Organic Chemistry : Help with Organic Carbohydrates

Study concepts, example questions & explanations for Organic Chemistry

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Example Questions

Example Question #11 : Help With Organic Carbohydrates

Which of the following correctly describes a reducing sugar?

Possible Answers:

None of these

A reducing sugar has an acetal/ketal group when in its cyclic form, and is able to oxidize other chemicals (while itself being reduced).

A reducing sugar has a hemiacetal/hemiketal group when in its cyclic form, and is able to reduce other chemicals (while itself being oxidized).

A reducing sugar has a hemiacetal/hemiketal group when in its cyclic form, and is able to oxidize other chemicals (while itself being reduced).

A reducing sugar has an acetal/ketal group when in its cyclic form, and is able to reduce other chemicals (while itself being oxidized).

Correct answer:

A reducing sugar has a hemiacetal/hemiketal group when in its cyclic form, and is able to reduce other chemicals (while itself being oxidized).

Explanation:

A reducing sugar contains a hemiacetal/hemiketal group which means that in its open chain form it contains a ketone/aldehyde group. Sugars containing a free aldehyde group can be oxidized to a carboxylic acid, while sugars containing a free ketone group must be tautomerized to an aldehyde group through an ene-diol intermediate (shown below), and this can be oxidized to a carboxylic acid.

 Screen shot 2015 11 18 at 9.13.46 pm

Reducing sugars are detectable with the formation of either a precipitate or a solution color change after addition of Tollens' Reagent, Benedict's solution, or Fehling's solution. 

Example Question #11 : Help With Organic Carbohydrates

Alpha-D-glucopyranose:

Screen shot 2015 11 21 at 4.32.55 pm

Glucose (pictured) is defined as which of the following?

Possible Answers:

Triose phosphate

Aldopentose

Ketohexose

Aldohexose

Ketopentose

Correct answer:

Aldohexose

Explanation:

Glucose in its open chain form (shown below), has a free aldehyde group (an aldose), and it contains six carbons (a hexose). Together, glucose is shown to be an aldohexose.

Screen shot 2015 11 21 at 4.46.41 pm

Example Question #12 : Help With Organic Carbohydrates

Alpha-D-glucopyranose

Screen shot 2015 11 21 at 4.44.17 pm

Which of the labelled carbon atoms is the anomeric carbon?

Possible Answers:

C

A

B

D

E

Correct answer:

A

Explanation:

The anomeric carbon is formed from the original carbonyl carbon in the straight-chain form of the molecule being attacked by a hydroxyl group to form a hemiacetal. This is seen as a carbon that is bonded to two oxygen atoms. In the case of glucose, the carbon labelled A is a hemiacetal, and is considered to be the anomeric carbon.

Example Question #13 : Help With Organic Carbohydrates

Shown below is the structure of a sugar molecule.

Sugar

Which of the following is the most appropriate classification of this sugar?

Possible Answers:

Ketoheptose

Aldoheptose

Aldohexose

Ketohexose

Correct answer:

Aldoheptose

Explanation:

In this question, we're given the structure of a sugar molecule, and we're asked to identify which answer choice represents the correct identification of this molecule.

To answer this question, there are two things we need to look at. For one, we need to determine whether it is an aldehyde sugar (aldose) or a ketone sugar (ketose). The first carbon atom in the molecule (shown at the very top in the image) is shown as . This means that the carbon contains a double bond to the oxygen. Furthermore, since it also contains a bond to a hydrogen, we can conclude that this is an aldehyde functional group. Consequently, we know that this must be an aldose sugar.

Next, we need to look at the number of carbon atoms in the molecule. In the image shown in the question, there are a total of seven carbon atoms. Thus, this sugar would be classified as a heptose sugar (seven carbons) rather than a hexose sugar (six carbons).

Putting these two pieces of information together, we know that the sugar is both an aldose and a heptose. Therefore, this sugar is an aldoheptose.

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