Haploid cells contain only one of each numbered chromosome, whereas diploid cells contain two of each. Therefore, a haploid cell in a given organism would contain half as many chromosomes as would be in a diploid cell of the same organism.

In DNA, the four nucleic acid basis are adenine, guanine, cytosine, and thymine. RNA has uracil instead of thymine. Adenine pairs with thymine in DNA and uracil in RNA. Cytosine and Guanine pair together in both. Deoxyribose and ribose are the 5-carbon sugars in DNA and RNA nucleotides, respectively. 

Haploid cells contain one of each numbered chromosome, for a chromosome number of "n." Diploid cells contain two of each, so the number of chromosomes in a diploid cell is 2n, or twice the haploid number.

The correct answer is the "S," or synthesis, phase. The cell cycle consists of six main parts: interphase, prophase, metaphase, anaphase, telophase, and cytokinesis. Interphase, the longest part of the cell cycle, is subdivided into three different phases: G1, S, and G2. G1 comes first; in this phase, the cell simply grows. In the S phase, the cell synthesizes (creates) a new set of DNA using its original genome as a template. In G2, the cell (which now contains two copies of DNA) continues to grow. These growth phases are an important part of interphase because the cell must grow enough to have enough cytoplasm to give to each of its daughter cells at the end of mitosis or meiosis.

A phenotype is a physical trait that can be observed. Thus, eye color (and hair color) are great examples of phenotypes. A genotype describes the genetic traits of a person (e.g. whether that person has the autosomal or recessive alleles of a gene). The genotype of an individual determines his or her phenotype.

The easiest way to solve this problem is to draw a punnet square. The genotypes of the parents are "AO" and "AB". The potential genotypes of their children are "AA", "AO", "BA", and "BO". Children with genotypes "AA" and "AO" will have type A blood. Children with genotype "BO" will have type B blood. Children with genotype "BA" will have type AB blood. Genotype "O/O" is the only one that will result in type O blood. "O/O" is not a possible product of this punnet square. Both the mother and the father must have the "O" allele in order for a child to have genotype "O/O" and type O blood.

This question is essentially asking, "Which of the following is a point mutation of the original sequence?" A point mutation is a mutation in which one base pair of DNA is substituted for another. A point mutation will not change the reading frame of a DNA sequence because it does not involve adding or removing any bases. The only answer choice that is identical to the original sequence with the exception of one base pair being changed for another is 5'GATCACG3', so this is the correct answer.

In RNA, the nucleic acid base adenine pairs with uracil. (In DNA, it pairs with thymine). In both RNA and DNA, cytosine pairs with guanine. Accordingly, RNA will have the same percent uracil as it does adenine—in this case, .  

(In this case it will also contain  guanine and  percent cytosine, because the adenine and uracil together add up to  and the remaining  is divided evenly between the paired guanine and cytosine (and  divided by two is ).

Gametes are germ cells used in sexual reproduction, such as eggs or sperm. They are haploid cells with a chromosome number of , while somatic (non-reproductive) cells are diploid with a chromosome number of . So, if an organism's gametes have  chromosomes each, a somatic cell in that organism will have twice that number of chromosomes—in this case, .

If other dingos are supplementing the population, we know that migration is occurring. Migration cannot occur if a population is to satisfy the conditions of Hardy-Weinberg equilibrium.