms.
Divide both sides by 3.
.
Now that we have , we can go back to either of our original two equations, substitute the value of we obtained, and solve for . Let's use the equation .
Substitute for .
Add to both sides. We will need to rewrite 4 with a denominator of 3.
Divide by 2 on both sides. When dividing a fraction, we simply multiply by its reciprocal.
Point , which is the intersection of the lines, must have the coordinates .
The question ultimately asks for the slope of the line passing through and the origin. We can use the equation of the slope between two points with coordinates and .
slope =
The answer is .
Example Question #24 : Systems Of Equations
Where do the lines and intersect?
Finding the intersection of two lines is the same as solving simultaneous equations. Here, both equations are already solved for , so the right sides of both equations are set equal to each other. Solving for results in a value of 11. Setting equal to 11 in either of the original equations gives a value of 27.
Example Question #25 : Systems Of Equations
At a carnival, hamburgers cost $4 while hot dogs cost $2. Becky has to buy 18 items for her students. She spent a total of $48. How many hamburgers did she buy?
6
10
12
8
6
Let x equal the number of hamburgers and y equal the number of hotdogs.
Solve for y in the first equation.
Substitute that solution into the second equation.
Example Question #2011 : Sat Mathematics
This year, Amy is 3 times older than Jackie. In 6 years, Amy will be 2 times older than Jackie. How old is Jackie today?
6
12
18
10
6
Let Amy's current age be equal to A and Jackie's age be equal to J.
Therefore, and
Substitute the first equation into the second.
Therefore, today Jackie is 6 years old.
Example Question #24 : How To Find The Solution For A System Of Equations
Bobbie's Boots makes winter boots. Their monthly fixed expenses are $600. The cost for making a pair of boots is $35. The boots sell for $75 a pair.
What is the monthly break-even point?
The break-even point is where the costs equal the revenue.
Costs:
Revenue:
So Costs = Revenue or
Solving for shows the break-even point is achieved when 15 pairs of boots are sold in a month.
Example Question #26 : Systems Of Equations
Bobbie's Boots makes winter boots. Their monthly fixed expenses are $600. The cost for making a pair of boots is $35. The boots sell for $75 a pair.
To make a profit of $200, how many pairs of boots must be sold?
Profits = Revenue - Costs
Revenue:
Costs:
So
Solving:
for means that 20 pairs of boots must be sold to make $200 profit.
Example Question #234 : New Sat
Solve the following system of equations:
What is the sum of and ?
This problem can be solved by using substitution. Write the first equation in terms of and substitute it into the second equation.
So and thus and solving for and then .
So the sum of and is 7.
Example Question #32 : Systems Of Equations
Find .
We have 3 unkown variables and only 2 equations. Instead of trying to solve for or , notice that we can substitute 2 in for the entire expression :
Substitution gives:
Subtract 8 from both sides:
Divide by 3:
Example Question #241 : Algebra
An amusement park charges both an entrance fee, and a fee for every ride. This fee is the same for all rides. Lisa went on 6 rides and paid 120 dollars. Tom went on only 4 rides and paid 95 dollars. What was the entrance fee?
We need 2 equations, because we have 2 unkown variables. Let = the entrance fee, and = the fee per ride. One ride costs dollars. We know that Lisa spent 120 dollars in total. Since Lisa went on 6 rides, she spent dollars on rides. Her only other expense was the entrance fee, :
Apply similar logic to Tom:
Subtracting the second equation from the first equation results in:
Divide both sides by 2:
So every ride costs 12.5 dollars. Plugging 12.5 back into one of the original equations allows us to solve for the entrance fee:
Subtract 50 from both sides:
Example Question #242 : Algebra
Solve the system of equations.
For this system, it will be easiest to solve by substitution. The variable is already isolated in the second equation. We can replace in the first equation with , since these two values are equal.
Now we can solve for .
Now that we know the value of , we can solve for by using our original second equation.
The final answer will be the ordered pair .