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SAT II Math II : Geometry

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Example Questions

Example Question #2 : Volume

A water tank takes the shape of a closed rectangular prism whose exterior has height 30 feet, length 20 feet, and width 15 feet. Its walls are one foot thick throughout. How many cubic feet of water does the tank hold?

Possible Answers:

$10,416\textup{ ft}^{3}$

$7,714\textup{ ft}^{3}$

$2,204\textup{ ft}^{3}$

$6,552\textup{ ft}^{3}$

$2,446\textup{ ft}^{3}$

Correct answer:

$6,552\textup{ ft}^{3}$

Explanation:

The height, length, and width of the interior tank are each two feet less than the corresponding dimension of the exterior of the tank, so the dimensions of the interior are 28, 18, and 13 feet. Multiply these to get the volume:

$V = 28 \cdot 18 \cdot 13 = 6,552$ cubic feet.

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Example Question #1 : 3 Dimensional Geometry

A circular swimming pool has diameter 40 meters and depth meters throughout. Which of the following expressions gives the amount of water it holds, in cubic meters?

Possible Answers:

$160 \pi t$

$40 \pi t$

$1,600 \pi t$

$400 \pi t$

$80 \pi t$

Correct answer:

$400 \pi t$

Explanation:

The pool can be seen as a cylinder with depth (or height) h= t , and a base with diameter 40 m - and radius half this, or r= 20 . The capacity of the pool is the volume of this cylinder, which is

$V = \pi r^{2}h = \pi \cdot 20^{2}\cdot t = 400 \pi t$

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Example Question #1 : Volume

One cubic meter is equal to one thousand liters.

A rectangular swimming pool is meters deep throughout and meters wide. Its length is ten meters greater than twice its width. How many liters of water does the pool hold?

Possible Answers:

None of the other responses is correct.

$2,000 DW^{2} + 10,000 DW$

$0.002 DW^{2} - 0.01 DW$

$0.002 DW^{2} + 0.01 DW$

$2,000 DW^{2} -10,000 DW$

Correct answer:

$2,000 DW^{2} + 10,000 DW$

Explanation:

Since the length of the pool is ten meters longer than twice its width , its length is 2W + 10 .

The inside of the pool can be seen as a rectangular prism, and as such, its volume in cubic feet can be calculated as the product of its length, width, and height (or depth). This product is

$V = D \cdot (2W + 10) \cdot W$

$V = 2DW^{2} + 10DW$

Multiply this by the conversion factor 1,000, and its volume in liters is

$V =1,000 \left ( 2DW^{2} + 10DW \right )$

$V = 2,000 DW^{2} + 10,000 DW$

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Example Question #1 : 3 Dimensional Geometry

A circular swimming pool has diameter 80 feet and depth five feet throughout. To the nearest thousand, how many gallons of water does it hold?

Use the conversion factor: One cubic foot = 7.5 gallons.

Possible Answers:

$3,000\textrm{ gal}$

$94,000\textrm{ gal}$

$754,000\textrm{ gal}$

$5,000\textrm{ gal}$

$188,000\textrm{ gal}$

Correct answer:

$188,000\textrm{ gal}$

Explanation:

The pool can be seen as a cylinder with depth (or height) 5 feet, and a base with diameter 80 feet - and radius half this, or 40 feet. The capacity of the pool is the volume of this cylinder, which is

$V = \pi r ^{2} h \approx 3.14 \times 40^{2} \times 5 \approx 25,120$ cubic feet.

One cubic foot is equal to 7.5 gallons, so multiply:

$25,120 \times 7.5 = 188,400$ gallons

This rounds to 188,000 gallons.

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Example Question #1 : Volume

Pool

The above depicts a rectangular swimming pool for an apartment.

On the left and right edges, the pool is three feet deep; the dashed line at the very center represents the line along which it is eight feet deep. Going from the left to the center, its depth increases uniformly; going from the center to the right, its depth decreases uniformly.

In cubic feet, how much water does the pool hold?

Possible Answers:

$1,870 \textrm{ ft}^{3}$

$9,625 \textrm{ ft}^{3}$

$2,070 \textrm{ ft}^{3}$

$10,225 \textrm{ ft}^{3}$

$9,875 \textrm{ ft}^{3}$

Correct answer:

$9,625 \textrm{ ft}^{3}$

Explanation:

The pool can be looked at as a pentagonal prism with "height" 35 feet and its bases the following shape (depth exaggerated):

Pool

This is a composite of two trapezoids, each with bases 3 feet and 8 feet and height 25 feet; the area of each is

$A = \frac{1}{2} (3+8) \cdot 25 = 137.5$ square feet.

The area of the base is twice this, or

$B = 137.5 \cdot 2 = 275$ square feet.

The volume of a prism is its height times the area of its base, or

$V = 275 \cdot 35 = 9,625$ cubic feet, the capacity of the pool.

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Example Question #1 : Volume

The bottom surface of a rectangular prism has area 100; the right surface has area 200; the rear surface has area 300. Give the volume of the prism (nearest whole unit), if applicable.

Possible Answers:

1,000

6,000

4,243

3,464

2,449

Correct answer:

2,449

Explanation:

Let the dimensions of the prism be , , and .

Then, LW = 100 , LH = 200 , and WH = 300 .

From the first and last equations, dividing both sides, we get

WH = 300

LW = 100

$\frac{WH}{LW} = \frac{300}{100}$

$\frac{H}{L} = 3$

Along with the second equation, multiply both sides:

LH = 200

$\frac{H}{L} \cdot LH = 3 \cdot 200$

$H ^{2}= 600$

Taking the square root of both sides and simplifying, we get

$H = \sqrt{600} = \sqrt{100} \cdot \sqrt{6} = 10 \sqrt{6}$

Now, substituting and solving for the other two dimensions:

LH = 200

$L \cdot 10 \sqrt{6} = 200$

$L = \frac{200}{10 \sqrt{6}} = \frac{20}{\sqrt{6}}$

WH = 300

$W \cdot 10 \sqrt{6} = 300$

$W = \frac{300}{10 \sqrt{6}} = \frac{30 }{\sqrt{6}}$

Now, multiply the three dimensions to obtain the volume:

V= LWH

$= \frac{20}{\sqrt{6}} \cdot 10 \sqrt{6} \cdot \frac{30 }{\sqrt{6}}$

$= \frac{20}{\sqrt{6}} \cdot\frac{ 10 \sqrt{6}}{1} \cdot \frac{30 }{\sqrt{6}}$

$= \frac{ 6,000 \sqrt{6}} {6}$

$= 1,000 \sqrt{6}$

$\approx 1,000 \cdot 2.449$

$\approx 2,449$

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Example Question #1 : 3 Dimensional Geometry

The width of a box is two-thirds its height and three-fifths its length. The volume of the box is 6 cubic meters. To the nearest centimeter, give the width of the box.

Possible Answers:

$164 \textrm{ cm}$

$223 \textrm{ cm}$

$246 \textrm{ cm}$

$201 \textrm{ cm}$

$134 \textrm{ cm}$

Correct answer:

$134 \textrm{ cm}$

Explanation:

Call , , and the length, width, and height of the crate.

The width is two-thirds the height, so

$W = \frac{2}{3} H$ .

Equivalently,

$\frac{3} {2} \cdot \frac{2}{3} H = \frac{3} {2} W$

$H = \frac{3} {2} W$

The width is three-fifths the length, so

$W = \frac{3}{5} L$ .

Equivalently,

$\frac{5} {3} \cdot \frac{3}{5} L = \frac{5} {3} \cdot W$

$L = \frac{5} {3 } W$

The dimensions of the crate in terms of are , $\frac{3} {2} W$ , and $\frac{5} {3 } W$ . The volume is their product:

V= LWH ,

Substitute:

LWH = V

$\frac{5} {3 } W \cdot W \cdot \frac{3} {2} W = V$

$\frac{5} {3 } \cdot \frac{3} {2} \cdot W \cdot W \cdot W = 6$

$\frac{5} {2} \cdot W ^{3}= 6$

$\frac{2} {5} \cdot \frac{5} {2} \cdot W ^{3}= \frac{2} {5} \cdot 6$

$W ^{3}= \frac{12} {5}$

Taking the cube root of both sides:

$W =\sqrt[3]{ \frac{12} {5}}$

$W \approx 1.339$ meters.

Since one meter comprises 100 centimeters, multiply by 100 to convert to centimeters:

$1.339 \cdot 100 = 133.9$ centimeters,

which rounds to 134 centimeters.

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Example Question #1 : Volume

Box 2

The shaded face of the rectangular prism in the above diagram is a square. The volume of the prism is ; give the value of in terms of .

Possible Answers:

$x =\frac{ \sqrt{V}}{25}$

$x =\frac{ \sqrt{V}}{5}$

$x =\frac{ \sqrt{V}}{625}$

$x =\frac{ V}{25}$

$x =\frac{ V}{625}$

Correct answer:

$x =\frac{ \sqrt{V}}{5}$

Explanation:

The volume of a rectangular prism is the product of its length, its width, and its height; that is,

LWH = V

Since the shaded face of the prism is a square, we can set L = H = x , and W = 25 ; substituting and solving for :

$x \cdot 25 \cdot x = V$

$25x^{2} = V$

$\frac{25x^{2}}{25} = \frac{V}{25}$

$x^{2} = \frac{V}{25}$

Taking the positive square root of both sides, and simplifying the expression on the right using the Quotient of Radicals Rule:

$x =\sqrt{ \frac{V}{25}} = \frac{\sqrt{V}}{\sqrt{25}} = \frac{\sqrt{V}}{5}$

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Example Question #11 : 3 Dimensional Geometry

Find the volume of a sphere with a diameter of 10.

Possible Answers:

$100\pi$

$25\pi$

$1333.33\pi$

$166.67\pi$

$33.33\pi$

Correct answer:

$166.67\pi$

Explanation:

The surface area of a sphere is found using the formula $A=\frac{4}{3}\pi r^3$ . We are given the diameter of the circle and so we have to use it to find the radius (r).

$Radius=\frac{Diameter}{2}=\frac{10}{2}=5$

Plug r into the formula to find the surface area

$A=\frac{4}{3}\pi 5^3=\frac{4}{3}\pi 125=166.67\pi$

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Example Question #86 : Geometry

Determine the volume of the cube with a side length of 3x^2 .

Possible Answers:

9x^6

27x^8

3x^8

27x^6

3x^6

Correct answer:

27x^6

Explanation:

Write the formula for the volume of a cube.

V = s^3

Substitute the length into the formula.

V = (3x^2)^3=(3x^2)(3x^2)(3x^2) = 27x^6

The volume is: 27x^6

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SAT II Math II : Geometry

Study concepts, example questions & explanations for SAT II Math II

All SAT II Math II Resources

Example Questions

Example Question #2 : Volume

Example Question #1 : 3 Dimensional Geometry

Example Question #1 : Volume

Example Question #1 : 3 Dimensional Geometry

Example Question #1 : Volume

Example Question #1 : Volume

Example Question #1 : 3 Dimensional Geometry

Example Question #1 : Volume

Example Question #11 : 3 Dimensional Geometry

Example Question #86 : Geometry

All SAT II Math II Resources

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