All SAT II Math I Resources
Example Questions
Example Question #2 : Trigonometry
Solve for between .
First we must solve for when sin is equal to 1/2. That is at
Now, plug it in:
Example Question #3 : Trigonometry
Solve for between .
First we must solve for when sin is equal to 1/2. That is at
Now, plug it in:
Example Question #2 : Trigonometry
In a triangle, , what is the measure of angle A if the side opposite of angle A is 3 and the adjacent side to angle A is 4?
(Round answer to the nearest tenth of a degree.)
To find the measure of angle of A we will use tangent to solve for A. We know that
In our case opposite = 3 and adjacent = 4, we substitute these values in and get:
Now we take the inverse tangent of each side to find the degree value of A.
Example Question #3 : Understanding Sine, Cosine, And Tangent
If , what is if is between and ?
Recall that .
Therefore, we are looking for or .
Now, this has a reference angle of , but it is in the third quadrant. This means that the value will be negative. The value of is . However, given the quadrant of our angle, it will be .
Example Question #1 : Sine, Cosine, Tangent
Determine the exact value of .
The exact value of is the x-value when the angle is 45 degrees on the unit circle.
The x-value of this angle is .
Example Question #2 : Sine, Cosine, Tangent
Which of the following is equal to cos(x)?
Remember SOH-CAH-TOA! That means:
sin(y) is equal to cos(x)
Example Question #2 : Sin, Cos, Tan
Find the value of .
To find the value of , solve each term separately.
Sum the two terms.
Example Question #4 : Sin, Cos, Tan
Calculate .
The tangent function has a period of units. That is,
for all .
Since , we can rewrite the original expression as follows:
Hence,
Example Question #3 : Sin, Cos, Tan
Calculate .
First, convert the given angle measure from radians to degrees:
Next, recall that lies in the fourth quadrant of the unit circle, wherein the cosine is positive. Furthermore, the reference angle of is
Hence, all that is required is to recognize from these observations that
,
which is .
Therefore,
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