All SAT II Math II Resources
Example Questions
Example Question #41 : Sat Subject Test In Math Ii
Give the set of real solutions to the equation
(round to the nearest hundredth, if applicable)
The equation has no solution.
Using the Product of Powers Rule, then the Power of a Power Rule, rewrite the first two terms strategically:
Substitute for ; the equation becomes
Factor this as
by finding two integers whose product is 3 and whose sum is . Through some trial and error we find , so we can write
By the Zero Product Rule, one of these two factors must be equal to 0.
If , then .
Substituting back for :
.
If , then .
Substituting back for :
Both can be confirmed to be solutions by substitution.
Example Question #41 : Sat Subject Test In Math Ii
Give the solution set:
The equation has no solution.
Rewrite by taking advantage of the Product of Powers Property and the Power of a Power Property:
Substitute for ; the resulting equation is the quadratic equation
which can be written in standard form by subtracting from both sides:
The trinomial can be factored by the method, Look for two integers with sum and product ; by trial and error, we find they are , so the equation can be rewritten and solved by grouping:
By the Zero Product Property, one of these factors must be equal to 0.
Either
Substituting back for :
Or:
Substituting back for :
The solution set, as can be confirmed by substituting in the equation, is .
Example Question #11 : Exponents And Logarithms
Solve for :
and , so,
can be rewritten as
Applying the Power of a Power Rule,
Example Question #22 : Mathematical Relationships
Solve the equation:
Rewrite the base of the right side.
Simplify the right side.
Add 6 on both sides.
Divide by 6 on both sides.
The answer is:
Example Question #23 : Mathematical Relationships
Solve:
Change the base of the left side to base two.
The equation becomes:
Set the exponents equal since they have similar bases.
Divide by 2 on both sides.
The answer is:
Example Question #51 : Sat Subject Test In Math Ii
Simplify:
Start by distributing the exponent in both the numerator and the denominator. Recall that when an exponent is raised to the exponent, you will need to multiply the two numbers together.
Next, recall that when you have numbers with different exponents, but the same base, subtract the exponent found in the denominator from the exponent in the numerator.
Recall that you can flip the fraction to make the exponents positive.
Example Question #52 : Sat Subject Test In Math Ii
Solve .
The first thing we need to do is find a common base. This can be tricky to do, but guessing and checking a little shows that:
Plugging that back in to the original equation:
Now that our bases are the same, we can cancel them:
From here, it's much easier to solve using simple algebra:
Example Question #53 : Sat Subject Test In Math Ii
Solve .
First, we gather all the constants on one side of the equation:
Next, we rewrite the equation in exponential form:
Now we can simplify the exponent:
And finally, divide:
Example Question #54 : Sat Subject Test In Math Ii
Solve .
Start by combining log terms. Remember, if you subtract logs, you divide the terms inside them:
Now we can rewrite the equation in exponential form:
Finally, we need to get the variable in the numerator, and then alone:
Example Question #55 : Sat Subject Test In Math Ii
Solve .
First, we combine log terms by subtracting them. Remember, when you subtract logs, you divide the terms inside them:
Now, because the bases of the logs match on either side of the equation, we can cancel them out:
From here, we use simple algebra to solve:
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